我使用Java从用户获得一个字符串输入。我试着让输入的第一个字母大写。
我试了一下:
String name;
BufferedReader br = new InputStreamReader(System.in);
String s1 = name.charAt(0).toUppercase());
System.out.println(s1 + name.substring(1));
这导致了以下编译错误:
类型不匹配:不能从InputStreamReader转换为BufferedReader 不能在基本类型char上调用toUppercase()
当前回答
String s = "first second third fourth";
int j = 0;
for (int i = 0; i < s.length(); i++) {
if ((s.substring(j, i).endsWith(" "))) {
String s2 = s.substring(j, i);
System.out.println(Character.toUpperCase(s.charAt(j))+s2.substring(1));
j = i;
}
}
System.out.println(Character.toUpperCase(s.charAt(j))+s.substring(j+1));
其他回答
public static String capitalizer(final String texto) {
// split words
String[] palavras = texto.split(" ");
StringBuilder sb = new StringBuilder();
// list of word exceptions
List<String> excessoes = new ArrayList<String>(Arrays.asList("de", "da", "das", "do", "dos", "na", "nas", "no", "nos", "a", "e", "o", "em", "com"));
for (String palavra : palavras) {
if (excessoes.contains(palavra.toLowerCase()))
sb.append(palavra.toLowerCase()).append(" ");
else
sb.append(Character.toUpperCase(palavra.charAt(0))).append(palavra.substring(1).toLowerCase()).append(" ");
}
return sb.toString().trim();
}
它的效率是101%
public class UpperCase {
public static void main(String [] args) {
String name;
System.out.print("INPUT: ");
Scanner scan = new Scanner(System.in);
name = scan.next();
String upperCase = name.substring(0, 1).toUpperCase() + name.substring(1);
System.out.println("OUTPUT: " + upperCase);
}
}
在Android Studio中
将此依赖项添加到构建中。gradle(模块:app)
dependencies {
...
compile 'org.apache.commons:commons-lang3:3.1'
...
}
现在你可以使用
String string = "STRING WITH ALL CAPPS AND SPACES";
string = string.toLowerCase(); // Make all lowercase if you have caps
someTextView.setText(WordUtils.capitalize(string));
一种方法。
String input = "someТекст$T%$4čřЭ"; //Enter your text.
if (input == null || input.isEmpty()) {
return "";
}
char [] chars = input.toCharArray();
chars[0] = chars[0].toUpperCase();
String res = new String(chars);
return res;
此方法的缺点是，如果inputString很长，则将有三个这样长度的对象。和你一样
String s1 = input.substring(1).toUpperCase();
String s2 = input.substring(1, lenght);
String res = s1 + s2;
甚至
//check if not null.
StringBuilder buf = new StringBuilder(input);
char ch = buf.getCharAt(0).toUpperCase();
buf.setCharAt(0, ch);
return buf.toString();
那些谁搜索首字母大写的名字在这里..
public static String capitaliseName(String name) {
String collect[] = name.split(" ");
String returnName = "";
for (int i = 0; i < collect.length; i++) {
collect[i] = collect[i].trim().toLowerCase();
if (collect[i].isEmpty() == false) {
returnName = returnName + collect[i].substring(0, 1).toUpperCase() + collect[i].substring(1) + " ";
}
}
return returnName.trim();
}
usase: capitaliseName(“saurav khan”); 输出:Saurav Khan
