我一直在寻找一种简单的Java算法来生成伪随机字母数字字符串。在我的情况下,它将被用作唯一的会话/密钥标识符,“很可能”在超过50万代的时间内是唯一的(我的需求实际上不需要更复杂的东西)。
理想情况下,我可以根据我的独特性需求指定长度。例如,生成的长度为12的字符串可能看起来像“AEYGF7K0DM1X”。
我一直在寻找一种简单的Java算法来生成伪随机字母数字字符串。在我的情况下,它将被用作唯一的会话/密钥标识符,“很可能”在超过50万代的时间内是唯一的(我的需求实际上不需要更复杂的东西)。
理想情况下,我可以根据我的独特性需求指定长度。例如,生成的长度为12的字符串可能看起来像“AEYGF7K0DM1X”。
当前回答
您可以为此使用Apache Commons库RandomStringUtils:
RandomStringUtils.randomAlphanumeric(20).toUpperCase();
其他回答
import java.util.Date;
import java.util.Random;
public class RandomGenerator {
private static Random random = new Random((new Date()).getTime());
public static String generateRandomString(int length) {
char[] values = {'a','b','c','d','e','f','g','h','i','j',
'k','l','m','n','o','p','q','r','s','t',
'u','v','w','x','y','z','0','1','2','3',
'4','5','6','7','8','9'};
String out = "";
for (int i=0;i<length;i++) {
int idx=random.nextInt(values.length);
out += values[idx];
}
return out;
}
}
如果密码必须包含数字和字母特殊字符,则可以使用以下代码:
private static final String NUMBERS = "0123456789";
private static final String UPPER_ALPHABETS = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
private static final String LOWER_ALPHABETS = "abcdefghijklmnopqrstuvwxyz";
private static final String SPECIALCHARACTERS = "@#$%&*";
private static final int MINLENGTHOFPASSWORD = 8;
public static String getRandomPassword() {
StringBuilder password = new StringBuilder();
int j = 0;
for (int i = 0; i < MINLENGTHOFPASSWORD; i++) {
password.append(getRandomPasswordCharacters(j));
j++;
if (j == 3) {
j = 0;
}
}
return password.toString();
}
private static String getRandomPasswordCharacters(int pos) {
Random randomNum = new Random();
StringBuilder randomChar = new StringBuilder();
switch (pos) {
case 0:
randomChar.append(NUMBERS.charAt(randomNum.nextInt(NUMBERS.length() - 1)));
break;
case 1:
randomChar.append(UPPER_ALPHABETS.charAt(randomNum.nextInt(UPPER_ALPHABETS.length() - 1)));
break;
case 2:
randomChar.append(SPECIALCHARACTERS.charAt(randomNum.nextInt(SPECIALCHARACTERS.length() - 1)));
break;
case 3:
randomChar.append(LOWER_ALPHABETS.charAt(randomNum.nextInt(LOWER_ALPHABETS.length() - 1)));
break;
}
return randomChar.toString();
}
这里有一个简单的一行代码,使用UUID作为字符基础,可以指定(几乎)任何长度。(是的,我知道以前有人建议使用UUID。)
public static String randString(int length) {
return UUID.randomUUID().toString().replace("-", "").substring(0, Math.min(length, 32)) + (length > 32 ? randString(length - 32) : "");
}
高效而简短。
/**
* Utility class for generating random Strings.
*/
public interface RandomUtil {
int DEF_COUNT = 20;
Random RANDOM = new SecureRandom();
/**
* Generate a password.
*
* @return the generated password
*/
static String generatePassword() {
return generate(true, true);
}
/**
* Generate an activation key.
*
* @return the generated activation key
*/
static String generateActivationKey() {
return generate(false, true);
}
/**
* Generate a reset key.
*
* @return the generated reset key
*/
static String generateResetKey() {
return generate(false, true);
}
static String generate(boolean letters, boolean numbers) {
int
start = ' ',
end = 'z' + 1,
count = DEF_COUNT,
gap = end - start;
StringBuilder builder = new StringBuilder(count);
while (count-- != 0) {
int codePoint = RANDOM.nextInt(gap) + start;
switch (getType(codePoint)) {
case UNASSIGNED:
case PRIVATE_USE:
case SURROGATE:
count++;
continue;
}
int numberOfChars = charCount(codePoint);
if (count == 0 && numberOfChars > 1) {
count++;
continue;
}
if (letters && isLetter(codePoint)
|| numbers && isDigit(codePoint)
|| !letters && !numbers) {
builder.appendCodePoint(codePoint);
if (numberOfChars == 2)
count--;
}
else
count++;
}
return builder.toString();
}
}
这里是一个基于流的Java8解决方案。
public String generateString(String alphabet, int length) {
return generateString(alphabet, length, new SecureRandom()::nextInt);
}
// nextInt = bound -> n in [0, bound)
public String generateString(String source, int length, IntFunction<Integer> nextInt) {
StringBuilder sb = new StringBuilder();
IntStream.generate(source::length)
.boxed()
.limit(length)
.map(nextInt::apply)
.map(source::charAt)
.forEach(sb::append);
return sb.toString();
}
像这样使用
String alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";
int length = 12;
String generated = generateString(alphabet, length);
System.out.println(generated);
函数nextInt应该接受一个int绑定,并返回一个介于0和绑定-1之间的随机数。