在Windows (Windows XP)批处理脚本中,我需要格式化当前日期和时间,以便以后在文件名等中使用。

这类似于堆栈溢出问题如何在批处理文件中添加日期,但也包含时间。

到目前为止,我有这个:

echo %DATE%
echo %TIME%
set datetimef=%date:~-4%_%date:~3,2%_%date:~0,2%__%time:~0,2%_%time:~3,2%_%time:~6,2%
echo %datetimef%

这使:

28/07/2009
 8:35:31.01
2009_07_28__ 8_36_01

是否有一种方法可以允许%TIME%中的个位数小时,以便我可以得到以下结果?

2009_07_28__08_36_01

当前回答

@ECHO OFF
: Sets the proper date and time stamp with 24Hr Time for log file naming
: convention ('YYYYMMDD_HHMMSS')

: Scrapes the characters out of their expected permissions in the date/time
: environment variables.

: Expects a date format of '____MM_DD_YYYY'
: Expects a time format of 'HH:MM:SS' or ' H:MM:SS'

SET HOUR=%time:~0,2%
SET dtStamp9=%date:~-4%%date:~4,2%%date:~7,2%_0%time:~1,1%%time:~3,2%%time:~6,2% 
SET dtStamp24=%date:~-4%%date:~4,2%%date:~7,2%_%time:~0,2%%time:~3,2%%time:~6,2%

if "%HOUR:~0,1%" == " " (SET dtStamp=%dtStamp9%) else (SET dtStamp=%dtStamp24%)

ECHO %dtStamp%

PAUSE

其他回答

我今天遇到了这个问题,并解决了它:

SET LOGTIME=%TIME: =0%

它用0代替空格,基本上是零垫小时。

经过一些快速搜索,我没有发现它是否需要命令扩展(仍然使用SETLOCAL DISABLEEXTENSIONS)。

set hourstr = %time:~0,2%
if "%time:~0,1%"==" " (set hourstr=0%time:~1,1%)
set datetimestr=%date:~0,4%%date:~5,2%%date:~8,2%-%hourstr%%time:~3,2%%time:~6,2%

以下可能不是一个直接的答案,但一个接近的答案?

set hour=%time:~0,2%
if "%hour:~0,1%" == " " set datetimef=%date:~-4%_%date:~3,2%_%date:~0,2%__0%time:~1,2%_%time:~3,2%_%time:~6,2%
else set datetimef=%date:~-4%_%date:~3,2%_%date:~0,2%__%time:~0,2%_%time:~3,2%_%time:~6,2%

至少这可能是鼓舞人心的。

下面是如何生成一个日志文件名(基于http://ss64.com/nt/syntax-getdate.html):)

@ECHO OFF
:: Check WMIC is available
WMIC.EXE Alias /? >NUL 2>&1 || GOTO s_error

:: Use WMIC to retrieve date and time
FOR /F "skip=1 tokens=1-6" %%G IN ('WMIC Path Win32_LocalTime Get Day^,Hour^,Minute^,Month^,Second^,Year /Format:table') DO (
   IF "%%~L"=="" goto s_done
      Set _yyyy=%%L
      Set _mm=00%%J
      Set _dd=00%%G
      Set _hour=00%%H
      SET _minute=00%%I
      SET _second=00%%K
)
:s_done

:: Pad digits with leading zeros
      Set _mm=%_mm:~-2%
      Set _dd=%_dd:~-2%
      Set _hour=%_hour:~-2%
      Set _minute=%_minute:~-2%
      Set _second=%_second:~-2%

Set logtimestamp=%_yyyy%-%_mm%-%_dd%_%_hour%_%_minute%_%_second%
goto make_dump

:s_error
echo WMIC is not available, using default log filename
Set logtimestamp=_

:make_dump
set FILENAME=database_dump_%logtimestamp%.sql
...

我尝试了公认的答案,效果很好。不幸的是,美国时间格式似乎是H:MM:SS.CS,前面缺少0导致上午10点之前的解析问题。为了克服这个障碍,并允许解析大多数世界时间格式,我提出了这个简单的例程,它似乎工作得相当好。

:ParseTime
rem The format of %%TIME%% is H:MM:SS.CS or (HH:MM:SS,CS) for example 0:01:23.45 or 23:59:59,99
FOR /F "tokens=1,2,3,4 delims=:.," %%a IN ("%1") DO SET /A "%2=(%%a * 360000) + (%%b * 6000) + (%%c * 100) + %%d"
GOTO :EOF

这个例程的好处是将时间字符串作为第一个参数传入,将希望包含时间(以厘秒为单位)的环境变量名称作为第二个参数传入。例如:

CALL :ParseTime %START_TIME% START_CS
CALL :ParseTime %TIME% END_CS
SET /A DURATION=%END_CS% - %START_CS%

克里斯(* *)