如何对活动目录验证用户名和密码?我只是想检查用户名和密码是否正确。
当前回答
这里是我完整的认证解决方案,供您参考。
首先,添加以下四个引用
using System.DirectoryServices;
using System.DirectoryServices.Protocols;
using System.DirectoryServices.AccountManagement;
using System.Net;
private void AuthUser() {
try{
string Uid = "USER_NAME";
string Pass = "PASSWORD";
if (Uid == "")
{
MessageBox.Show("Username cannot be null");
}
else if (Pass == "")
{
MessageBox.Show("Password cannot be null");
}
else
{
LdapConnection connection = new LdapConnection("YOUR DOMAIN");
NetworkCredential credential = new NetworkCredential(Uid, Pass);
connection.Credential = credential;
connection.Bind();
// after authenticate Loading user details to data table
PrincipalContext ctx = new PrincipalContext(ContextType.Domain);
UserPrincipal user = UserPrincipal.FindByIdentity(ctx, Uid);
DirectoryEntry up_User = (DirectoryEntry)user.GetUnderlyingObject();
DirectorySearcher deSearch = new DirectorySearcher(up_User);
SearchResultCollection results = deSearch.FindAll();
ResultPropertyCollection rpc = results[0].Properties;
DataTable dt = new DataTable();
DataRow toInsert = dt.NewRow();
dt.Rows.InsertAt(toInsert, 0);
foreach (string rp in rpc.PropertyNames)
{
if (rpc[rp][0].ToString() != "System.Byte[]")
{
dt.Columns.Add(rp.ToString(), typeof(System.String));
foreach (DataRow row in dt.Rows)
{
row[rp.ToString()] = rpc[rp][0].ToString();
}
}
}
//You can load data to grid view and see for reference only
dataGridView1.DataSource = dt;
}
} //Error Handling part
catch (LdapException lexc)
{
String error = lexc.ServerErrorMessage;
string pp = error.Substring(76, 4);
string ppp = pp.Trim();
if ("52e" == ppp)
{
MessageBox.Show("Invalid Username or password, contact ADA Team");
}
if ("775" == ppp)
{
MessageBox.Show("User account locked, contact ADA Team");
}
if ("525" == ppp)
{
MessageBox.Show("User not found, contact ADA Team");
}
if ("530" == ppp)
{
MessageBox.Show("Not permitted to logon at this time, contact ADA Team");
}
if ("531" == ppp)
{
MessageBox.Show("Not permitted to logon at this workstation, contact ADA Team");
}
if ("532" == ppp)
{
MessageBox.Show("Password expired, contact ADA Team");
}
if ("533" == ppp)
{
MessageBox.Show("Account disabled, contact ADA Team");
}
if ("533" == ppp)
{
MessageBox.Show("Account disabled, contact ADA Team");
}
} //common error handling
catch (Exception exc)
{
MessageBox.Show("Invalid Username or password, contact ADA Team");
}
finally {
tbUID.Text = "";
tbPass.Text = "";
}
}
其他回答
使用DirectoryServices非常简单的解决方案:
using System.DirectoryServices;
//srvr = ldap server, e.g. LDAP://domain.com
//usr = user name
//pwd = user password
public bool IsAuthenticated(string srvr, string usr, string pwd)
{
bool authenticated = false;
try
{
DirectoryEntry entry = new DirectoryEntry(srvr, usr, pwd);
object nativeObject = entry.NativeObject;
authenticated = true;
}
catch (DirectoryServicesCOMException cex)
{
//not authenticated; reason why is in cex
}
catch (Exception ex)
{
//not authenticated due to some other exception [this is optional]
}
return authenticated;
}
需要NativeObject访问来检测坏的用户/密码
完整的. net解决方案是使用来自系统的类。DirectoryServices名称空间。它们允许直接查询AD服务器。下面是一个可以做到这一点的小样本:
using (DirectoryEntry entry = new DirectoryEntry())
{
entry.Username = "here goes the username you want to validate";
entry.Password = "here goes the password";
DirectorySearcher searcher = new DirectorySearcher(entry);
searcher.Filter = "(objectclass=user)";
try
{
searcher.FindOne();
}
catch (COMException ex)
{
if (ex.ErrorCode == -2147023570)
{
// Login or password is incorrect
}
}
}
// FindOne() didn't throw, the credentials are correct
这段代码使用提供的凭据直接连接到AD服务器。如果凭证无效,则search . findone()将抛出异常。ErrorCode是一个对应于“无效的用户名/密码”COM错误。
您不需要以AD用户的身份运行代码。事实上,我成功地使用它在AD服务器上查询信息,从域外的客户端!
如果你被。net 2.0和托管代码困住了,这里有另一种处理本地和域帐户的方法:
using System;
using System.Collections.Generic;
using System.Text;
using System.Security;
using System.Diagnostics;
static public bool Validate(string domain, string username, string password)
{
try
{
Process proc = new Process();
proc.StartInfo = new ProcessStartInfo()
{
FileName = "no_matter.xyz",
CreateNoWindow = true,
WindowStyle = ProcessWindowStyle.Hidden,
WorkingDirectory = Environment.GetFolderPath(Environment.SpecialFolder.CommonApplicationData),
UseShellExecute = false,
RedirectStandardError = true,
RedirectStandardOutput = true,
RedirectStandardInput = true,
LoadUserProfile = true,
Domain = String.IsNullOrEmpty(domain) ? "" : domain,
UserName = username,
Password = Credentials.ToSecureString(password)
};
proc.Start();
proc.WaitForExit();
}
catch (System.ComponentModel.Win32Exception ex)
{
switch (ex.NativeErrorCode)
{
case 1326: return false;
case 2: return true;
default: throw ex;
}
}
catch (Exception ex)
{
throw ex;
}
return false;
}
不幸的是,没有“简单”的方法来检查AD上的用户凭据。
使用到目前为止所介绍的每一种方法,你可能会得到一个假阴性:用户的信用将是有效的,但AD在某些情况下将返回false:
用户需要在下次登录时更改密码。 用户密码已过期。
ActiveDirectory不允许您使用LDAP来确定密码是否由于用户必须更改密码或密码是否过期而无效。
要确定密码更改或密码过期,您可以调用Win32:LogonUser(),并检查以下2个常量的windows错误码:
Error_password_must_change = 1907 Error_password_expired = 1330
对我来说,这两个下面的工作,确保你的域名是LDAP://在开始
//"LDAP://" + domainName
private void btnValidate_Click(object sender, RoutedEventArgs e)
{
try
{
DirectoryEntry de = new DirectoryEntry(txtDomainName.Text, txtUsername.Text, txtPassword.Text);
DirectorySearcher dsearch = new DirectorySearcher(de);
SearchResult results = null;
results = dsearch.FindOne();
MessageBox.Show("Validation Success.");
}
catch (LdapException ex)
{
MessageBox.Show($"Validation Failure. {ex.GetBaseException().Message}");
}
catch (Exception ex)
{
MessageBox.Show($"Validation Failure. {ex.GetBaseException().Message}");
}
}
private void btnValidate2_Click(object sender, RoutedEventArgs e)
{
try
{
LdapConnection lcon = new LdapConnection(new LdapDirectoryIdentifier((string)null, false, false));
NetworkCredential nc = new NetworkCredential(txtUsername.Text,
txtPassword.Text, txtDomainName.Text);
lcon.Credential = nc;
lcon.AuthType = AuthType.Negotiate;
lcon.Bind(nc);
MessageBox.Show("Validation Success.");
}
catch (LdapException ex)
{
MessageBox.Show($"Validation Failure. {ex.GetBaseException().Message}");
}
catch (Exception ex)
{
MessageBox.Show($"Validation Failure. {ex.GetBaseException().Message}");
}
}