在Windows (Windows XP)批处理脚本中,我需要格式化当前日期和时间,以便以后在文件名等中使用。
这类似于堆栈溢出问题如何在批处理文件中添加日期,但也包含时间。
到目前为止,我有这个:
echo %DATE%
echo %TIME%
set datetimef=%date:~-4%_%date:~3,2%_%date:~0,2%__%time:~0,2%_%time:~3,2%_%time:~6,2%
echo %datetimef%
这使:
28/07/2009
8:35:31.01
2009_07_28__ 8_36_01
是否有一种方法可以允许%TIME%中的个位数小时,以便我可以得到以下结果?
2009_07_28__08_36_01
@ECHO OFF
: Sets the proper date and time stamp with 24Hr Time for log file naming
: convention ('YYYYMMDD_HHMMSS')
: Scrapes the characters out of their expected permissions in the date/time
: environment variables.
: Expects a date format of '____MM_DD_YYYY'
: Expects a time format of 'HH:MM:SS' or ' H:MM:SS'
SET HOUR=%time:~0,2%
SET dtStamp9=%date:~-4%%date:~4,2%%date:~7,2%_0%time:~1,1%%time:~3,2%%time:~6,2%
SET dtStamp24=%date:~-4%%date:~4,2%%date:~7,2%_%time:~0,2%%time:~3,2%%time:~6,2%
if "%HOUR:~0,1%" == " " (SET dtStamp=%dtStamp9%) else (SET dtStamp=%dtStamp24%)
ECHO %dtStamp%
PAUSE
我喜欢@The lorax上面的简短版本,
但对于其他语言设置可能略有不同。
例如,在德语设置中(使用自然日期格式:dd.mm.yyyy),月份查询必须从4,2更改为3,2:
@ECHO OFF
: Sets the proper date and time stamp with 24h time for log file naming convention i.e.
SET HOUR=%time:~0,2%
SET dtStamp9=%date:~-4%%date:~3,2%%date:~7,2%_0%time:~1,1%%time:~3,2%%time:~6,2%
SET dtStamp24=%date:~-4%%date:~3,2%%date:~7,2%_%time:~0,2%%time:~3,2%%time:~6,2%
if "%HOUR:~0,1%" == " " (SET dtStamp=%dtStamp9%) else (SET dtStamp=%dtStamp24%)
ECHO %dtStamp%
: Outputs= 20160727_081040
: (format: YYYYMMDD_HHmmss; e.g.: the date-output of this post timestamp)
PAUSE
REM Assumes UK style date format for date environment variable (DD/MM/YYYY).
REM Assumes times before 10:00:00 (10am) displayed padded with a space instead of a zero.
REM If first character of time is a space (less than 1) then set DATETIME to:
REM YYYY-MM-DD-0h-mm-ss
REM Otherwise, set DATETIME to:
REM YYYY-MM-DD-HH-mm-ss
REM Year, month, day format provides better filename sorting (otherwise, days grouped
REM together when sorted alphabetically).
IF "%time:~0,1%" LSS "1" (
SET DATETIME=%date:~6,4%-%date:~3,2%-%date:~0,2%-0%time:~1,1%-%time:~3,2%-%time:~6,2%
) ELSE (
SET DATETIME=%date:~6,4%-%date:~3,2%-%date:~0,2%-%time:~0,2%-%time:~3,2%-%time:~6,2%
)
ECHO %DATETIME%