您可以将数据读入为块，并将每个块保存为pickle。

import pandas as pd 
import pickle

in_path = "" #Path where the large file is
out_path = "" #Path to save the pickle files to
chunk_size = 400000 #size of chunks relies on your available memory
separator = "~"

reader = pd.read_csv(in_path,sep=separator,chunksize=chunk_size, 
                    low_memory=False)    


for i, chunk in enumerate(reader):
    out_file = out_path + "/data_{}.pkl".format(i+1)
    with open(out_file, "wb") as f:
        pickle.dump(chunk,f,pickle.HIGHEST_PROTOCOL)

在下一步中，读入pickle并将每个pickle附加到所需的数据框架中。

import glob
pickle_path = "" #Same Path as out_path i.e. where the pickle files are

data_p_files=[]
for name in glob.glob(pickle_path + "/data_*.pkl"):
   data_p_files.append(name)


df = pd.DataFrame([])
for i in range(len(data_p_files)):
    df = df.append(pd.read_pickle(data_p_files[i]),ignore_index=True)

下面是一个例子:

chunkTemp = []
queryTemp = []
query = pd.DataFrame()

for chunk in pd.read_csv(file, header=0, chunksize=<your_chunksize>, iterator=True, low_memory=False):

    #REPLACING BLANK SPACES AT COLUMNS' NAMES FOR SQL OPTIMIZATION
    chunk = chunk.rename(columns = {c: c.replace(' ', '') for c in chunk.columns})

    #YOU CAN EITHER: 
    #1)BUFFER THE CHUNKS IN ORDER TO LOAD YOUR WHOLE DATASET 
    chunkTemp.append(chunk)

    #2)DO YOUR PROCESSING OVER A CHUNK AND STORE THE RESULT OF IT
    query = chunk[chunk[<column_name>].str.startswith(<some_pattern>)]   
    #BUFFERING PROCESSED DATA
    queryTemp.append(query)

#!  NEVER DO pd.concat OR pd.DataFrame() INSIDE A LOOP
print("Database: CONCATENATING CHUNKS INTO A SINGLE DATAFRAME")
chunk = pd.concat(chunkTemp)
print("Database: LOADED")

#CONCATENATING PROCESSED DATA
query = pd.concat(queryTemp)
print(query)

该错误表明机器没有足够的内存来读取整个 CSV一次转换成一个数据帧。假设您不需要整个数据集 内存，避免这个问题的一种方法是处理CSV在 Chunks(通过指定chunksize参数):

chunksize = 10 ** 6
for chunk in pd.read_csv(filename, chunksize=chunksize):
    process(chunk)

chunksize参数指定每个块的行数。 (当然，最后一个块可能包含少于块大小的行。)

熊猫>= 1.2

Read_csv with chunksize返回一个上下文管理器，像这样使用:

chunksize = 10 ** 6
with pd.read_csv(filename, chunksize=chunksize) as reader:
    for chunk in reader:
        process(chunk)

参见 GH38225

我是这样说的:

chunks=pd.read_table('aphro.csv',chunksize=1000000,sep=';',\
       names=['lat','long','rf','date','slno'],index_col='slno',\
       header=None,parse_dates=['date'])

df=pd.DataFrame()
%time df=pd.concat(chunk.groupby(['lat','long',chunk['date'].map(lambda x: x.year)])['rf'].agg(['sum']) for chunk in chunks)

解决方案1:

使用大数据的熊猫

解决方案2:

TextFileReader = pd.read_csv(path, chunksize=1000)  # the number of rows per chunk

dfList = []
for df in TextFileReader:
    dfList.append(df)

df = pd.concat(dfList,sort=False)

如果您使用pandas将大文件读入块，然后逐行yield，这是我所做的

import pandas as pd

def chunck_generator(filename, header=False,chunk_size = 10 ** 5):
   for chunk in pd.read_csv(filename,delimiter=',', iterator=True, chunksize=chunk_size, parse_dates=[1] ): 
        yield (chunk)

def _generator( filename, header=False,chunk_size = 10 ** 5):
    chunk = chunck_generator(filename, header=False,chunk_size = 10 ** 5)
    for row in chunk:
        yield row

if __name__ == "__main__":
filename = r'file.csv'
        generator = generator(filename=filename)
        while True:
           print(next(generator))