如何只计算目录中的文件?这将目录本身计算为一个文件:
len(glob.glob('*'))
如何只计算目录中的文件?这将目录本身计算为一个文件:
len(glob.glob('*'))
当前回答
这是一个简单的解决方案,可以计算包含子文件夹的目录中的文件数量。它可能会派上用场:
import os
from pathlib import Path
def count_files(rootdir):
'''counts the number of files in each subfolder in a directory'''
for path in pathlib.Path(rootdir).iterdir():
if path.is_dir():
print("There are " + str(len([name for name in os.listdir(path) \
if os.path.isfile(os.path.join(path, name))])) + " files in " + \
str(path.name))
count_files(data_dir) # data_dir is the directory you want files counted.
你应该得到一个类似这样的输出(当然,占位符改变了):
There are {number of files} files in {name of sub-folder1}
There are {number of files} files in {name of sub-folder2}
其他回答
一行和递归:
def count_files(path):
return sum([len(files) for _, _, files in os.walk(path)])
count_files('path/to/dir')
import os
def count_files(in_directory):
joiner= (in_directory + os.path.sep).__add__
return sum(
os.path.isfile(filename)
for filename
in map(joiner, os.listdir(in_directory))
)
>>> count_files("/usr/lib")
1797
>>> len(os.listdir("/usr/lib"))
2049
def directory(path,extension):
list_dir = []
list_dir = os.listdir(path)
count = 0
for file in list_dir:
if file.endswith(extension): # eg: '.txt'
count += 1
return count
简单的一个:
import os
number_of_files = len(os.listdir(directory))
print(number_of_files)
我这样做了,这返回了文件夹(Attack_Data)中的文件数量…这很好。
import os
def fcount(path):
#Counts the number of files in a directory
count = 0
for f in os.listdir(path):
if os.path.isfile(os.path.join(path, f)):
count += 1
return count
path = r"C:\Users\EE EKORO\Desktop\Attack_Data" #Read files in folder
print (fcount(path))