在。net下使用c#和WPF(而不是Windows窗体或控制台),创建一个只能作为单个实例运行的应用程序的正确方法是什么?
我知道它与某种叫做互斥的神秘事物有关,我很少能找到有人费心停下来解释其中一个是什么。
代码还需要通知已经运行的实例,用户试图启动第二个实例,如果存在命令行参数,还可能传递任何命令行参数。
在。net下使用c#和WPF(而不是Windows窗体或控制台),创建一个只能作为单个实例运行的应用程序的正确方法是什么?
我知道它与某种叫做互斥的神秘事物有关,我很少能找到有人费心停下来解释其中一个是什么。
代码还需要通知已经运行的实例,用户试图启动第二个实例,如果存在命令行参数,还可能传递任何命令行参数。
当前回答
这段代码应该转到main方法。关于WPF中main方法的更多信息,请参阅这里。
[DllImport("user32.dll")]
private static extern Boolean ShowWindow(IntPtr hWnd, Int32 nCmdShow);
private const int SW_SHOWMAXIMIZED = 3;
static void Main()
{
Process currentProcess = Process.GetCurrentProcess();
var runningProcess = (from process in Process.GetProcesses()
where
process.Id != currentProcess.Id &&
process.ProcessName.Equals(
currentProcess.ProcessName,
StringComparison.Ordinal)
select process).FirstOrDefault();
if (runningProcess != null)
{
ShowWindow(runningProcess.MainWindowHandle, SW_SHOWMAXIMIZED);
return;
}
}
方法2
static void Main()
{
string procName = Process.GetCurrentProcess().ProcessName;
// get the list of all processes by that name
Process[] processes=Process.GetProcessesByName(procName);
if (processes.Length > 1)
{
MessageBox.Show(procName + " already running");
return;
}
else
{
// Application.Run(...);
}
}
注意:上述方法假设您的进程/应用程序有唯一的名称。因为它使用进程名来查找是否有现有的处理器。所以,如果你的应用程序有一个非常普通的名字(如:记事本),上述方法是行不通的。
其他回答
基于命名互斥的方法不是跨平台的,因为命名互斥在Mono中不是全局的。基于进程枚举的方法没有任何同步,可能会导致不正确的行为(例如,同时启动的多个进程可能都根据时间自行终止)。在控制台应用程序中不需要基于windows系统的方法。这个解决方案建立在Divin的答案之上,解决了所有这些问题:
using System;
using System.IO;
namespace TestCs
{
public class Program
{
// The app id must be unique. Generate a new guid for your application.
public static string AppId = "01234567-89ab-cdef-0123-456789abcdef";
// The stream is stored globally to ensure that it won't be disposed before the application terminates.
public static FileStream UniqueInstanceStream;
public static int Main(string[] args)
{
EnsureUniqueInstance();
// Your code here.
return 0;
}
private static void EnsureUniqueInstance()
{
// Note: If you want the check to be per-user, use Environment.SpecialFolder.ApplicationData instead.
string lockDir = Path.Combine(
Environment.GetFolderPath(Environment.SpecialFolder.CommonApplicationData),
"UniqueInstanceApps");
string lockPath = Path.Combine(lockDir, $"{AppId}.unique");
Directory.CreateDirectory(lockDir);
try
{
// Create the file with exclusive write access. If this fails, then another process is executing.
UniqueInstanceStream = File.Open(lockPath, FileMode.Create, FileAccess.Write, FileShare.None);
// Although only the line above should be sufficient, when debugging with a vshost on Visual Studio
// (that acts as a proxy), the IO exception isn't passed to the application before a Write is executed.
UniqueInstanceStream.Write(new byte[] { 0 }, 0, 1);
UniqueInstanceStream.Flush();
}
catch
{
throw new Exception("Another instance of the application is already running.");
}
}
}
}
我在这里找不到一个简单的解决方案,所以我希望有人会喜欢这个:
更新2018-09-20
把这段代码放在Program.cs中:
using System.Diagnostics;
static void Main()
{
Process thisProcess = Process.GetCurrentProcess();
Process[] allProcesses = Process.GetProcessesByName(thisProcess.ProcessName);
if (allProcesses.Length > 1)
{
// Don't put a MessageBox in here because the user could spam this MessageBox.
return;
}
// Optional code. If you don't want that someone runs your ".exe" with a different name:
string exeName = AppDomain.CurrentDomain.FriendlyName;
// in debug mode, don't forget that you don't use your normal .exe name.
// Debug uses the .vshost.exe.
if (exeName != "the name of your executable.exe")
{
// You can add a MessageBox here if you want.
// To point out to users that the name got changed and maybe what the name should be or something like that^^
MessageBox.Show("The executable name should be \"the name of your executable.exe\"",
"Wrong executable name", MessageBoxButtons.OK, MessageBoxIcon.Error);
return;
}
// Following code is default code:
Application.EnableVisualStyles();
Application.SetCompatibleTextRenderingDefault(false);
Application.Run(new MainForm());
}
我在解决方案中使用互斥来防止多个实例。
static Mutex mutex = null;
//A string that is the name of the mutex
string mutexName = @"Global\test";
//Prevent Multiple Instances of Application
bool onlyInstance = false;
mutex = new Mutex(true, mutexName, out onlyInstance);
if (!onlyInstance)
{
MessageBox.Show("You are already running this application in your system.", "Already Running..", MessageBoxButton.OK);
Application.Current.Shutdown();
}
Just some thoughts: There are cases when requiring that only one instance of an application is not "lame" as some would have you believe. Database apps, etc. are an order of magnitude more difficult if one allows multiple instances of the app for a single user to access a database (you know, all that updating all the records that are open in multiple instances of the app on the users machine, etc.). First, for the "name collision thing, don't use a human readable name - use a GUID instead or, even better a GUID + the human readable name. Chances of name collision just dropped off the radar and the Mutex doesn't care. As someone pointed out, a DOS attack would suck, but if the malicious person has gone to the trouble of getting the mutex name and incorporating it into their app, you are pretty much a target anyway and will have to do MUCH more to protect yourself than just fiddle a mutex name. Also, if one uses the variant of: new Mutex(true, "some GUID plus Name", out AIsFirstInstance), you already have your indicator as to whether or not the Mutex is the first instance.
[我在下面提供了控制台和wpf应用程序的示例代码。]
在创建命名的Mutex实例后,只需检查createdNew变量的值(示例如下!)。
布尔值createdNew将返回false:
如果命名为“YourApplicationNameHere”的互斥锁实例已经存在 在系统某处创建
布尔值createdNew将返回true:
如果这是第一个名为“YourApplicationNameHere”的互斥锁 系统。
控制台应用程序-示例:
static Mutex m = null;
static void Main(string[] args)
{
const string mutexName = "YourApplicationNameHere";
bool createdNew = false;
try
{
// Initializes a new instance of the Mutex class with a Boolean value that indicates
// whether the calling thread should have initial ownership of the mutex, a string that is the name of the mutex,
// and a Boolean value that, when the method returns, indicates whether the calling thread was granted initial ownership of the mutex.
using (m = new Mutex(true, mutexName, out createdNew))
{
if (!createdNew)
{
Console.WriteLine("instance is alreday running... shutting down !!!");
Console.Read();
return; // Exit the application
}
// Run your windows forms app here
Console.WriteLine("Single instance app is running!");
Console.ReadLine();
}
}
catch (Exception ex)
{
Console.WriteLine(ex.Message);
Console.ReadLine();
}
}
WPF-Example:
public partial class App : Application
{
static Mutex m = null;
protected override void OnStartup(StartupEventArgs e)
{
const string mutexName = "YourApplicationNameHere";
bool createdNew = false;
try
{
// Initializes a new instance of the Mutex class with a Boolean value that indicates
// whether the calling thread should have initial ownership of the mutex, a string that is the name of the mutex,
// and a Boolean value that, when the method returns, indicates whether the calling thread was granted initial ownership of the mutex.
m = new Mutex(true, mutexName, out createdNew);
if (!createdNew)
{
Current.Shutdown(); // Exit the application
}
}
catch (Exception)
{
throw;
}
base.OnStartup(e);
}
protected override void OnExit(ExitEventArgs e)
{
if (m != null)
{
m.Dispose();
}
base.OnExit(e);
}
}