如果你需要else子句，你可以使用下面的语法:

AND:

if %v1% == a (if %v2% == b (echo yes) else echo no) else echo no

OR:

if %v1% == a (echo yes) else (if %v2% == b (echo yes) else echo no)

试试否定操作数“not”!

好吧，如果你可以使用嵌套的“if”对if语句执行“AND”操作(参考前面的答案)，那么你可以对“if not”做同样的事情来执行“or”操作。

如果你还没有完全明白，继续往下读。否则，就不要浪费时间，回到编程中去。

就像嵌套的“if”只有在所有条件为真时才被满足一样，嵌套的“if not”只有在所有条件为假时才被满足。这类似于你想要对'or'操作数做的事情，不是吗?

即使嵌套的“if not”中的任何一个条件为真，整个语句仍然不满足。因此，你可以连续使用否定的“if”，记住条件语句的主体应该是你想要做的，如果所有嵌套的条件都是假的。你真正想要给出的主体应该在else语句下。

如果你还是不明白事情的真相，对不起，我16岁了，我只能解释这么多了。

如果你需要else子句，你可以使用下面的语法:

AND:

if %v1% == a (if %v2% == b (echo yes) else echo no) else echo no

OR:

if %v1% == a (echo yes) else (if %v2% == b (echo yes) else echo no)

对Andry的回答进行了轻微修改，减少了重复的类型命令:

set "A=1" & set "B=2" & call :IF_AND
set "A=1" & set "B=3" & call :IF_AND
set "A=2" & set "B=2" & call :IF_AND
set "A=2" & set "B=3" & call :IF_AND

echo.

set "A=1" & set "B=2" & call :IF_OR
set "A=1" & set "B=3" & call :IF_OR
set "A=2" & set "B=2" & call :IF_OR
set "A=2" & set "B=3" & call :IF_OR

goto :eof

:IF_OR

(if /i not %A% EQU 1 (
   if /i not %B% EQU 2 (
      echo FALSE-
      type 2>nul
   )
)) && echo TRUE+

goto :eof

:IF_AND


(if /i %A% EQU 1 (
   if /i %B% EQU 2 (
      echo TRUE+
      type 2>nul
   )
)) && echo FALSE-

goto :eof

只有OR部分是棘手的，但对于一个包含NOT OR AND的普通布尔表达式，唯一好的解决方案是:

REM if A == B OR C == C then yes

(call :strequ A B || call :strequ C C) && echo yes
exit /b

:strequ
if "%1" == "%2" exit /b 0
exit /b 1

Athul Prakash (age 16 at the time) gave a logical idea for how to implement an OR test by negating the conditions in IF statements and then using the ELSE clause as the location to put the code that requires execution. I thought to myself that there are however two else clauses usually needed since he is suggesting using two IF statements, and so the executed code needs to be written twice. However, if a GOTO is used to skip past the required code, instead of writing ELSE clauses the code for execution only needs to be written once.

下面是一个可测试的例子，我将如何实现Athul Prakash的否定逻辑来创建一个OR。

在我的例子中，如果某人有坦克执照或者正在服兵役，他就可以开坦克。在两个提示中输入true或false，你将能够看到逻辑是否允许你驾驶坦克。

@ECHO OFF
@SET /p tanklicence=tanklicence:
@SET /p militaryservice=militaryservice:

IF /I NOT %tanklicence%==true IF /I NOT %militaryservice%==true GOTO done

ECHO I am driving a tank with tanklicence set to %tanklicence% and militaryservice set to %militaryservice%

:done

PAUSE