基本上我需要运行与shell脚本文件位置相关的路径脚本,我如何将当前目录更改为脚本文件所在的相同目录?


当前回答

正如marko所言:

BASEDIR=$(dirname $0)
echo $BASEDIR

除非你在脚本所在的目录中执行脚本,在这种情况下,你会得到一个值'。'

要解决这个问题,请使用:

current_dir=$(pwd)
script_dir=$(dirname $0)

if [ $script_dir = '.' ]
then
script_dir="$current_dir"
fi

现在可以在整个脚本中使用变量current_dir来引用脚本目录。然而,这可能仍然有符号链接的问题。

其他回答

如果您正在使用bash....

#!/bin/bash

pushd $(dirname "${0}") > /dev/null
basedir=$(pwd -L)
# Use "pwd -P" for the path without links. man bash for more info.
popd > /dev/null

echo "${basedir}"

最初的帖子包含了解决方案(忽略回复,他们没有添加任何有用的东西)。有趣的工作是由前面提到的unix命令readlink和选项-f完成的。当以绝对路径和相对路径调用脚本时,此方法有效。

对于bash, sh, ksh:

#!/bin/bash 
# Absolute path to this script, e.g. /home/user/bin/foo.sh
SCRIPT=$(readlink -f "$0")
# Absolute path this script is in, thus /home/user/bin
SCRIPTPATH=$(dirname "$SCRIPT")
echo $SCRIPTPATH

对于tcsh, csh:

#!/bin/tcsh
# Absolute path to this script, e.g. /home/user/bin/foo.csh
set SCRIPT=`readlink -f "$0"`
# Absolute path this script is in, thus /home/user/bin
set SCRIPTPATH=`dirname "$SCRIPT"`
echo $SCRIPTPATH

参见:https://stackoverflow.com/a/246128/59087

基本版:

dir=$(dirname $0)

如果脚本可以通过$PATH调用,那么:

dir=$(dirname $(which $0))

如果脚本可能像这样调用:bash script.sh,那么:

dir=$(dirname $(which $0 2>/dev/null || realpath ./$0))

如果你感到极度不安全,那么:

dir="$(dirname -- "$(which -- "$0" 2>/dev/null || realpath -- "./$0")")"

这应该能奏效:

echo `pwd`/`dirname $0`

它可能看起来很丑,这取决于它是如何被调用和cwd,但应该得到你需要去的地方(或者你可以调整字符串,如果你关心它的外观)。

这个问题的最佳答案是: 从内部获取Bash脚本的源目录

它是:

DIR="$( cd "$( dirname "${BASH_SOURCE[0]}" )" && pwd )"

一行代码,它将提供脚本的完整目录名,无论从哪里调用脚本。

要了解它是如何工作的,你可以执行以下脚本:

#!/bin/bash

SOURCE="${BASH_SOURCE[0]}"
while [ -h "$SOURCE" ]; do # resolve $SOURCE until the file is no longer a symlink
  TARGET="$(readlink "$SOURCE")"
  if [[ $TARGET == /* ]]; then
    echo "SOURCE '$SOURCE' is an absolute symlink to '$TARGET'"
    SOURCE="$TARGET"
  else
    DIR="$( dirname "$SOURCE" )"
    echo "SOURCE '$SOURCE' is a relative symlink to '$TARGET' (relative to '$DIR')"
    SOURCE="$DIR/$TARGET" # if $SOURCE was a relative symlink, we need to resolve it relative to the path where the symlink file was located
  fi
done
echo "SOURCE is '$SOURCE'"
RDIR="$( dirname "$SOURCE" )"
DIR="$( cd -P "$( dirname "$SOURCE" )" && pwd )"
if [ "$DIR" != "$RDIR" ]; then
  echo "DIR '$RDIR' resolves to '$DIR'"
fi
echo "DIR is '$DIR'"