在一个使用AJAX调用的web应用程序中，我需要提交一个请求，但在URL的末尾添加一个参数，例如:
原始URL:
http://server/myapp.php?id=10
导致的网址:
http://server/myapp.php?id=10&enabled=true
寻找一个JavaScript函数，该函数解析URL并查看每个参数，然后添加新参数或更新已经存在的值。
当前回答
这是一个非常简化的版本，为了可读性和更少的代码行而不是微观优化的性能(我们说的是几毫秒的差异，实际上……由于它的性质(操作当前文档的位置)，这将很可能在一个页面上运行一次)。
/**
* Add a URL parameter (or changing it if it already exists)
* @param {search} string this is typically document.location.search
* @param {key} string the key to set
* @param {val} string value
*/
var addUrlParam = function(search, key, val){
var newParam = key + '=' + val,
params = '?' + newParam;
// If the "search" string exists, then build params from it
if (search) {
// Try to replace an existance instance
params = search.replace(new RegExp('([?&])' + key + '[^&]*'), '$1' + newParam);
// If nothing was replaced, then add the new param to the end
if (params === search) {
params += '&' + newParam;
}
}
return params;
};
然后你可以这样使用:
document.location.pathname + addUrlParam(document.location.search, 'foo', 'bar');
其他回答
以下功能将帮助您添加，更新和删除参数或从URL。
/ / example1and
var myURL = '/search';
myURL = updateUrl(myURL,'location','california');
console.log('added location...' + myURL);
//added location.../search?location=california
myURL = updateUrl(myURL,'location','new york');
console.log('updated location...' + myURL);
//updated location.../search?location=new%20york
myURL = updateUrl(myURL,'location');
console.log('removed location...' + myURL);
//removed location.../search
/ / example2
var myURL = '/search?category=mobile';
myURL = updateUrl(myURL,'location','california');
console.log('added location...' + myURL);
//added location.../search?category=mobile&location=california
myURL = updateUrl(myURL,'location','new york');
console.log('updated location...' + myURL);
//updated location.../search?category=mobile&location=new%20york
myURL = updateUrl(myURL,'location');
console.log('removed location...' + myURL);
//removed location.../search?category=mobile
/ /青年们
var myURL = '/search?location=texas';
myURL = updateUrl(myURL,'location','california');
console.log('added location...' + myURL);
//added location.../search?location=california
myURL = updateUrl(myURL,'location','new york');
console.log('updated location...' + myURL);
//updated location.../search?location=new%20york
myURL = updateUrl(myURL,'location');
console.log('removed location...' + myURL);
//removed location.../search
/ / example4
var myURL = '/search?category=mobile&location=texas';
myURL = updateUrl(myURL,'location','california');
console.log('added location...' + myURL);
//added location.../search?category=mobile&location=california
myURL = updateUrl(myURL,'location','new york');
console.log('updated location...' + myURL);
//updated location.../search?category=mobile&location=new%20york
myURL = updateUrl(myURL,'location');
console.log('removed location...' + myURL);
//removed location.../search?category=mobile
/ / example5
var myURL = 'https://example.com/search?location=texas#fragment';
myURL = updateUrl(myURL,'location','california');
console.log('added location...' + myURL);
//added location.../search?location=california#fragment
myURL = updateUrl(myURL,'location','new york');
console.log('updated location...' + myURL);
//updated location.../search?location=new%20york#fragment
myURL = updateUrl(myURL,'location');
console.log('removed location...' + myURL);
//removed location.../search#fragment
这是函数。
function updateUrl(url,key,value){
if(value!==undefined){
value = encodeURI(value);
}
var hashIndex = url.indexOf("#")|0;
if (hashIndex === -1) hashIndex = url.length|0;
var urls = url.substring(0, hashIndex).split('?');
var baseUrl = urls[0];
var parameters = '';
var outPara = {};
if(urls.length>1){
parameters = urls[1];
}
if(parameters!==''){
parameters = parameters.split('&');
for(k in parameters){
var keyVal = parameters[k];
keyVal = keyVal.split('=');
var ekey = keyVal[0];
var evalue = '';
if(keyVal.length>1){
evalue = keyVal[1];
}
outPara[ekey] = evalue;
}
}
if(value!==undefined){
outPara[key] = value;
}else{
delete outPara[key];
}
parameters = [];
for(var k in outPara){
parameters.push(k + '=' + outPara[k]);
}
var finalUrl = baseUrl;
if(parameters.length>0){
finalUrl += '?' + parameters.join('&');
}
return finalUrl + url.substring(hashIndex);
}
我喜欢穆罕穆德·法提赫·耶尔达兹的回答，即使他没有回答整个问题。
在他回答的同一行中，我使用了这样的代码:
“它不控制参数的存在，也不改变现有的值。它把你的参数加到最后"
/** add a parameter at the end of the URL. Manage '?'/'&', but not the existing parameters.
* does escape the value (but not the key)
*/
function addParameterToURL(_url,_key,_value){
var param = _key+'='+escape(_value);
var sep = '&';
if (_url.indexOf('?') < 0) {
sep = '?';
} else {
var lastChar=_url.slice(-1);
if (lastChar == '&') sep='';
if (lastChar == '?') sep='';
}
_url += sep + param;
return _url;
}
测试者:
/*
function addParameterToURL_TESTER_sub(_url,key,value){
//log(_url);
log(addParameterToURL(_url,key,value));
}
function addParameterToURL_TESTER(){
log('-------------------');
var _url ='www.google.com';
addParameterToURL_TESTER_sub(_url,'key','value');
addParameterToURL_TESTER_sub(_url,'key','Text Value');
_url ='www.google.com?';
addParameterToURL_TESTER_sub(_url,'key','value');
_url ='www.google.com?A=B';
addParameterToURL_TESTER_sub(_url,'key','value');
_url ='www.google.com?A=B&';
addParameterToURL_TESTER_sub(_url,'key','value');
_url ='www.google.com?A=1&B=2';
addParameterToURL_TESTER_sub(_url,'key','value');
}//*/
/** * Add a URL parameter * @param {string} url * @param {string} param the key to set * @param {string} value */ var addParam = function(url, param, value) { param = encodeURIComponent(param); var a = document.createElement('a'); param += (value ? "=" + encodeURIComponent(value) : ""); a.href = url; a.search += (a.search ? "&" : "") + param; return a.href; } /** * Add a URL parameter (or modify if already exists) * @param {string} url * @param {string} param the key to set * @param {string} value */ var addOrReplaceParam = function(url, param, value) { param = encodeURIComponent(param); var r = "([&?]|&)" + param + "\\b(?:=(?:[^&#]*))*"; var a = document.createElement('a'); var regex = new RegExp(r); var str = param + (value ? "=" + encodeURIComponent(value) : ""); a.href = url; var q = a.search.replace(regex, "$1"+str); if (q === a.search) { a.search += (a.search ? "&" : "") + str; } else { a.search = q; } return a.href; } url = "http://www.example.com#hashme"; newurl = addParam(url, "ciao", "1"); alert(newurl);
请注意，参数应该在被追加到查询字符串之前进行编码。
http://jsfiddle.net/48z7z4kx/
加入@Vianney的回答https://stackoverflow.com/a/44160941/6609678
我们可以导入node中的内置URL模块，如下所示
const { URL } = require('url');
例子:
Terminal $ node
> const { URL } = require('url');
undefined
> let url = new URL('', 'http://localhost:1989/v3/orders');
undefined
> url.href
'http://localhost:1989/v3/orders'
> let fetchAll=true, timePeriod = 30, b2b=false;
undefined
> url.href
'http://localhost:1989/v3/orders'
> url.searchParams.append('fetchAll', fetchAll);
undefined
> url.searchParams.append('timePeriod', timePeriod);
undefined
> url.searchParams.append('b2b', b2b);
undefined
> url.href
'http://localhost:1989/v3/orders?fetchAll=true&timePeriod=30&b2b=false'
> url.toString()
'http://localhost:1989/v3/orders?fetchAll=true&timePeriod=30&b2b=false'
有用的链接:
https://developer.mozilla.org/en-US/docs/Web/API/URL https://developer.mozilla.org/en/docs/Web/API/URLSearchParams
有时我们看到?在URL结尾，我找到了一些解决方案，生成的结果为file.php?&foo=bar。我想出了我自己的解决方案，以完美地工作!
location.origin + location.pathname + location.search + (location.search=='' ? '?' : '&') + 'lang=ar'
注意:位置。origin不能在IE中工作，这里是它的修复。
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