日期。解析几乎可以得到你想要的。它在上午/下午部分窒息，但通过一些黑客你可以让它工作:

var str = 'Sun Apr 25, 2010 3:30pm',
    timestamp;

timestamp = Date.parse(str.replace(/[ap]m$/i, ''));

if(str.match(/pm$/i) >= 0) {
    timestamp += 12 * 60 * 60 * 1000;
}

                //little bit of code for Converting dates 

                var dat1 = document.getElementById('inputDate').value;
                var date1 = new Date(dat1)//converts string to date object
                alert(date1);
                var dat2 = document.getElementById('inputFinishDate').value;
                var date2 = new Date(dat2)
                alert(date2);

你可以使用regex解析字符串以详细的时间，然后创建日期或任何返回格式，如:

//example : let dateString = "2018-08-17 01:02:03.4"

function strToDate(dateString){
    let reggie = /(\d{4})-(\d{2})-(\d{2}) (\d{2}):(\d{2}):(\d{2}).(\d{1})/
  , [,year, month, day, hours, minutes, seconds, miliseconds] = reggie.exec(dateString)
  , dateObject = new Date(year, month-1, day, hours, minutes, seconds, miliseconds);
  return dateObject;
}
alert(strToDate(dateString));

只是新日期(st);

假设这是正确的格式。

新的日期(2000,10,1)将给你“星期三11月1日2000 00:00:00 GMT+0100 (CET)”

0表示month，表示1月

如果在转换为Date格式之前需要检查字符串的内容:

// Convert 'M/D/YY' to Date()
mdyToDate = function(mdy) {
  var d = mdy.split(/[\/\-\.]/, 3);

  if (d.length != 3) return null;

  // Check if date is valid
  var mon = parseInt(d[0]), 
      day = parseInt(d[1]),
      year= parseInt(d[2]);
  if (d[2].length == 2) year += 2000;
  if (day <= 31 && mon <= 12 && year >= 2015)
    return new Date(year, mon - 1, day);

  return null; 
}