我如何在另一个JavaScript文件中添加一个JavaScript文件,类似于CSS中的 @import?
当前回答
您将使用此:
<script src="your_file.js"></script>
轻松!
其他回答
可以动态地创建一个JavaScript标签并将其添加到来自其他JavaScript代码的HTML文档中,这将加载针对JavaScript文件。
function includeJs(jsFilePath) {
var js = document.createElement("script");
js.type = "text/javascript";
js.src = jsFilePath;
document.body.appendChild(js);
}
includeJs("/path/to/some/file.js");
var s=["Hscript.js","checkRobert.js","Hscript.js"];
for(i=0;i<s.length;i++){
var script=document.createElement("script");
script.type="text/javascript";
script.src=s[i];
document.getElementsByTagName("head")[0].appendChild(script)
};
保持它好,短,简单,可持续的! :]
// Third-party plugins / script (don't forget the full path is necessary)
var FULL_PATH = '', s =
[
FULL_PATH + 'plugins/script.js' // Script example
FULL_PATH + 'plugins/jquery.1.2.js', // jQuery Library
FULL_PATH + 'plugins/crypto-js/hmac-sha1.js', // CryptoJS
FULL_PATH + 'plugins/crypto-js/enc-base64-min.js' // CryptoJS
];
function load(url)
{
var ajax = new XMLHttpRequest();
ajax.open('GET', url, false);
ajax.onreadystatechange = function ()
{
var script = ajax.response || ajax.responseText;
if (ajax.readyState === 4)
{
switch(ajax.status)
{
case 200:
eval.apply( window, [script] );
console.log("library loaded: ", url);
break;
default:
console.log("ERROR: library not loaded: ", url);
}
}
};
ajax.send(null);
}
// Initialize a single load
load('plugins/script.js');
// Initialize a full load of scripts
if (s.length > 0)
{
for (i = 0; i < s.length; i++)
{
load(s[i]);
}
}
这个代码只是一个短暂的功能例子,可能需要额外的功能功能,以便在任何(或提供)平台上提供完整的支持。
与 $.getScript 和实际上任何其他解决方案需要一个呼叫回复,当加载完成时的问题是,如果你有多个文件使用它,并依赖对方,你已经没有办法知道什么时候所有的脚本被加载(一旦它们被纳入多个文件)。
文件3JS
var f3obj = "file3";
// Define other stuff
文件2JS:
var f2obj = "file2";
$.getScript("file3.js", function(){
alert(f3obj);
// Use anything defined in file3.
});
此分類上一篇: JS
$.getScript("file2.js", function(){
alert(f3obj); //This will probably fail because file3 is only guaranteed to have loaded inside the callback in file2.
alert(f2obj);
// Use anything defined in the loaded script...
});
您可以尝试使用 $.when 检查一系列丢失的对象,但现在您正在做这一点在每个文件和文件2 将被视为加载,一旦 $.when 执行,而不是当呼叫回复执行,所以文件1 仍然继续执行之前文件3 被加载,这真的仍然有相同的问题。
我喜欢延长jQuery的想法,但显然你不需要。
在呼叫document.writeln之前,它检查以确保脚本已经没有被加载,通过评估所有脚本元素。
而不是这个方法,你可以尝试修改 jQuery readyList,但这似乎是一个更糟糕的解决方案。
解决方案:
$.extend(true,
{
import_js : function(scriptpath, reAddLast)
{
if (typeof reAddLast === "undefined" || reAddLast === null)
{
reAddLast = true; // Default this value to true. It is not used by the end user, only to facilitate recursion correctly.
}
var found = false;
if (reAddLast == true) // If we are re-adding the originating script we do not care if it has already been added.
{
found = $('script').filter(function () {
return ($(this).attr('src') == scriptpath);
}).length != 0; // jQuery to check if the script already exists. (replace it with straight JavaScript if you don't like jQuery.
}
if (found == false) {
var callingScriptPath = $('script').last().attr("src"); // Get the script that is currently loading. Again this creates a limitation where this should not be used in a button, and only before document.ready.
document.writeln("<script type='text/javascript' src='" + scriptpath + "'></script>"); // Add the script to the document using writeln
if (reAddLast)
{
$.import_js(callingScriptPath, false); // Call itself with the originating script to fix the order.
throw 'Readding script to correct order: ' + scriptpath + ' < ' + callingScriptPath; // This halts execution of the originating script since it is getting reloaded. If you put a try / catch around the call to $.import_js you results will vary.
}
return true;
}
return false;
}
});
使用:
var f3obj = "file3";
// Define other stuff
$(function(){
f3obj = "file3docready";
});
文件2:
$.import_js('js/file3.js');
var f2obj = "file2";
$(function(){
f2obj = "file2docready";
});
文件1:
$.import_js('js/file2.js');
// Use objects from file2 or file3
alert(f3obj); // "file3"
alert(f2obj); // "file2"
$(function(){
// Use objects from file2 or file3 some more.
alert(f3obj); //"file3docready"
alert(f2obj); //"file2docready"
});
如果你发现有两个或多个脚本在被召唤时占据相同功能,我们不能同时包含它们,我们需要通过用户选择进行动态操作。
在 jQuery 中的另一个文件使用 $.getScript 工作,因为脚本不会默认隐藏。
HTML
<select class="choice">
<option value="script1" selected>Script-1</option>
<option value="script2">Script-2</option>
</select>
雅各布斯
$(".choice").change(on_change);
var url = "https://example.com";
$.url1 = url + "/script1.js";
$.url2 = url + "/script2.js";
function on_change() {
if ($(".choice").val()=="script1") {
script1();
} else {
script2();
}
}
// script1
function script1() {
$.getScript($.url1, function( data, textStatus, jqxhr ) {
// Execute here
});
}
// script2
function script2() {
$.getScript($.url2, function( data, textStatus, jqxhr ) {
// Execute here
});
}