这不是一个很简单的手术吗?但是,我看到既没有size()也没有length()方法。
当前回答
我也有同样的问题。以这种方式使用ResultSet.first()在执行后解决它:
if(rs.first()){
// Do your job
} else {
// No rows take some actions
}
文档(链接):
布尔第一次() 抛出SQLException异常 将光标移动到此ResultSet对象的第一行。 返回: 如果光标位于有效的 行;如果结果集中没有行,则为False 抛出: SQLException—如果发生数据库访问错误;在封闭的结果集或结果集类型为TYPE_FORWARD_ONLY时调用此方法 SQLFeatureNotSupportedException—如果JDBC驱动程序不支持 这个方法 自: 1.2
其他回答
String sql = "select count(*) from message";
ps = cn.prepareStatement(sql);
rs = ps.executeQuery();
int rowCount = 0;
while(rs.next()) {
rowCount = Integer.parseInt(rs.getString("count(*)"));
System.out.println(Integer.parseInt(rs.getString("count(*)")));
}
System.out.println("Count : " + rowCount);
如果你有一个ResultSet类型的ResultSet。TYPE_FORWARD_ONLY您希望保持这种方式(而不是切换到ResultSet)。TYPE_SCROLL_INSENSITIVE或ResultSet。TYPE_SCROLL_INSENSITIVE,以便能够使用.last())。
我建议一种非常有效的破解方法,即在顶部添加第一个包含行数的伪/伪行。
例子
假设您的查询如下
select MYBOOL,MYINT,MYCHAR,MYSMALLINT,MYVARCHAR
from MYTABLE
where ...blahblah...
输出是这样的
true 65537 "Hey" -32768 "The quick brown fox"
false 123456 "Sup" 300 "The lazy dog"
false -123123 "Yo" 0 "Go ahead and jump"
false 3 "EVH" 456 "Might as well jump"
...
[1000 total rows]
简单地重构你的代码,就像这样:
Statement s=myConnection.createStatement(ResultSet.TYPE_FORWARD_ONLY,
ResultSet.CONCUR_READ_ONLY);
String from_where="FROM myTable WHERE ...blahblah... ";
//h4x
ResultSet rs=s.executeQuery("select count(*)as RECORDCOUNT,"
+ "cast(null as boolean)as MYBOOL,"
+ "cast(null as int)as MYINT,"
+ "cast(null as char(1))as MYCHAR,"
+ "cast(null as smallint)as MYSMALLINT,"
+ "cast(null as varchar(1))as MYVARCHAR "
+from_where
+"UNION ALL "//the "ALL" part prevents internal re-sorting to prevent duplicates (and we do not want that)
+"select cast(null as int)as RECORDCOUNT,"
+ "MYBOOL,MYINT,MYCHAR,MYSMALLINT,MYVARCHAR "
+from_where);
您的查询输出将如下所示
1000 null null null null null
null true 65537 "Hey" -32768 "The quick brown fox"
null false 123456 "Sup" 300 "The lazy dog"
null false -123123 "Yo" 0 "Go ahead and jump"
null false 3 "EVH" 456 "Might as well jump"
...
[1001 total rows]
所以你必须
if(rs.next())
System.out.println("Recordcount: "+rs.getInt("RECORDCOUNT"));//hack: first record contains the record count
while(rs.next())
//do your stuff
ResultSet rs = ps.executeQuery();
int rowcount = 0;
if (rs.last()) {
rowcount = rs.getRow();
rs.beforeFirst(); // not rs.first() because the rs.next() below will move on, missing the first element
}
while (rs.next()) {
// do your standard per row stuff
}
为列命名。
String query = "SELECT COUNT(*) as count FROM
引用该列从ResultSet对象到int,并从那里做你的逻辑。
PreparedStatement statement = connection.prepareStatement(query);
statement.setString(1, item.getProductId());
ResultSet resultSet = statement.executeQuery();
while (resultSet.next()) {
int count = resultSet.getInt("count");
if (count >= 1) {
System.out.println("Product ID already exists.");
} else {
System.out.println("New Product ID.");
}
}
SELECT COUNT(*) FROM…查询。
OR
int size =0;
if (rs != null)
{
rs.last(); // moves cursor to the last row
size = rs.getRow(); // get row id
}
在这两种情况下,都不需要遍历整个数据。
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