在一个使用AJAX调用的web应用程序中,我需要提交一个请求,但在URL的末尾添加一个参数,例如:
原始URL:
http://server/myapp.php?id=10
导致的网址:
http://server/myapp.php?id=10&enabled=true
寻找一个JavaScript函数,该函数解析URL并查看每个参数,然后添加新参数或更新已经存在的值。
在一个使用AJAX调用的web应用程序中,我需要提交一个请求,但在URL的末尾添加一个参数,例如:
原始URL:
http://server/myapp.php?id=10
导致的网址:
http://server/myapp.php?id=10&enabled=true
寻找一个JavaScript函数,该函数解析URL并查看每个参数,然后添加新参数或更新已经存在的值。
当前回答
这将在所有现代浏览器中工作。
function insertParam(key,value) {
if (history.pushState) {
var newurl = window.location.protocol + "//" + window.location.host + window.location.pathname + '?' +key+'='+value;
window.history.pushState({path:newurl},'',newurl);
}
}
其他回答
/** * Add a URL parameter * @param {string} url * @param {string} param the key to set * @param {string} value */ var addParam = function(url, param, value) { param = encodeURIComponent(param); var a = document.createElement('a'); param += (value ? "=" + encodeURIComponent(value) : ""); a.href = url; a.search += (a.search ? "&" : "") + param; return a.href; } /** * Add a URL parameter (or modify if already exists) * @param {string} url * @param {string} param the key to set * @param {string} value */ var addOrReplaceParam = function(url, param, value) { param = encodeURIComponent(param); var r = "([&?]|&)" + param + "\\b(?:=(?:[^&#]*))*"; var a = document.createElement('a'); var regex = new RegExp(r); var str = param + (value ? "=" + encodeURIComponent(value) : ""); a.href = url; var q = a.search.replace(regex, "$1"+str); if (q === a.search) { a.search += (a.search ? "&" : "") + str; } else { a.search = q; } return a.href; } url = "http://www.example.com#hashme"; newurl = addParam(url, "ciao", "1"); alert(newurl);
请注意,参数应该在被追加到查询字符串之前进行编码。
http://jsfiddle.net/48z7z4kx/
var MyApp = new Class();
MyApp.extend({
utility: {
queryStringHelper: function (url) {
var originalUrl = url;
var newUrl = url;
var finalUrl;
var insertParam = function (key, value) {
key = escape(key);
value = escape(value);
//The previous post had the substr strat from 1 in stead of 0!!!
var kvp = newUrl.substr(0).split('&');
var i = kvp.length;
var x;
while (i--) {
x = kvp[i].split('=');
if (x[0] == key) {
x[1] = value;
kvp[i] = x.join('=');
break;
}
}
if (i < 0) {
kvp[kvp.length] = [key, value].join('=');
}
finalUrl = kvp.join('&');
return finalUrl;
};
this.insertParameterToQueryString = insertParam;
this.insertParams = function (keyValues) {
for (var keyValue in keyValues[0]) {
var key = keyValue;
var value = keyValues[0][keyValue];
newUrl = insertParam(key, value);
}
return newUrl;
};
return this;
}
}
});
在URL类中有一个内置函数,你可以使用它来轻松处理查询字符串的键/值参数:
const url = new URL(window.location.href);
// url.searchParams has several function, we just use `set` function
// to set a value, if you just want to append without replacing value
// let use `append` function
url.searchParams.set('key', 'value');
console.log(url.search) // <== '?key=value'
// if window.location.href has already some qs params this `set` function
// modify or append key/value in it
有关searchParams函数的更多信息。
IE不支持URL,请检查兼容性
Vianney Bajart的答案是正确的;然而,URL只会工作,如果你有完整的URL端口,主机,路径和查询:
new URL('http://server/myapp.php?id=10&enabled=true')
URLSearchParams只会在你只传递查询字符串时起作用:
new URLSearchParams('?id=10&enabled=true')
如果你有一个不完整或相对的URL,不关心的基础URL,你可以通过?获取查询字符串,然后像这样连接:
function setUrlParams(url, key, value) {
url = url.split('?');
usp = new URLSearchParams(url[1]);
usp.set(key, value);
url[1] = usp.toString();
return url.join('?');
}
let url = 'myapp.php?id=10';
url = setUrlParams(url, 'enabled', true); // url = 'myapp.php?id=10&enabled=true'
url = setUrlParams(url, 'id', 11); // url = 'myapp.php?id=11&enabled=true'
Internet Explorer浏览器不兼容。
这就是我在服务器端(如Node.js)添加或更新一些基本url参数时使用的方法。
CoffeScript:
### @method addUrlParam Adds parameter to a given url. If the parameter already exists in the url is being replaced. @param {string} url @param {string} key Parameter's key @param {string} value Parameter's value @returns {string} new url containing the parameter ### addUrlParam = (url, key, value) -> newParam = key+"="+value result = url.replace(new RegExp('(&|\\?)' + key + '=[^\&|#]*'), '$1' + newParam) if result is url result = if url.indexOf('?') != -1 then url.split('?')[0] + '?' + newParam + '&' + url.split('?')[1] else if url.indexOf('#') != -1 then url.split('#')[0] + '?' + newParam + '#' + url.split('#')[1] else url + '?' + newParam return result
JavaScript:
function addUrlParam(url, key, value) { var newParam = key+"="+value; var result = url.replace(new RegExp("(&|\\?)"+key+"=[^\&|#]*"), '$1' + newParam); if (result === url) { result = (url.indexOf("?") != -1 ? url.split("?")[0]+"?"+newParam+"&"+url.split("?")[1] : (url.indexOf("#") != -1 ? url.split("#")[0]+"?"+newParam+"#"+ url.split("#")[1] : url+'?'+newParam)); } return result; } var url = "http://www.example.com?foo=bar&ciao=3&doom=5#hashme"; result1.innerHTML = addUrlParam(url, "ciao", "1"); <p id="result1"></p>