如果目录不存在,下面的方法是否正确?

它应该对脚本具有完全的权限,并且其他人可以阅读。

var dir = __dirname + '/upload';
if (!path.existsSync(dir)) {
    fs.mkdirSync(dir, 0744);
}

当前回答

Use:

var filessystem = require('fs');
var dir = './path/subpath/';

if (!filessystem.existsSync(dir))
{
    filessystem.mkdirSync(dir);
}
else
{
    console.log("Directory already exist");
}

其他回答

您可以使用Node.js文件系统命令fs。Stat检查目录是否存在。Mkdir创建一个带有回调的目录,或fs. Mkdir。mkdirSync创建一个没有回调的目录,如下所示:

// First require fs
const fs = require('fs');

// Create directory if not exist (function)
const createDir = (path) => {
    // Check if dir exist
    fs.stat(path, (err, stats) => {
        if (stats.isDirectory()) {
            // Do nothing
        } else {
            // If the given path is not a directory, create a directory
            fs.mkdirSync(path);
        }
    });
};

mkdir方法能够递归地在一个路径中创建任何不存在的目录,并忽略存在的目录。

来自Node.js v10/11文档:

// Creates /tmp/a/apple, regardless of whether `/tmp` and /tmp/a exist.
fs.mkdir('/tmp/a/apple', { recursive: true }, (err) => {
    if (err) throw err;
});

注意:首先需要导入内置的fs模块。

现在,这里有一个更健壮的例子,它利用了原生ECMAScript模块(启用了标志和.mjs扩展名),处理非根路径,并说明完整的路径名:

import fs from 'fs';
import path from 'path';

function createDirectories(pathname) {
   const __dirname = path.resolve();
   pathname = pathname.replace(/^\.*\/|\/?[^\/]+\.[a-z]+|\/$/g, ''); // Remove leading directory markers, and remove ending /file-name.extension
   fs.mkdir(path.resolve(__dirname, pathname), { recursive: true }, e => {
       if (e) {
           console.error(e);
       } else {
           console.log('Success');
       }
    });
}

你可以像createDirectories('/components/widget/widget.js');一样使用它。

当然,当目录创建时,你可能想要在async/await中使用promises以一种更可读的同步方式来利用文件创建;但是,这超出了问题的范围。

如果子目录不存在,我必须创建子目录。我用了这个:

const path = require('path');
const fs = require('fs');

function ensureDirectoryExists(p) {
    //console.log(ensureDirectoryExists.name, {p});
    const d = path.dirname(p);
    if (d && d !== p) {
        ensureDirectoryExists(d);
    }
    if (!fs.existsSync(d)) {
        fs.mkdirSync(d);
    }
}

异步执行此操作的函数(从使用同步函数的SO上的类似答案调整,我现在找不到)

// ensure-directory.js
import { mkdir, access } from 'fs'

/**
 * directoryPath is a path to a directory (no trailing file!)
 */
export default async directoryPath => {
  directoryPath = directoryPath.replace(/\\/g, '/')

  // -- preparation to allow absolute paths as well
  let root = ''
  if (directoryPath[0] === '/') {
    root = '/'
    directoryPath = directoryPath.slice(1)
  } else if (directoryPath[1] === ':') {
    root = directoryPath.slice(0, 3) // c:\
    directoryPath = directoryPath.slice(3)
  }

  // -- create folders all the way down
  const folders = directoryPath.split('/')
  let folderPath = `${root}`
  for (const folder of folders) {
    folderPath = `${folderPath}${folder}/`

    const folderExists = await new Promise(resolve =>
      access(folderPath, error => {
        if (error) {
          resolve(false)
        }
        resolve(true)
      })
    )

    if (!folderExists) {
      await new Promise((resolve, reject) =>
        mkdir(folderPath, error => {
          if (error) {
            reject('Error creating folderPath')
          }
          resolve(folderPath)
        })
      )
    }
  }
}

我的解决方案

CommonJS


var fs = require("fs");

var dir = __dirname + '/upload';

// if (!fs.existsSync(dir)) {
//   fs.mkdirSync(dir);
// }

if (!fs.existsSync(dir)) {
  fs.mkdirSync(dir, {
    mode: 0o744,
  });
  // mode's default value is 0o744
}

ESM

更新包。json配置

{
  //...
  "type": "module",
  //...
}
import fs from "fs";
import path from "path";

// create one custom `__dirname`, because it not exist in es-module env ⚠️
const __dirname = path.resolve();

const dir = __dirname + '/upload';

if (!fs.existsSync(dir)) {
  fs.mkdirSync(dir);
}

// OR
if (!fs.existsSync(dir)) {
  fs.mkdirSync(dir, {
    mode: 0o744,
  });
  // mode's default value is 0o744
}

refs

https://nodejs.org/api/fs.html#fsexistssyncpath

https://github.com/nodejs/help/issues/2907#issuecomment-671782092