你可以尝试sframe，它和pandas有相同的语法，但是允许你操作比你的RAM大的文件。

您可以将数据读入为块，并将每个块保存为pickle。

import pandas as pd 
import pickle

in_path = "" #Path where the large file is
out_path = "" #Path to save the pickle files to
chunk_size = 400000 #size of chunks relies on your available memory
separator = "~"

reader = pd.read_csv(in_path,sep=separator,chunksize=chunk_size, 
                    low_memory=False)    


for i, chunk in enumerate(reader):
    out_file = out_path + "/data_{}.pkl".format(i+1)
    with open(out_file, "wb") as f:
        pickle.dump(chunk,f,pickle.HIGHEST_PROTOCOL)

在下一步中，读入pickle并将每个pickle附加到所需的数据框架中。

import glob
pickle_path = "" #Same Path as out_path i.e. where the pickle files are

data_p_files=[]
for name in glob.glob(pickle_path + "/data_*.pkl"):
   data_p_files.append(name)


df = pd.DataFrame([])
for i in range(len(data_p_files)):
    df = df.append(pd.read_pickle(data_p_files[i]),ignore_index=True)

你可以尝试sframe，它和pandas有相同的语法，但是允许你操作比你的RAM大的文件。

解决方案1:

使用大数据的熊猫

解决方案2:

TextFileReader = pd.read_csv(path, chunksize=1000)  # the number of rows per chunk

dfList = []
for df in TextFileReader:
    dfList.append(df)

df = pd.concat(dfList,sort=False)

如果您使用pandas将大文件读入块，然后逐行yield，这是我所做的

import pandas as pd

def chunck_generator(filename, header=False,chunk_size = 10 ** 5):
   for chunk in pd.read_csv(filename,delimiter=',', iterator=True, chunksize=chunk_size, parse_dates=[1] ): 
        yield (chunk)

def _generator( filename, header=False,chunk_size = 10 ** 5):
    chunk = chunck_generator(filename, header=False,chunk_size = 10 ** 5)
    for row in chunk:
        yield row

if __name__ == "__main__":
filename = r'file.csv'
        generator = generator(filename=filename)
        while True:
           print(next(generator))

在使用chunksize选项之前，如果你想确定你想要在@unutbu提到的分块for循环中写入的进程函数，你可以简单地使用nrows选项。

small_df = pd.read_csv(filename, nrows=100)

一旦确定流程块准备好了，就可以将其放入整个数据帧的分块for循环中。