如何对活动目录验证用户名和密码?我只是想检查用户名和密码是否正确。


当前回答

我使用这个过程作为DLL登录到我们开发的其他应用程序… (我们目前正在使用OpenEdge Progress)

public static string AzureLogin(string user, string password) {

    string status;

    try {
        new DirectorySearcher(new DirectoryEntry("LDAP://yourdomain.com", user, password) {
            AuthenticationType = AuthenticationTypes.Secure,
            Username = user,
            Password = password
        })  {
            Filter = "(objectclass=user)"
        }.FindOne().Properties["displayname"][0].ToString();

        status = $"SUCCESS - User {user} has logged in.";

    } catch(System.Exception e) {
        status = $"ERROR - While logging in: {e}";
    }

    return status;
}

其他回答

如果你被。net 2.0和托管代码困住了,这里有另一种处理本地和域帐户的方法:

using System;
using System.Collections.Generic;
using System.Text;
using System.Security;
using System.Diagnostics;

static public bool Validate(string domain, string username, string password)
{
    try
    {
        Process proc = new Process();
        proc.StartInfo = new ProcessStartInfo()
        {
            FileName = "no_matter.xyz",
            CreateNoWindow = true,
            WindowStyle = ProcessWindowStyle.Hidden,
            WorkingDirectory = Environment.GetFolderPath(Environment.SpecialFolder.CommonApplicationData),
            UseShellExecute = false,
            RedirectStandardError = true,
            RedirectStandardOutput = true,
            RedirectStandardInput = true,
            LoadUserProfile = true,
            Domain = String.IsNullOrEmpty(domain) ? "" : domain,
            UserName = username,
            Password = Credentials.ToSecureString(password)
        };
        proc.Start();
        proc.WaitForExit();
    }
    catch (System.ComponentModel.Win32Exception ex)
    {
        switch (ex.NativeErrorCode)
        {
            case 1326: return false;
            case 2: return true;
            default: throw ex;
        }
    }
    catch (Exception ex)
    {
        throw ex;
    }

    return false;
}   

Windows身份验证失败的原因有很多:用户名或密码不正确、帐户被锁定、密码过期等等。为了区分这些错误,通过P/Invoke调用LogonUser API函数,如果函数返回false,检查错误代码:

using System;
using System.ComponentModel;
using System.Runtime.InteropServices;

using Microsoft.Win32.SafeHandles;

public static class Win32Authentication
{
    private class SafeTokenHandle : SafeHandleZeroOrMinusOneIsInvalid
    {
        private SafeTokenHandle() // called by P/Invoke
            : base(true)
        {
        }

        protected override bool ReleaseHandle()
        {
            return CloseHandle(this.handle);
        }
    }

    private enum LogonType : uint
    {
        Network = 3, // LOGON32_LOGON_NETWORK
    }

    private enum LogonProvider : uint
    {
        WinNT50 = 3, // LOGON32_PROVIDER_WINNT50
    }

    [DllImport("kernel32.dll", SetLastError = true)]
    private static extern bool CloseHandle(IntPtr handle);

    [DllImport("advapi32.dll", SetLastError = true)]
    private static extern bool LogonUser(
        string userName, string domain, string password,
        LogonType logonType, LogonProvider logonProvider,
        out SafeTokenHandle token);

    public static void AuthenticateUser(string userName, string password)
    {
        string domain = null;
        string[] parts = userName.Split('\\');
        if (parts.Length == 2)
        {
            domain = parts[0];
            userName = parts[1];
        }

        SafeTokenHandle token;
        if (LogonUser(userName, domain, password, LogonType.Network, LogonProvider.WinNT50, out token))
            token.Dispose();
        else
            throw new Win32Exception(); // calls Marshal.GetLastWin32Error()
    }
}

示例用法:

try
{
    Win32Authentication.AuthenticateUser("EXAMPLE\\user", "P@ssw0rd");
    // Or: Win32Authentication.AuthenticateUser("user@example.com", "P@ssw0rd");
}
catch (Win32Exception ex)
{
    switch (ex.NativeErrorCode)
    {
        case 1326: // ERROR_LOGON_FAILURE (incorrect user name or password)
            // ...
        case 1327: // ERROR_ACCOUNT_RESTRICTION
            // ...
        case 1330: // ERROR_PASSWORD_EXPIRED
            // ...
        case 1331: // ERROR_ACCOUNT_DISABLED
            // ...
        case 1907: // ERROR_PASSWORD_MUST_CHANGE
            // ...
        case 1909: // ERROR_ACCOUNT_LOCKED_OUT
            // ...
        default: // Other
            break;
    }
}

注意:LogonUser需要与您验证的域建立信任关系。

完整的. net解决方案是使用来自系统的类。DirectoryServices名称空间。它们允许直接查询AD服务器。下面是一个可以做到这一点的小样本:

using (DirectoryEntry entry = new DirectoryEntry())
{
    entry.Username = "here goes the username you want to validate";
    entry.Password = "here goes the password";

    DirectorySearcher searcher = new DirectorySearcher(entry);

    searcher.Filter = "(objectclass=user)";

    try
    {
        searcher.FindOne();
    }
    catch (COMException ex)
    {
        if (ex.ErrorCode == -2147023570)
        {
            // Login or password is incorrect
        }
    }
}

// FindOne() didn't throw, the credentials are correct

这段代码使用提供的凭据直接连接到AD服务器。如果凭证无效,则search . findone()将抛出异常。ErrorCode是一个对应于“无效的用户名/密码”COM错误。

您不需要以AD用户的身份运行代码。事实上,我成功地使用它在AD服务器上查询信息,从域外的客户端!

我的简单功能

 private bool IsValidActiveDirectoryUser(string activeDirectoryServerDomain, string username, string password)
    {
        try
        {
            DirectoryEntry de = new DirectoryEntry("LDAP://" + activeDirectoryServerDomain, username + "@" + activeDirectoryServerDomain, password, AuthenticationTypes.Secure);
            DirectorySearcher ds = new DirectorySearcher(de);
            ds.FindOne();
            return true;
        }
        catch //(Exception ex)
        {
            return false;
        }
    }

我使用这个过程作为DLL登录到我们开发的其他应用程序… (我们目前正在使用OpenEdge Progress)

public static string AzureLogin(string user, string password) {

    string status;

    try {
        new DirectorySearcher(new DirectoryEntry("LDAP://yourdomain.com", user, password) {
            AuthenticationType = AuthenticationTypes.Secure,
            Username = user,
            Password = password
        })  {
            Filter = "(objectclass=user)"
        }.FindOne().Properties["displayname"][0].ToString();

        status = $"SUCCESS - User {user} has logged in.";

    } catch(System.Exception e) {
        status = $"ERROR - While logging in: {e}";
    }

    return status;
}