如果目录不存在,下面的方法是否正确?

它应该对脚本具有完全的权限,并且其他人可以阅读。

var dir = __dirname + '/upload';
if (!path.existsSync(dir)) {
    fs.mkdirSync(dir, 0744);
}

当前回答

单行版本:

// Or in TypeScript: import * as fs from 'fs';
const fs = require('fs');
!fs.existsSync(dir) && fs.mkdirSync(dir);

其他回答

Use:

var filessystem = require('fs');
var dir = './path/subpath/';

if (!filessystem.existsSync(dir))
{
    filessystem.mkdirSync(dir);
}
else
{
    console.log("Directory already exist");
}

使用Node.js 10 + ES6:

import path from 'path';
import fs from 'fs';

(async () => {
  const dir = path.join(__dirname, 'upload');

  try {
    await fs.promises.mkdir(dir);
  } catch (error) {
    if (error.code === 'EEXIST') {
      // Something already exists, but is it a file or directory?
      const lstat = await fs.promises.lstat(dir);

      if (!lstat.isDirectory()) {
        throw error;
      }
    } else {
      throw error;
    }
  }
})();

异步执行此操作的函数(从使用同步函数的SO上的类似答案调整,我现在找不到)

// ensure-directory.js
import { mkdir, access } from 'fs'

/**
 * directoryPath is a path to a directory (no trailing file!)
 */
export default async directoryPath => {
  directoryPath = directoryPath.replace(/\\/g, '/')

  // -- preparation to allow absolute paths as well
  let root = ''
  if (directoryPath[0] === '/') {
    root = '/'
    directoryPath = directoryPath.slice(1)
  } else if (directoryPath[1] === ':') {
    root = directoryPath.slice(0, 3) // c:\
    directoryPath = directoryPath.slice(3)
  }

  // -- create folders all the way down
  const folders = directoryPath.split('/')
  let folderPath = `${root}`
  for (const folder of folders) {
    folderPath = `${folderPath}${folder}/`

    const folderExists = await new Promise(resolve =>
      access(folderPath, error => {
        if (error) {
          resolve(false)
        }
        resolve(true)
      })
    )

    if (!folderExists) {
      await new Promise((resolve, reject) =>
        mkdir(folderPath, error => {
          if (error) {
            reject('Error creating folderPath')
          }
          resolve(folderPath)
        })
      )
    }
  }
}

解决方案

CommonJS

const fs = require('fs');
const path = require('path');

const dir = path.resolve(path.join(__dirname, 'upload');

if (!fs.existsSync(dir)) {
  fs.mkdirSync(dir);
}

// OR
if (!fs.existsSync(dir)) {
  fs.mkdirSync(dir, {
    mode: 0o744, // Not supported on Windows. Default: 0o777
  });
}

ESM

更新您的包。Json文件配置

{
  // declare using ECMAScript modules(ESM)
  "type": "module",
  //...
}
import fs from 'fs';
import path from 'path';
import { fileURLToPath } from 'url';

// create one custom `__dirname`, because it does not exist in es-module env ⚠️
const __filename = fileURLToPath(import.meta.url);
const __dirname = path.dirname(__filename);
const dir = path.resolve(path.join(__dirname, 'upload');

if (!fs.existsSync(dir)) {
  fs.mkdirSync(dir);
}

// OR
if (!fs.existsSync(dir)) {
  fs.mkdirSync(dir, {
    mode: 0o744, // Not supported on Windows. Default: 0o777
  });
}

更新2022

import { existsSync } from 'node:fs';

refs

NodeJS版本:v18.2.0

https://nodejs.org/api/fs.html#fsexistssyncpath

https://nodejs.org/api/fs.html#fsmkdirsyncpath-options

https://nodejs.org/api/url.html#urlfileurltopathurl

https://github.com/nodejs/help/issues/2907#issuecomment-757446568

ESM: ECMAScript模块

https://nodejs.org/api/esm.html#introduction

Fs.exist()已弃用。所以我使用fs.stat()来检查目录状态。如果目录不存在,fs.stat()抛出一个错误,并显示类似'没有这样的文件或目录'的消息。然后我创建了一个目录。

const fs = require('fs').promises;

const dir = './dir';
fs.stat(dir).catch(async (err) => {
  if (err.message.includes('no such file or directory')) {
    await fs.mkdir(dir);
  }
});