我扩展了Carlos LM的解决方案，使其更加详细。

一个模式的例子:

var schema = {
    _id: 123,
    id: 12,
    t: 'title',
    p: 4.5,
    ls: [{
            l: 'lemma',
            p: {
                pp: 8.9
            }
        },
         {
            l: 'lemma2',
            p: {
               pp: 8.3
           }
        }
    ]
};

在控制台输入:

var schemafy = function(schema, i, limit) {
    var i = (typeof i !== 'undefined') ? i : 1;
    var limit = (typeof limit !== 'undefined') ? limit : false;
    var type = '';
    var array = false;

    for (key in schema) {
        type = typeof schema[key];
        array = (schema[key] instanceof Array) ? true : false;

        if (type === 'object') {
            print(Array(i).join('    ') + key+' <'+((array) ? 'array' : type)+'>:');
            schemafy(schema[key], i+1, array);
        } else {
            print(Array(i).join('    ') + key+' <'+type+'>');
        }

        if (limit) {
            break;
        }
    }
}

Run:

schemafy(db.collection.findOne());

输出

_id <number>
id <number>
t <string>
p <number>
ls <object>:
    0 <object>:
    l <string>
    p <object>:
        pp <number> 

我知道这个问题已经10年了，但是c#没有解决方案，我花了好几个小时才弄清楚。我正在使用。net驱动程序和系统。Linq返回键的列表。

var map = new BsonJavaScript("function() { for (var key in this) { emit(key, null); } }");
var reduce = new BsonJavaScript("function(key, stuff) { return null; }");
var options = new MapReduceOptions<BsonDocument, BsonDocument>();
var result = await collection.MapReduceAsync(map, reduce, options);
var list = result.ToEnumerable().Select(item => item["_id"].ToString());

这一行将集合中的所有键提取到一个逗号分隔的排序字符串中:

db.<collection>.find().map((x) => Object.keys(x)).reduce((a, e) => {for (el of e) { if(!a.includes(el)) { a.push(el) }  }; return a}, []).sort((a, b) => a.toLowerCase() > b.toLowerCase()).join(", ")

这个查询的结果通常是这样的:

_class, _id, address, city, companyName, country, emailId, firstName, isAssigned, isLoggedIn, lastLoggedIn, lastName, location, mobile, printName, roleName, route, state, status, token

基于@Wolkenarchitekt的回答:https://stackoverflow.com/a/48117846/8808983，我写了一个脚本，可以在db中找到所有键的模式，我认为它可以帮助其他人阅读这个线程:

"""
Python 3
This script get list of patterns and print the collections that contains fields with this patterns.
"""

import argparse

import pymongo
from bson import Code


# initialize mongo connection:
def get_db():
    client = pymongo.MongoClient("172.17.0.2")
    db = client["Data"]
    return db


def get_commandline_options():
    description = "To run use: python db_fields_pattern_finder.py -p <list_of_patterns>"
    parser = argparse.ArgumentParser(description=description)
    parser.add_argument('-p', '--patterns', nargs="+", help='List of patterns to look for in the db.', required=True)
    return parser.parse_args()


def report_matching_fields(relevant_fields_by_collection):
    print("Matches:")

    for collection_name in relevant_fields_by_collection:
        if relevant_fields_by_collection[collection_name]:
            print(f"{collection_name}: {relevant_fields_by_collection[collection_name]}")

    # pprint(relevant_fields_by_collection)


def get_collections_names(db):
    """
    :param pymongo.database.Database db:
    :return list: collections names
    """
    return db.list_collection_names()


def get_keys(db, collection):
    """
    See: https://stackoverflow.com/a/48117846/8808983
    :param db:
    :param collection:
    :return:
    """
    map = Code("function() { for (var key in this) { emit(key, null); } }")
    reduce = Code("function(key, stuff) { return null; }")
    result = db[collection].map_reduce(map, reduce, "myresults")
    return result.distinct('_id')


def get_fields(db, collection_names):
    fields_by_collections = {}
    for collection_name in collection_names:
        fields_by_collections[collection_name] = get_keys(db, collection_name)
    return fields_by_collections


def get_matches_fields(fields_by_collections, patterns):
    relevant_fields_by_collection = {}
    for collection_name in fields_by_collections:
        relevant_fields = [field for field in fields_by_collections[collection_name] if
                           [pattern for pattern in patterns if
                            pattern in field]]
        relevant_fields_by_collection[collection_name] = relevant_fields

    return relevant_fields_by_collection


def main(patterns):
    """
    :param list patterns: List of strings to look for in the db.
    """
    db = get_db()

    collection_names = get_collections_names(db)
    fields_by_collections = get_fields(db, collection_names)
    relevant_fields_by_collection = get_matches_fields(fields_by_collections, patterns)

    report_matching_fields(relevant_fields_by_collection)


if __name__ == '__main__':
    args = get_commandline_options()
    main(args.patterns)

以Kristina的回答为灵感，我创建了一个名为Variety的开源工具，它的功能就是:https://github.com/variety/variety

下面是用Python编写的示例: 这个示例内联返回结果。

from pymongo import MongoClient
from bson.code import Code

mapper = Code("""
    function() {
                  for (var key in this) { emit(key, null); }
               }
""")
reducer = Code("""
    function(key, stuff) { return null; }
""")

distinctThingFields = db.things.map_reduce(mapper, reducer
    , out = {'inline' : 1}
    , full_response = True)
## do something with distinctThingFields['results']