在Windows (Windows XP)批处理脚本中,我需要格式化当前日期和时间,以便以后在文件名等中使用。
这类似于堆栈溢出问题如何在批处理文件中添加日期,但也包含时间。
到目前为止,我有这个:
echo %DATE%
echo %TIME%
set datetimef=%date:~-4%_%date:~3,2%_%date:~0,2%__%time:~0,2%_%time:~3,2%_%time:~6,2%
echo %datetimef%
这使:
28/07/2009
8:35:31.01
2009_07_28__ 8_36_01
是否有一种方法可以允许%TIME%中的个位数小时,以便我可以得到以下结果?
2009_07_28__08_36_01
你可以用这些…
Parameters:
%date:~4,2% -- month
%date:~7,2% -- days
%date:~10,4% -- years
%time:~1,1% -- hours
%time:~3,2% -- minutes
%time:~6,2% -- seconds
%time:~9,2% -- mili-seconds
%date:~4,2%%date:~7,2%%date:~10,4% : MMDDYYYY
%date:~7,2%%date:~4,2%%date:~10,4% : DDMMYYYY
%date:~10,4%%date:~4,2%%date:~7,2% : YYYYMMDD
@ECHO OFF
: Sets the proper date and time stamp with 24Hr Time for log file naming
: convention ('YYYYMMDD_HHMMSS')
: Scrapes the characters out of their expected permissions in the date/time
: environment variables.
: Expects a date format of '____MM_DD_YYYY'
: Expects a time format of 'HH:MM:SS' or ' H:MM:SS'
SET HOUR=%time:~0,2%
SET dtStamp9=%date:~-4%%date:~4,2%%date:~7,2%_0%time:~1,1%%time:~3,2%%time:~6,2%
SET dtStamp24=%date:~-4%%date:~4,2%%date:~7,2%_%time:~0,2%%time:~3,2%%time:~6,2%
if "%HOUR:~0,1%" == " " (SET dtStamp=%dtStamp9%) else (SET dtStamp=%dtStamp24%)
ECHO %dtStamp%
PAUSE
以下可能不是一个直接的答案,但一个接近的答案?
set hour=%time:~0,2%
if "%hour:~0,1%" == " " set datetimef=%date:~-4%_%date:~3,2%_%date:~0,2%__0%time:~1,2%_%time:~3,2%_%time:~6,2%
else set datetimef=%date:~-4%_%date:~3,2%_%date:~0,2%__%time:~0,2%_%time:~3,2%_%time:~6,2%
至少这可能是鼓舞人心的。
这个批处理脚本将完全按照O.P.的要求执行(在Windows XP SP3上测试)。
我还使用了前面“jph”所描述的聪明的注册表技巧,我认为这是在任何新的或旧的Windows系统上获得100%一致的日期格式“yyyy_MM_dd”的最简单方法。对一个注册表值的更改是瞬时、临时和微不足道的;它只持续几毫秒,然后立即恢复。
双击此批处理文件进行即时演示,命令提示符窗口将弹出并显示您的时间戳. . . . .
::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
:: generates a custom formatted timestamp string using date and time.
:: run this batch file for an instant demo.
::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
@ECHO OFF
SETLOCAL & MODE CON:COLS=80 LINES=15 & COLOR 0A
:: --- CHANGE THE COMPUTER DATE FORMAT TEMPORARILY TO MY PREFERENCE "yyyy_MM_dd",
REG COPY "HKCU\Control Panel\International" "HKCU\Control Panel\International-Temp" /f 2>nul >nul
REG ADD "HKCU\Control Panel\International" /v sShortDate /d "yyyy_MM_dd" /f 2>nul >nul
SET MYDATE=%date%
:: --- REVERT COMPUTER DATE BACK TO SYSTEM PREFERENCE
REG COPY "HKCU\Control Panel\International-Temp" "HKCU\Control Panel\International" /f 2>nul >nul
REG DELETE "HKCU\Control Panel\International-Temp" /f 2>nul >nul
:: --- SPLIT THE TIME [HH:MM:SS.SS] TO THREE SEPARATE VARIABLES [HH] [MM] [SS.SS]
FOR /F "tokens=1-3 delims=:" %%A IN ('echo %time%') DO (
SET HOUR=%%A
SET MINUTES=%%B
SET SECONDS=%%C
)
:: --- CHOOSE ONE OF THESE TWO OPTIONS :
:: --- FOR 4 DIGIT SECONDS //REMOVES THE DOT FROM THE SECONDS VARIABLE [SS.SS]
:: SET SECONDS=%SECONDS:.=%
:: --- FOR 2 DIGIT SECONDS //GETS THE FIRST TWO DIGITS FROM THE SECONDS VARIABLE [SS.SS]
SET SECONDS=%SECONDS:~0,2%
:: --- FROM 12 AM TO 9 AM, THE HOUR VARIABLE WE EXTRACTED FROM %TIME% RETURNS A SINGLE DIGIT,
:: --- WE PREFIX A ZERO CHARACTER TO THOSE CASES, SO THAT OUR WANTED TIMESTAMP
:: --- ALWAYS GENERATES DOUBLE-DIGIT HOURS (24-HOUR CLOCK TIME SYSTEM).
IF %HOUR%==0 (SET HOUR=00)
IF %HOUR%==1 (SET HOUR=01)
IF %HOUR%==2 (SET HOUR=02)
IF %HOUR%==3 (SET HOUR=03)
IF %HOUR%==4 (SET HOUR=04)
IF %HOUR%==5 (SET HOUR=05)
IF %HOUR%==6 (SET HOUR=06)
IF %HOUR%==7 (SET HOUR=07)
IF %HOUR%==8 (SET HOUR=08)
IF %HOUR%==9 (SET HOUR=09)
:: --- GENERATE OUR WANTED TIMESTAMP
SET TIMESTAMP=%MYDATE%__%HOUR%_%MINUTES%_%SECONDS%
:: --- VIEW THE RESULT IN THE CONSOLE SCREEN
ECHO.
ECHO Generate a custom formatted timestamp string using date and time.
ECHO.
ECHO Your timestamp is: %TIMESTAMP%
ECHO.
ECHO.
ECHO Job is done. Press any key to exit . . .
PAUSE > NUL
EXIT
当我需要一个日期/时间字符串时,我通常这样做:
set dt=%DATE:~6,4%_%DATE:~3,2%_%DATE:~0,2%__%TIME:~0,2%_%TIME:~3,2%_%TIME:~6,2%
set dt=%dt: =0%
这是为德国日期/时间格式(dd.mm。yyyy hh: mm: ss)。基本上,我将子字符串连接起来,最后将所有空格替换为零。
结果字符串的格式为:yyyy_mm_dd__hh_mm_ss
子字符串如何工作的简短解释:
%VARIABLE:~num_chars_to_skip,num_chars_to_keep%
因此,要想从“29.03.2018”这样的日期中得到年份,可以使用:
%DATE:~6,4%
^-----skip 6 characters
^---keep 4 characters