一个简单的选择是使用SciTE (http://www.scintilla.org/SciTEDownload.html)这样的编辑器编辑java代码，它允许您对文本进行WRAP，以便容易地查看和编辑长字符串。如果你需要转义字符，你只需输入它们。通过关闭“换行”选项，您可以检查字符串是否仍然是一个很长的单行字符串。当然，如果不是，编译器也会告诉你。

Eclipse或NetBeans是否支持编辑器中的文本包装，我不知道，因为它们有太多的选项。但如果没有，这将是一个很好的补充。

我建议使用ThomasP所建议的实用程序，然后将其链接到构建过程中。仍然存在一个外部文件以包含文本，但在运行时不读取该文件。 工作流程如下:

构建一个“文本文件到java代码”实用程序并检查到版本控制 在每次构建时，针对资源文件运行实用程序以创建修改后的java源 Java源代码包含类似于 类TextBlock{…后面跟着一个从资源文件自动生成的静态字符串 用剩下的代码构建生成的java文件

从问题中还不完全清楚作者是否有兴趣处理某种需要有一些动态值的格式化大字符串，但如果是这种情况，像StringTemplate (http://www.stringtemplate.org/)这样的模板引擎可能非常有用。

下面是一个使用StringTemplate的简单代码示例。实际的模板("Hello， < name >")可以从外部纯文本文件加载。模板中的所有缩进都将被保留，不需要转义。

import org.stringtemplate.v4.*;
 
public class Hello {
    public static void main(String[] args) {
        ST hello = new ST("Hello, <name>");
        hello.add("name", "World");
        System.out.println(hello.render());
    }
}

附注:为了可读性和本地化目的，从源代码中删除大块文本总是一个好主意。

注意:这个答案适用于Java 14及以上版本。

Java 15引入了文本块(多行文字)。详情请看这个答案。

听起来像是要做一个多行文字，这在Java中是不存在的。

你最好的选择是用+ d组合的字符串。人们提到的一些其他选项(StringBuilder, String。format, String.join)只有当你从一个字符串数组开始时才更可取。

考虑一下:

String s = "It was the best of times, it was the worst of times,\n"
         + "it was the age of wisdom, it was the age of foolishness,\n"
         + "it was the epoch of belief, it was the epoch of incredulity,\n"
         + "it was the season of Light, it was the season of Darkness,\n"
         + "it was the spring of hope, it was the winter of despair,\n"
         + "we had everything before us, we had nothing before us";

与StringBuilder:

String s = new StringBuilder()
           .append("It was the best of times, it was the worst of times,\n")
           .append("it was the age of wisdom, it was the age of foolishness,\n")
           .append("it was the epoch of belief, it was the epoch of incredulity,\n")
           .append("it was the season of Light, it was the season of Darkness,\n")
           .append("it was the spring of hope, it was the winter of despair,\n")
           .append("we had everything before us, we had nothing before us")
           .toString();

与String.format ():

String s = String.format("%s\n%s\n%s\n%s\n%s\n%s"
         , "It was the best of times, it was the worst of times,"
         , "it was the age of wisdom, it was the age of foolishness,"
         , "it was the epoch of belief, it was the epoch of incredulity,"
         , "it was the season of Light, it was the season of Darkness,"
         , "it was the spring of hope, it was the winter of despair,"
         , "we had everything before us, we had nothing before us"
);

相对于Java8 String.join():

String s = String.join("\n"
         , "It was the best of times, it was the worst of times,"
         , "it was the age of wisdom, it was the age of foolishness,"
         , "it was the epoch of belief, it was the epoch of incredulity,"
         , "it was the season of Light, it was the season of Darkness,"
         , "it was the spring of hope, it was the winter of despair,"
         , "we had everything before us, we had nothing before us"
);

如果您想在特定的系统中使用换行符，您要么需要使用system . lineseparator()，要么可以在String.format中使用%n。

另一种选择是将资源放在文本文件中，只读取该文件的内容。对于非常大的字符串，这将是可取的，以避免不必要地膨胀您的类文件。

看到所有的答案，我认为没有人提到比在java的新版本，你可以这样做:

String s = """
    This
    is 
    a
    multiline
    string
    """;
System.out.println(s);

这是它打印的内容:

This
is
a
multiline
string

一个非常高效且与平台无关的解决方案是使用系统属性的行分隔符和StringBuilder类来构建字符串:

String separator = System.getProperty("line.separator");
String[] lines = {"Line 1", "Line 2" /*, ... */};

StringBuilder builder = new StringBuilder(lines[0]);
for (int i = 1; i < lines.length(); i++) {
    builder.append(separator).append(lines[i]);
}
String multiLine = builder.toString();