英语字母表中哪个字母占像素最多?

我正在尝试做一些基于句子中字符数量的动态规划。英语字母表中哪个字母在屏幕上占像素最多?

当前回答

我知道公认的答案是W, W代表胜利。

但是，在本例中，W也表示宽度。案例研究使用了一个简单的宽度测试来检查像素，但它只是宽度，而不是总像素数。作为一个简单的反例，公认的答案假设O和Q占用相同数量的像素，但它们只占用相同数量的空间。

因此，W占的空间最大。但是，这是所有的像素，它被吹捧吗?

让我们来看看一些经验数据。我从下面的B, M和w中创建了imgur图像，然后分析了它们的像素数(见下文)，结果如下:

B: 114像素

M: 150像素

女:157像素

以下是我如何将它们放入画布并分析图像中的原始像素数据。

2017-11-17 07:37:56

其他回答

Alex Michael在他的博客上发布了一个计算字体宽度的解决方案，有点像xxx发布的解决方案(有趣的是，他在这里链接了我)。

简介:

对于Helvetica，前三个字母是:M(2493像素)，W(2414像素)和B(1909像素)。对于他的Mac附带的一组字体，结果大致相同:M(2217.51±945.19)，W(2139.06±945.29)和B(1841.38±685.26)。

原文:http://alexmic.net/letter-pixel-count/

代码:

# -*- coding: utf-8 -*-
from __future__ import division
import os
from collections import defaultdict
from math import sqrt
from PIL import Image, ImageDraw, ImageFont


# Make a lowercase + uppercase alphabet.
alphabet = 'abcdefghijklmnopqrstuvwxyz'
alphabet += ''.join(map(str.upper, alphabet))


def draw_letter(letter, font, save=True):
    img = Image.new('RGB', (100, 100), 'white')

    draw = ImageDraw.Draw(img)
    draw.text((0,0), letter, font=font, fill='#000000')

    if save:
        img.save("imgs/{}.png".format(letter), 'PNG')

    return img


def count_black_pixels(img):
    pixels = list(img.getdata())
    return len(filter(lambda rgb: sum(rgb) == 0, pixels))


def available_fonts():
    fontdir = '/Users/alex/Desktop/English'
    for root, dirs, filenames in os.walk(fontdir):
        for name in filenames:
            path = os.path.join(root, name)
            try:
                yield ImageFont.truetype(path, 100)
            except IOError:
                pass


def letter_statistics(counts):
    for letter, counts in sorted(counts.iteritems()):
        n = len(counts)
        mean = sum(counts) / n
        sd = sqrt(sum((x - mean) ** 2 for x in counts) / n)
        yield letter, mean, sd


def main():
    counts = defaultdict(list)

    for letter in alphabet:
        for font in available_fonts():
            img = draw_letter(letter, font, save=False)
            count = count_black_pixels(img)
            counts[letter].append(count)

        for letter, mean, sd in letter_statistics(counts):
            print u"{0}: {1:.2f} ± {2:.2f}".format(letter, mean, sd)


    if __name__ == '__main__':
        main()

2014-07-08 11:07:05

嗯，让我想想:

啊

咔嚓咔嚓

cccccccccccccccccccccccccccccccccccccccc

DDDD

eeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

ffffffffffffffffffffffffffffffffffffffff

gggggggggggggggggggggggggggggggggggggggg

hhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh

iiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii

jjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjj

kkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk

唔��

mmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm

nnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnn

呜

购买力平价

qqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqq

rrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrr

ssssssssssssssssssssssssssssssssssssssss

啧��

uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu

vvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv

wwwwww

xxxx

yyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy

zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz

啊

BBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB

CCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC

DDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDD

EEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE

FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF

GGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGGG

HHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHH

IIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIII

JJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJJ

KKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKKK

LLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLLL

MMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMM

NNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNNN

啊

公私合营

QQQQQQQQQQQQQQQQQQQQQQQQQQQQQQQQQQQQQQQQ

RRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR

SSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS

TTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTT

UUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUUU

VVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVVV

www

XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX

YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY

ZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ

W获胜。

当然，这是一个愚蠢的经验实验。哪个字母最宽没有唯一的答案。这取决于字体。所以你必须做一个类似的经验实验来找出你所处环境的答案。但事实是，大多数字体遵循相同的惯例，大写W将是最宽的。

主旨与这些字符宽度的比率形式(W = 100)在这里捕获使用特定的示例字体:

https://gist.github.com/imaurer/d330e68e70180c985b380f25e195b90c

2010-10-16 15:15:57

大写的“M”通常是最宽的。

2010-10-16 15:10:24

根据您的平台，可能有一种方法从字符串或DrawText()函数中“getWidth”，以某种方式使用width属性。

我会做一个简单的算法时间，利用所需的字体，然后通过alfabet运行，并将其存储在一个小配置或只是计算它在初始化作为一个循环从a到Z并不难。

2010-10-16 16:56:10