我使用Java从用户获得一个字符串输入。我试着让输入的第一个字母大写。

我试了一下:

String name;

BufferedReader br = new InputStreamReader(System.in);

String s1 = name.charAt(0).toUppercase());

System.out.println(s1 + name.substring(1));

这导致了以下编译错误:

类型不匹配:不能从InputStreamReader转换为BufferedReader 不能在基本类型char上调用toUppercase()


当前回答

来自Ameen Mahheen的答案很好,但如果我们有一些双空格字符串,如“hello world”,那么sb.append得到IndexOutOfBounds异常。正确的做法是在这行之前测试,做:

private String capitalizer(String word){
        String[] words = word.split(" ");
        StringBuilder sb = new StringBuilder();
        if (words[0].length() > 0) {
            sb.append(Character.toUpperCase(words[0].charAt(0)) + words[0].subSequence(1, words[0].length()).toString().toLowerCase());
            for (int i = 1; i < words.length; i++) {
                sb.append(" ");
                if (words[i].length() > 0) sb.append(Character.toUpperCase(words[i].charAt(0)) + words[i].subSequence(1, words[i].length()).toString().toLowerCase());
            }
        }
        return  sb.toString();
    }

其他回答

字符串首字母大写的更短/更快的版本代码是:

String name  = "stackoverflow"; 
name = name.substring(0,1).toUpperCase() + name.substring(1).toLowerCase();

name的值为Stackoverflow

下面的解决方案将工作。

String A = "stackOverflow";
String ACaps = A.toUpperCase().charAt(0)+A.substring(1,A.length());
//Will print StackOverflow

你不能在原始字符上使用toUpperCase(),但你可以先将整个String变成大写,然后取第一个字符,然后像上面所示的那样追加到子字符串。

public static String capitalizer(final String texto) {

    // split words
    String[] palavras = texto.split(" ");
    StringBuilder sb = new StringBuilder();

    // list of word exceptions
    List<String> excessoes = new ArrayList<String>(Arrays.asList("de", "da", "das", "do", "dos", "na", "nas", "no", "nos", "a", "e", "o", "em", "com"));

    for (String palavra : palavras) {

        if (excessoes.contains(palavra.toLowerCase()))
            sb.append(palavra.toLowerCase()).append(" ");
        else
            sb.append(Character.toUpperCase(palavra.charAt(0))).append(palavra.substring(1).toLowerCase()).append(" ");
    }
    return sb.toString().trim();
}

你可以试试这个

/**
 * capitilizeFirst(null)  -> ""
 * capitilizeFirst("")    -> ""
 * capitilizeFirst("   ") -> ""
 * capitilizeFirst(" df") -> "Df"
 * capitilizeFirst("AS")  -> "As"
 *
 * @param str input string
 * @return String with the first letter capitalized
 */
public String capitilizeFirst(String str)
{
    // assumptions that input parameter is not null is legal, as we use this function in map chain
    Function<String, String> capFirst = (String s) -> {
        String result = ""; // <-- accumulator

        try { result += s.substring(0, 1).toUpperCase(); }
        catch (Throwable e) {}
        try { result += s.substring(1).toLowerCase(); }
        catch (Throwable e) {}

        return result;
    };

    return Optional.ofNullable(str)
            .map(String::trim)
            .map(capFirst)
            .orElse("");
}

您可以使用以下代码:

public static void main(String[] args) {

    capitalizeFirstLetter("java");
    capitalizeFirstLetter("java developer");
}

public static void capitalizeFirstLetter(String text) {

    StringBuilder str = new StringBuilder();

    String[] tokens = text.split("\\s");// Can be space,comma or hyphen

    for (String token : tokens) {
        str.append(Character.toUpperCase(token.charAt(0))).append(token.substring(1)).append(" ");
    }
    str.toString().trim(); // Trim trailing space

    System.out.println(str);

}