我正在尝试做一些基于句子中字符数量的动态规划。英语字母表中哪个字母在屏幕上占像素最多?
当前回答
根据您的平台，可能有一种方法从字符串或DrawText()函数中“getWidth”，以某种方式使用width属性。
我会做一个简单的算法时间，利用所需的字体，然后通过alfabet运行，并将其存储在一个小配置或只是计算它在初始化作为一个循环从a到Z并不难。
其他回答
接下来是Ned Batchelder非常实用的回答，因为我来这里是想知道数字:
0000000000000000000000000000000000000000
1111111111111111111111111111111111111111
2222222222222222222222222222222222222222
3333333333333333333333333333333333333333
4444444444444444444444444444444444444444
5555555555555555555555555555555555555555
6666666666666666666666666666666666666666
7777777777777777777777777777777777777777
8888888888888888888888888888888888888888
9999999999999999999999999999999999999999
嗯，让我想想:
啊
咔嚓咔嚓
cccccccccccccccccccccccccccccccccccccccc
DDDD
eeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
ffffffffffffffffffffffffffffffffffffffff
gggggggggggggggggggggggggggggggggggggggg
hhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh
iiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii
jjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjj
kkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk
唔��
mmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm
nnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnn
呜
购买力平价
qqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqq
rrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrr
ssssssssssssssssssssssssssssssssssssssss
啧��
uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu
vvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv
wwwwww
xxxx
yyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy
zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz
啊
BBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB
CCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC
DDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDD
EEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE
FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF
GGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGG
HHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHH
IIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIII
JJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJ
KKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKK
LLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLL
MMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMM
NNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNN
啊
公私合营
QQQQQQQQQQQQQQQQQQQQQQQQQQQQQQQQQQQQQQQQ
RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR
SSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS
TTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTT
UUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUU
VVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVV
www
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY
ZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ
W获胜。
当然，这是一个愚蠢的经验实验。哪个字母最宽没有唯一的答案。这取决于字体。所以你必须做一个类似的经验实验来找出你所处环境的答案。但事实是，大多数字体遵循相同的惯例，大写W将是最宽的。
主旨与这些字符宽度的比率形式(W = 100)在这里捕获使用特定的示例字体:
https://gist.github.com/imaurer/d330e68e70180c985b380f25e195b90c
那么程序化的解决方案呢?
var capsIndex = 65; var smallIndex = 97 var div = document.createElement('div'); div.style.float = 'left'; document.body.appendChild(div); var highestWidth = 0; var elem; for(var i = capsIndex; i < capsIndex + 26; i++) { div.innerText = String.fromCharCode(i); var computedWidth = window.getComputedStyle(div, null).getPropertyValue("width"); if(highestWidth < parseFloat(computedWidth)) { highestWidth = parseFloat(computedWidth); elem = String.fromCharCode(i); } } for(var i = smallIndex; i < smallIndex + 26; i++) { div.innerText = String.fromCharCode(i); var computedWidth = window.getComputedStyle(div, null).getPropertyValue("width"); if(highestWidth < parseFloat(computedWidth)) { highestWidth = parseFloat(computedWidth); elem = String.fromCharCode(i); } } div.innerHTML = '<b>' + elem + '</b>' + ' won';
Alex Michael在他的博客上发布了一个计算字体宽度的解决方案，有点像xxx发布的解决方案(有趣的是，他在这里链接了我)。
简介:
对于Helvetica，前三个字母是:M(2493像素)，W(2414像素)和B(1909像素)。 对于他的Mac附带的一组字体，结果大致相同:M(2217.51±945.19)，W(2139.06±945.29)和B(1841.38±685.26)。
原文:http://alexmic.net/letter-pixel-count/
代码:
# -*- coding: utf-8 -*-
from __future__ import division
import os
from collections import defaultdict
from math import sqrt
from PIL import Image, ImageDraw, ImageFont
# Make a lowercase + uppercase alphabet.
alphabet = 'abcdefghijklmnopqrstuvwxyz'
alphabet += ''.join(map(str.upper, alphabet))
def draw_letter(letter, font, save=True):
img = Image.new('RGB', (100, 100), 'white')
draw = ImageDraw.Draw(img)
draw.text((0,0), letter, font=font, fill='#000000')
if save:
img.save("imgs/{}.png".format(letter), 'PNG')
return img
def count_black_pixels(img):
pixels = list(img.getdata())
return len(filter(lambda rgb: sum(rgb) == 0, pixels))
def available_fonts():
fontdir = '/Users/alex/Desktop/English'
for root, dirs, filenames in os.walk(fontdir):
for name in filenames:
path = os.path.join(root, name)
try:
yield ImageFont.truetype(path, 100)
except IOError:
pass
def letter_statistics(counts):
for letter, counts in sorted(counts.iteritems()):
n = len(counts)
mean = sum(counts) / n
sd = sqrt(sum((x - mean) ** 2 for x in counts) / n)
yield letter, mean, sd
def main():
counts = defaultdict(list)
for letter in alphabet:
for font in available_fonts():
img = draw_letter(letter, font, save=False)
count = count_black_pixels(img)
counts[letter].append(count)
for letter, mean, sd in letter_statistics(counts):
print u"{0}: {1:.2f} ± {2:.2f}".format(letter, mean, sd)
if __name__ == '__main__':
main()
这取决于字体。我会用你最熟悉的编程语言创建一个小程序，把字母表中的每个字母画成n乘以m的位图。用白色初始化每个像素。然后，在你画完每个字母后，数一数白色像素的数量，并保存这个数字。你找到的最大的数字就是你要找的数字。
编辑:如果你实际上只是对哪个占据了最大的矩形感兴趣(但看起来你真的是在追求它，而不是像素)，你可以使用各种API调用来找到大小，但这取决于你的编程语言。例如，在Java中，您将使用FontMetrics类。
