这个脚本使用一个WMI接口，主要通过WMIC工具访问，这是Windows的一个组成部分，因为Windows XP专业版(家庭版也支持，但默认情况下不安装该工具)。该脚本还通过创建和调用WSH vbscript来访问WMI接口，并以与WMIC工具提供的相同格式写入控制台输出时间，从而实现了缺少WMIC工具的解决方案。

@ECHO OFF
REM Returns: RETURN
REM Modify:  RETURN, StdOut
REM Required - mandatory: none
REM Required - optionaly: format strings delimited by a space to format an output delimited by predefined delimiter
REM    YYYY = 4-digit year
REM      MM = 2-digit month
REM      DD = 2-digit day
REM      hh = 2-digit hour
REM      mm = 2-digit minute
REM      ss = 2-digit second
REM      ms = 3-digit millisecond

CALL :getTime %*
ECHO %RETURN%
GOTO :EOF


REM SUBROUTINE
REM Returns: RETURN
REM Modify:  RETURN
REM Required - mandatory: none
REM Required - optionaly: format strings delimited by a space to format an output delimited by predefined delimiter
REM    YYYY = 4-digit year
REM      MM = 2-digit month
REM      DD = 2-digit day
REM      hh = 2-digit hour
REM      mm = 2-digit minute
REM      ss = 2-digit second
REM      ms = 3-digit millisecond
:getTime
  SETLOCAL EnableDelayedExpansion
    SET DELIM=-
    WHERE /Q wmic.exe
    IF NOT ERRORLEVEL 1 FOR /F "usebackq skip=1 tokens=*" %%x IN (`wmic.exe os get LocalDateTime`) DO (SET DT=%%x & GOTO getTime_Parse)
    SET _TMP=%TEMP:"=%
    ECHO Wscript.StdOut.WriteLine (GetObject("winmgmts:root\cimv2:Win32_OperatingSystem=@").LocalDateTime)>"%_TMP%\get_time_local-helper.vbs"
    FOR /F "usebackq tokens=*" %%x IN (`cscript //B //NoLogo "%_TMP%\get_time_local-helper.vbs"`) DO (SET DT=%%x & GOTO getTime_Parse)
    :getTime_Parse
      SET _RET=
      IF "%1" EQU "" (
        SET _RET=%DT:~0,4%%DELIM%%DT:~4,2%%DELIM%%DT:~6,2%%DELIM%%DT:~8,2%%DELIM%%DT:~10,2%%DELIM%%DT:~12,2%%DELIM%%DT:~15,3%
      ) ELSE (
        REM Not recognized format strings are ignored during parsing - no error is reported.
       :getTime_ParseLoop
         SET _VAL=
         IF "%1" EQU "YYYY" SET _VAL=%DT:~0,4%
         IF "%1" EQU "MM"   SET _VAL=%DT:~4,2%
         IF "%1" EQU "DD"   SET _VAL=%DT:~6,2%
         IF "%1" EQU "hh"   SET _VAL=%DT:~8,2%
         IF "%1" EQU "mm"   SET _VAL=%DT:~10,2%
         IF "%1" EQU "ss"   SET _VAL=%DT:~12,2%
         IF "%1" EQU "ms"   SET _VAL=%DT:~15,3%
         IF DEFINED _VAL (
           IF DEFINED _RET (
             SET _RET=!_RET!%DELIM%!_VAL!
           ) ELSE (
             SET _RET=!_VAL!
           )
         )
         SHIFT
         IF "%1" NEQ "" GOTO getTime_ParseLoop
      )
  ENDLOCAL & SET RETURN=%_RET%
GOTO :EOF

我尝试了公认的答案，效果很好。不幸的是，美国时间格式似乎是H:MM:SS.CS，前面缺少0导致上午10点之前的解析问题。为了克服这个障碍，并允许解析大多数世界时间格式，我提出了这个简单的例程，它似乎工作得相当好。

:ParseTime
rem The format of %%TIME%% is H:MM:SS.CS or (HH:MM:SS,CS) for example 0:01:23.45 or 23:59:59,99
FOR /F "tokens=1,2,3,4 delims=:.," %%a IN ("%1") DO SET /A "%2=(%%a * 360000) + (%%b * 6000) + (%%c * 100) + %%d"
GOTO :EOF

这个例程的好处是将时间字符串作为第一个参数传入，将希望包含时间(以厘秒为单位)的环境变量名称作为第二个参数传入。例如:

CALL :ParseTime %START_TIME% START_CS
CALL :ParseTime %TIME% END_CS
SET /A DURATION=%END_CS% - %START_CS%

克里斯(* *)

我最终得到了这个脚本:

set hour=%time:~0,2%
if "%hour:~0,1%" == " " set hour=0%hour:~1,1%
echo hour=%hour%
set min=%time:~3,2%
if "%min:~0,1%" == " " set min=0%min:~1,1%
echo min=%min%
set secs=%time:~6,2%
if "%secs:~0,1%" == " " set secs=0%secs:~1,1%
echo secs=%secs%

set year=%date:~-4%
echo year=%year%

在WIN2008R2上，例如，我需要使您的'set month=%date:~3,2%'如下所示::否则，00表示month

set month=%date:~4,2%
if "%month:~0,1%" == " " set month=0%month:~1,1%
echo month=%month%
set day=%date:~0,2%
if "%day:~0,1%" == " " set day=0%day:~1,1%
echo day=%day%

set datetimef=%year%%month%%day%_%hour%%min%%secs%

echo datetimef=%datetimef%

我是这样做的:

REM Generate FileName from date and time in format YYYYMMTTHHMM

Time /T > Time.dat
set /P ftime= < Time.dat

set FileName=LogFile%date:~6%%date:~3,2%%date:~0,2%%ftime:~0,2%%ftime:~3,2%.log

echo %FileName%

LogFile201310170928.log

以下可能不是一个直接的答案，但一个接近的答案?

set hour=%time:~0,2%
if "%hour:~0,1%" == " " set datetimef=%date:~-4%_%date:~3,2%_%date:~0,2%__0%time:~1,2%_%time:~3,2%_%time:~6,2%
else set datetimef=%date:~-4%_%date:~3,2%_%date:~0,2%__%time:~0,2%_%time:~3,2%_%time:~6,2%

至少这可能是鼓舞人心的。

我今天遇到了这个问题，并解决了它:

SET LOGTIME=%TIME: =0%

它用0代替空格，基本上是零垫小时。

经过一些快速搜索，我没有发现它是否需要命令扩展(仍然使用SETLOCAL DISABLEEXTENSIONS)。