在一个使用AJAX调用的web应用程序中,我需要提交一个请求,但在URL的末尾添加一个参数,例如:
原始URL:
http://server/myapp.php?id=10
导致的网址:
http://server/myapp.php?id=10&enabled=true
寻找一个JavaScript函数,该函数解析URL并查看每个参数,然后添加新参数或更新已经存在的值。
在一个使用AJAX调用的web应用程序中,我需要提交一个请求,但在URL的末尾添加一个参数,例如:
原始URL:
http://server/myapp.php?id=10
导致的网址:
http://server/myapp.php?id=10&enabled=true
寻找一个JavaScript函数,该函数解析URL并查看每个参数,然后添加新参数或更新已经存在的值。
当前回答
这将在所有现代浏览器中工作。
function insertParam(key,value) {
if (history.pushState) {
var newurl = window.location.protocol + "//" + window.location.host + window.location.pathname + '?' +key+'='+value;
window.history.pushState({path:newurl},'',newurl);
}
}
其他回答
我添加我的解决方案,因为它支持相对url除了绝对url。在其他方面,它与顶部的答案相同,后者也使用Web API。
/**
* updates a relative or absolute
* by setting the search query with
* the passed key and value.
*/
export const setQueryParam = (url, key, value) => {
const dummyBaseUrl = 'https://dummy-base-url.com';
const result = new URL(url, dummyBaseUrl);
result.searchParams.set(key, value);
return result.toString().replace(dummyBaseUrl, '');
};
还有人开玩笑说:
// some jest tests
describe('setQueryParams', () => {
it('sets param on relative url with base path', () => {
// act
const actual = setQueryParam(
'/', 'ref', 'some-value',
);
// assert
expect(actual).toEqual('/?ref=some-value');
});
it('sets param on relative url with no path', () => {
// act
const actual = setQueryParam(
'', 'ref', 'some-value',
);
// assert
expect(actual).toEqual('/?ref=some-value');
});
it('sets param on relative url with some path', () => {
// act
const actual = setQueryParam(
'/some-path', 'ref', 'some-value',
);
// assert
expect(actual).toEqual('/some-path?ref=some-value');
});
it('overwrites existing param', () => {
// act
const actual = setQueryParam(
'/?ref=prev-value', 'ref', 'some-value',
);
// assert
expect(actual).toEqual('/?ref=some-value');
});
it('sets param while another param exists', () => {
// act
const actual = setQueryParam(
'/?other-param=other-value', 'ref', 'some-value',
);
// assert
expect(actual).toEqual('/?other-param=other-value&ref=some-value');
});
it('honors existing base url', () => {
// act
const actual = setQueryParam(
'https://base.com', 'ref', 'some-value',
);
// assert
expect(actual).toEqual('https://base.com/?ref=some-value');
});
it('honors existing base url with some path', () => {
// act
const actual = setQueryParam(
'https://base.com/some-path', 'ref', 'some-value',
);
// assert
expect(actual).toEqual('https://base.com/some-path?ref=some-value');
});
});
你需要适应的基本实现是这样的:
function insertParam(key, value) {
key = encodeURIComponent(key);
value = encodeURIComponent(value);
// kvp looks like ['key1=value1', 'key2=value2', ...]
var kvp = document.location.search.substr(1).split('&');
let i=0;
for(; i<kvp.length; i++){
if (kvp[i].startsWith(key + '=')) {
let pair = kvp[i].split('=');
pair[1] = value;
kvp[i] = pair.join('=');
break;
}
}
if(i >= kvp.length){
kvp[kvp.length] = [key,value].join('=');
}
// can return this or...
let params = kvp.join('&');
// reload page with new params
document.location.search = params;
}
这大约是正则表达式或基于搜索的解决方案的两倍,但这完全取决于查询字符串的长度和任何匹配的索引
为了完成起见,我以慢速regex方法为基准(大约慢了150%)
function insertParam2(key,value)
{
key = encodeURIComponent(key); value = encodeURIComponent(value);
var s = document.location.search;
var kvp = key+"="+value;
var r = new RegExp("(&|\\?)"+key+"=[^\&]*");
s = s.replace(r,"$1"+kvp);
if(!RegExp.$1) {s += (s.length>0 ? '&' : '?') + kvp;};
//again, do what you will here
document.location.search = s;
}
/** * Add a URL parameter * @param {string} url * @param {string} param the key to set * @param {string} value */ var addParam = function(url, param, value) { param = encodeURIComponent(param); var a = document.createElement('a'); param += (value ? "=" + encodeURIComponent(value) : ""); a.href = url; a.search += (a.search ? "&" : "") + param; return a.href; } /** * Add a URL parameter (or modify if already exists) * @param {string} url * @param {string} param the key to set * @param {string} value */ var addOrReplaceParam = function(url, param, value) { param = encodeURIComponent(param); var r = "([&?]|&)" + param + "\\b(?:=(?:[^&#]*))*"; var a = document.createElement('a'); var regex = new RegExp(r); var str = param + (value ? "=" + encodeURIComponent(value) : ""); a.href = url; var q = a.search.replace(regex, "$1"+str); if (q === a.search) { a.search += (a.search ? "&" : "") + str; } else { a.search = q; } return a.href; } url = "http://www.example.com#hashme"; newurl = addParam(url, "ciao", "1"); alert(newurl);
请注意,参数应该在被追加到查询字符串之前进行编码。
http://jsfiddle.net/48z7z4kx/
试一试 正则表达式,如此之慢,因此:
var SetParamUrl = function(_k, _v) {// replace and add new parameters
let arrParams = window.location.search !== '' ? decodeURIComponent(window.location.search.substr(1)).split('&').map(_v => _v.split('=')) : Array();
let index = arrParams.findIndex((_v) => _v[0] === _k);
index = index !== -1 ? index : arrParams.length;
_v === null ? arrParams = arrParams.filter((_v, _i) => _i != index) : arrParams[index] = [_k, _v];
let _search = encodeURIComponent(arrParams.map(_v => _v.join('=')).join('&'));
let newurl = window.location.protocol + "//" + window.location.host + window.location.pathname + (arrParams.length > 0 ? '?' + _search : '');
// window.location = newurl; //reload
if (history.pushState) { // without reload
window.history.pushState({path:newurl}, null, newurl);
}
};
var GetParamUrl = function(_k) {// get parameter by key
let sPageURL = decodeURIComponent(window.location.search.substr(1)),
sURLVariables = sPageURL.split('&').map(_v => _v.split('='));
let _result = sURLVariables.find(_v => _v[0] === _k);
return _result[1];
};
例子:
// https://some.com/some_path
GetParamUrl('cat');//undefined
SetParamUrl('cat', "strData");// https://some.com/some_path?cat=strData
GetParamUrl('cat');//strData
SetParamUrl('sotr', "strDataSort");// https://some.com/some_path?cat=strData&sotr=strDataSort
GetParamUrl('sotr');//strDataSort
SetParamUrl('cat', "strDataTwo");// https://some.com/some_path?cat=strDataTwo&sotr=strDataSort
GetParamUrl('cat');//strDataTwo
//remove param
SetParamUrl('cat', null);// https://some.com/some_path?sotr=strDataSort
这是我自己的尝试,但我将使用annakata的答案,因为它看起来更清晰:
function AddUrlParameter(sourceUrl, parameterName, parameterValue, replaceDuplicates)
{
if ((sourceUrl == null) || (sourceUrl.length == 0)) sourceUrl = document.location.href;
var urlParts = sourceUrl.split("?");
var newQueryString = "";
if (urlParts.length > 1)
{
var parameters = urlParts[1].split("&");
for (var i=0; (i < parameters.length); i++)
{
var parameterParts = parameters[i].split("=");
if (!(replaceDuplicates && parameterParts[0] == parameterName))
{
if (newQueryString == "")
newQueryString = "?";
else
newQueryString += "&";
newQueryString += parameterParts[0] + "=" + parameterParts[1];
}
}
}
if (newQueryString == "")
newQueryString = "?";
else
newQueryString += "&";
newQueryString += parameterName + "=" + parameterValue;
return urlParts[0] + newQueryString;
}
另外,我从stackoverflow上的另一篇文章中找到了这个jQuery插件,如果你需要更多的灵活性,你可以使用它: http://plugins.jquery.com/project/query-object
我认为代码应该是(还没有测试):
return $.query.parse(sourceUrl).set(parameterName, parameterValue).toString();