如何验证程序是否存在,以返回错误并退出,或继续执行脚本?
看起来应该很容易,但这让我很为难。
如何验证程序是否存在,以返回错误并退出,或继续执行脚本?
看起来应该很容易,但这让我很为难。
当前回答
我的Debian服务器设置:
当多个包包含相同的名称时,我遇到了问题。
例如apache2。这就是我的解决方案:
function _apt_install() {
apt-get install -y $1 > /dev/null
}
function _apt_install_norecommends() {
apt-get install -y --no-install-recommends $1 > /dev/null
}
function _apt_available() {
if [ `apt-cache search $1 | grep -o "$1" | uniq | wc -l` = "1" ]; then
echo "Package is available : $1"
PACKAGE_INSTALL="1"
else
echo "Package $1 is NOT available for install"
echo "We can not continue without this package..."
echo "Exitting now.."
exit 0
fi
}
function _package_install {
_apt_available $1
if [ "${PACKAGE_INSTALL}" = "1" ]; then
if [ "$(dpkg-query -l $1 | tail -n1 | cut -c1-2)" = "ii" ]; then
echo "package is already_installed: $1"
else
echo "installing package : $1, please wait.."
_apt_install $1
sleep 0.5
fi
fi
}
function _package_install_no_recommends {
_apt_available $1
if [ "${PACKAGE_INSTALL}" = "1" ]; then
if [ "$(dpkg-query -l $1 | tail -n1 | cut -c1-2)" = "ii" ]; then
echo "package is already_installed: $1"
else
echo "installing package : $1, please wait.."
_apt_install_norecommends $1
sleep 0.5
fi
fi
}
其他回答
我同意lhunath不鼓励使用which,他的解决方案对Bash用户完全有效。但是,为了更便于携带,应使用命令-v:
$ command -v foo >/dev/null 2>&1 || { echo "I require foo but it's not installed. Aborting." >&2; exit 1; }
命令命令符合POSIX。参见此处了解其规范:command-execute一个简单的命令
注意:类型符合POSIX,但类型-P不符合。
我找不到一个可行的解决方案,但编辑了一下后,我想到了这个。这对我有用:
dpkg --get-selections | grep -q linux-headers-$(uname -r)
if [ $? -eq 1 ]; then
apt-get install linux-headers-$(uname -r)
fi
以下是检查命令是否存在于$PATH中并可执行的便携式方法:
[ -x "$(command -v foo)" ]
例子:
if ! [ -x "$(command -v git)" ]; then
echo 'Error: git is not installed.' >&2
exit 1
fi
需要进行可执行检查,因为如果$PATH中找不到具有该名称的可执行文件,bash将返回一个不可执行文件。
还请注意,如果$PATH中存在与可执行文件同名的不可执行文件,则dash会返回前者,即使后者会被执行。这是一个bug,违反了POSIX标准。[错误报告][标准]编辑:从破折号0.5.11(Debian 11)开始,这似乎是固定的。
此外,如果要查找的命令已定义为别名,则此操作将失败。
我的Debian服务器设置:
当多个包包含相同的名称时,我遇到了问题。
例如apache2。这就是我的解决方案:
function _apt_install() {
apt-get install -y $1 > /dev/null
}
function _apt_install_norecommends() {
apt-get install -y --no-install-recommends $1 > /dev/null
}
function _apt_available() {
if [ `apt-cache search $1 | grep -o "$1" | uniq | wc -l` = "1" ]; then
echo "Package is available : $1"
PACKAGE_INSTALL="1"
else
echo "Package $1 is NOT available for install"
echo "We can not continue without this package..."
echo "Exitting now.."
exit 0
fi
}
function _package_install {
_apt_available $1
if [ "${PACKAGE_INSTALL}" = "1" ]; then
if [ "$(dpkg-query -l $1 | tail -n1 | cut -c1-2)" = "ii" ]; then
echo "package is already_installed: $1"
else
echo "installing package : $1, please wait.."
_apt_install $1
sleep 0.5
fi
fi
}
function _package_install_no_recommends {
_apt_available $1
if [ "${PACKAGE_INSTALL}" = "1" ]; then
if [ "$(dpkg-query -l $1 | tail -n1 | cut -c1-2)" = "ii" ]; then
echo "package is already_installed: $1"
else
echo "installing package : $1, please wait.."
_apt_install_norecommends $1
sleep 0.5
fi
fi
}
which命令可能有用。男子谁
如果找到可执行文件,则返回0;如果找不到或不可执行,则返回1:
NAME
which - locate a command
SYNOPSIS
which [-a] filename ...
DESCRIPTION
which returns the pathnames of the files which would
be executed in the current environment, had its
arguments been given as commands in a strictly
POSIX-conformant shell. It does this by searching
the PATH for executable files matching the names
of the arguments.
OPTIONS
-a print all matching pathnames of each argument
EXIT STATUS
0 if all specified commands are
found and executable
1 if one or more specified commands is nonexistent
or not executable
2 if an invalid option is specified
这样做的好处是,它可以确定可执行文件在运行环境中是否可用-这节省了一些问题。。。