我正在尝试使用echo命令在终端中打印文本。
我想用红色打印文本。我该怎么做？
当前回答
其他的答案已经很好地解释了如何做到这一点。我仍然缺少的是对颜色代码的一个精心安排的概述。维基百科文章“ANSI转义码”对此非常有用。然而，由于颜色通常可以在每个终端中进行配置，并且看起来不同，所以我更希望有一个可以在终端中调用的功能。为此，我创建了以下函数来显示颜色表，并提醒我如何设置它们（排列方式受wiki文章的启发）。例如，您可以将它们加载到.bashrc/.zshrc中，或将它们作为脚本放在某处。
256色
由bash/zsh脚本生成：
function showcolors256() {
local row col blockrow blockcol red green blue
local showcolor=_showcolor256_${1:-bg}
local white="\033[1;37m"
local reset="\033[0m"
echo -e "Set foreground color: \\\\033[38;5;${white}NNN${reset}m"
echo -e "Set background color: \\\\033[48;5;${white}NNN${reset}m"
echo -e "Reset color & style: \\\\033[0m"
echo
echo 16 standard color codes:
for row in {0..1}; do
for col in {0..7}; do
$showcolor $(( row*8 + col )) $row
done
echo
done
echo
echo 6·6·6 RGB color codes:
for blockrow in {0..2}; do
for red in {0..5}; do
for blockcol in {0..1}; do
green=$(( blockrow*2 + blockcol ))
for blue in {0..5}; do
$showcolor $(( red*36 + green*6 + blue + 16 )) $green
done
echo -n " "
done
echo
done
echo
done
echo 24 grayscale color codes:
for row in {0..1}; do
for col in {0..11}; do
$showcolor $(( row*12 + col + 232 )) $row
done
echo
done
echo
}
function _showcolor256_fg() {
local code=$( printf %03d $1 )
echo -ne "\033[38;5;${code}m"
echo -nE " $code "
echo -ne "\033[0m"
}
function _showcolor256_bg() {
if (( $2 % 2 == 0 )); then
echo -ne "\033[1;37m"
else
echo -ne "\033[0;30m"
fi
local code=$( printf %03d $1 )
echo -ne "\033[48;5;${code}m"
echo -nE " $code "
echo -ne "\033[0m"
}
16种颜色
由bash/zsh脚本生成：
function showcolors16() {
_showcolor "\033[0;30m" "\033[1;30m" "\033[40m" "\033[100m"
_showcolor "\033[0;31m" "\033[1;31m" "\033[41m" "\033[101m"
_showcolor "\033[0;32m" "\033[1;32m" "\033[42m" "\033[102m"
_showcolor "\033[0;33m" "\033[1;33m" "\033[43m" "\033[103m"
_showcolor "\033[0;34m" "\033[1;34m" "\033[44m" "\033[104m"
_showcolor "\033[0;35m" "\033[1;35m" "\033[45m" "\033[105m"
_showcolor "\033[0;36m" "\033[1;36m" "\033[46m" "\033[106m"
_showcolor "\033[0;37m" "\033[1;37m" "\033[47m" "\033[107m"
}
function _showcolor() {
for code in $@; do
echo -ne "$code"
echo -nE " $code"
echo -ne " \033[0m "
done
echo
}
其他回答
这些代码在我的Ubuntu盒子上运行：
echo -e "\x1B[31m foobar \x1B[0m"
echo -e "\x1B[32m foobar \x1B[0m"
echo -e "\x1B[96m foobar \x1B[0m"
echo -e "\x1B[01;96m foobar \x1B[0m"
echo -e "\x1B[01;95m foobar \x1B[0m"
echo -e "\x1B[01;94m foobar \x1B[0m"
echo -e "\x1B[01;93m foobar \x1B[0m"
echo -e "\x1B[01;91m foobar \x1B[0m"
echo -e "\x1B[01;90m foobar \x1B[0m"
echo -e "\x1B[01;89m foobar \x1B[0m"
echo -e "\x1B[01;36m foobar \x1B[0m"
这将以不同的颜色打印字母a、b、c、d：
echo -e "\x1B[0;93m a \x1B[0m b \x1B[0;92m c \x1B[0;93m d \x1B[0;94m"
对于循环：
for (( i = 0; i < 17; i++ ));
do echo "$(tput setaf $i)This is ($i) $(tput sgr0)";
done
这是颜色开关\033[。请参阅历史记录。
颜色代码类似于1；32（浅绿色），0；34（蓝色），1；34（浅蓝色）等。
我们使用颜色开关\033[和0m（无颜色代码）终止颜色序列。就像标记语言中的打开和关闭选项卡一样。
SWITCH="\033["
NORMAL="${SWITCH}0m"
YELLOW="${SWITCH}1;33m"
echo "${YELLOW}hello, yellow${NORMAL}"
简单的彩色回声功能解决方案：
cecho() {
local code="\033["
case "$1" in
black | bk) color="${code}0;30m";;
red | r) color="${code}1;31m";;
green | g) color="${code}1;32m";;
yellow | y) color="${code}1;33m";;
blue | b) color="${code}1;34m";;
purple | p) color="${code}1;35m";;
cyan | c) color="${code}1;36m";;
gray | gr) color="${code}0;37m";;
*) local text="$1"
esac
[ -z "$text" ] && local text="$color$2${code}0m"
echo "$text"
}
cecho "Normal"
cecho y "Yellow!"
如果您使用zsh或bash
black() {
echo -e "\e[30m${1}\e[0m"
}
red() {
echo -e "\e[31m${1}\e[0m"
}
green() {
echo -e "\e[32m${1}\e[0m"
}
yellow() {
echo -e "\e[33m${1}\e[0m"
}
blue() {
echo -e "\e[34m${1}\e[0m"
}
magenta() {
echo -e "\e[35m${1}\e[0m"
}
cyan() {
echo -e "\e[36m${1}\e[0m"
}
gray() {
echo -e "\e[90m${1}\e[0m"
}
black 'BLACK'
red 'RED'
green 'GREEN'
yellow 'YELLOW'
blue 'BLUE'
magenta 'MAGENTA'
cyan 'CYAN'
gray 'GRAY'
联机尝试
其他的答案已经很好地解释了如何做到这一点。我仍然缺少的是对颜色代码的一个精心安排的概述。维基百科文章“ANSI转义码”对此非常有用。然而，由于颜色通常可以在每个终端中进行配置，并且看起来不同，所以我更希望有一个可以在终端中调用的功能。为此，我创建了以下函数来显示颜色表，并提醒我如何设置它们（排列方式受wiki文章的启发）。例如，您可以将它们加载到.bashrc/.zshrc中，或将它们作为脚本放在某处。
256色
由bash/zsh脚本生成：
function showcolors256() {
local row col blockrow blockcol red green blue
local showcolor=_showcolor256_${1:-bg}
local white="\033[1;37m"
local reset="\033[0m"
echo -e "Set foreground color: \\\\033[38;5;${white}NNN${reset}m"
echo -e "Set background color: \\\\033[48;5;${white}NNN${reset}m"
echo -e "Reset color & style: \\\\033[0m"
echo
echo 16 standard color codes:
for row in {0..1}; do
for col in {0..7}; do
$showcolor $(( row*8 + col )) $row
done
echo
done
echo
echo 6·6·6 RGB color codes:
for blockrow in {0..2}; do
for red in {0..5}; do
for blockcol in {0..1}; do
green=$(( blockrow*2 + blockcol ))
for blue in {0..5}; do
$showcolor $(( red*36 + green*6 + blue + 16 )) $green
done
echo -n " "
done
echo
done
echo
done
echo 24 grayscale color codes:
for row in {0..1}; do
for col in {0..11}; do
$showcolor $(( row*12 + col + 232 )) $row
done
echo
done
echo
}
function _showcolor256_fg() {
local code=$( printf %03d $1 )
echo -ne "\033[38;5;${code}m"
echo -nE " $code "
echo -ne "\033[0m"
}
function _showcolor256_bg() {
if (( $2 % 2 == 0 )); then
echo -ne "\033[1;37m"
else
echo -ne "\033[0;30m"
fi
local code=$( printf %03d $1 )
echo -ne "\033[48;5;${code}m"
echo -nE " $code "
echo -ne "\033[0m"
}
16种颜色
由bash/zsh脚本生成：
function showcolors16() {
_showcolor "\033[0;30m" "\033[1;30m" "\033[40m" "\033[100m"
_showcolor "\033[0;31m" "\033[1;31m" "\033[41m" "\033[101m"
_showcolor "\033[0;32m" "\033[1;32m" "\033[42m" "\033[102m"
_showcolor "\033[0;33m" "\033[1;33m" "\033[43m" "\033[103m"
_showcolor "\033[0;34m" "\033[1;34m" "\033[44m" "\033[104m"
_showcolor "\033[0;35m" "\033[1;35m" "\033[45m" "\033[105m"
_showcolor "\033[0;36m" "\033[1;36m" "\033[46m" "\033[106m"
_showcolor "\033[0;37m" "\033[1;37m" "\033[47m" "\033[107m"
}
function _showcolor() {
for code in $@; do
echo -ne "$code"
echo -nE " $code"
echo -ne " \033[0m "
done
echo
}
red='\e[0;31m'
NC='\e[0m' # No Color
echo -e "${red}Hello Stackoverflow${NC}"
这个答案是正确的，只是对颜色的调用不应该在引号内。
echo -e ${red}"Hello Stackoverflow"${NC}
应该会成功的。
