我使用Java从用户获得一个字符串输入。我试着让输入的第一个字母大写。

我试了一下:

String name;

BufferedReader br = new InputStreamReader(System.in);

String s1 = name.charAt(0).toUppercase());

System.out.println(s1 + name.substring(1));

这导致了以下编译错误:

类型不匹配:不能从InputStreamReader转换为BufferedReader 不能在基本类型char上调用toUppercase()


当前回答

其中一个答案的正确率是95%,但它在我的unitTest中失败了@Ameen Maheen的解决方案几乎完美。除了在输入被转换为String数组之前,您必须修剪输入。所以最完美的一个:

private String convertStringToName(String name) {
        name = name.trim();
        String[] words = name.split(" ");
        StringBuilder sb = new StringBuilder();
        if (words[0].length() > 0) {
            sb.append(Character.toUpperCase(words[0].charAt(0)) + words[0].subSequence(1, words[0].length()).toString().toLowerCase());
            for (int i = 1; i < words.length; i++) {
                sb.append(" ");
                sb.append(Character.toUpperCase(words[i].charAt(0)) + words[i].subSequence(1, words[i].length()).toString().toLowerCase());
            }
        }
        return sb.toString();
    }

其他回答

只是重做了Jorgesys代码,并添加了一些检查,因为很少有与字符串长度相关的情况。不要做空参考检查在我的情况下。

 public static String capitalizeFirstLetter(@NonNull String customText){
        int count = customText.length();
        if (count == 0) {
            return customText;
        }
        if (count == 1) {
            return customText.toUpperCase();
        }
        return customText.substring(0, 1).toUpperCase() + customText.substring(1).toLowerCase();
    }

为了避免异常(IndexOutOfBoundsException或NullPointerException当使用子字符串(0,1)为空或空字符串时),您可以使用regex ("^.") (自Java 9起):

    try(BufferedReader reader = new BufferedReader(new InputStreamReader(System.in))) {
        String name = reader.readLine();

        name = Pattern.compile("^.")    // regex for the first character of a string
                .matcher(name)
                .replaceFirst(matchResult -> matchResult.group().toUpperCase());

        System.out.println(name);
    } catch(IOException ignore) {}

下面的例子也将特殊字符后的单词大写,如[/-]

  public static String capitalize(String text) {
    char[] stringArray = text.trim().toCharArray();
    boolean wordStarted = false;
    for( int i = 0; i < stringArray.length; i++) {
      char ch = stringArray[i];
      if ((ch >= 'a' && ch <= 'z') || (ch >= 'A' && ch <= 'Z') || ch == '\'') {
        if( !wordStarted ) {
          stringArray[i] = Character.toUpperCase(stringArray[i]);
          wordStarted = true;
        } 
      } else {
        wordStarted = false;
      }
    }
    return new String(stringArray);
  }

Example:
capitalize("that's a beautiful/wonderful life we have.We really-do")

Output:
That's A Beautiful/Wonderful Life We Have.We Really-Do
String str1 = "hello";
str1.substring(0, 1).toUpperCase()+str1.substring(1);
String str = "java";
String cap = str.substring(0, 1).toUpperCase() + str.substring(1);
// cap = "Java"

用你的例子:

public static void main(String[] args) throws IOException {
    BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
    // Actually use the Reader
    String name = br.readLine();
    // Don't mistake String object with a Character object
    String s1 = name.substring(0, 1).toUpperCase();
    String nameCapitalized = s1 + name.substring(1);
    System.out.println(nameCapitalized);
}