是否有一个快速和简单的方法来编码JavaScript对象到字符串,我可以通过GET请求传递?

没有jQuery,没有其他框架-只有纯JavaScript:)


当前回答

对于TS

const convertQueryToString = (data: { [x: string]: any }): string => { const serialize = (obj: { [x: string]: any }, prefix?: string): string => { const str = []; let p; for (p in obj) { if (obj.hasOwnProperty(p)) { const k = prefix ? `${prefix}[${p}]` : p; const v = obj[p]; str.push( v !== null && typeof v === 'object' ? serialize(v, k) : `${encodeURIComponent(k)}=${encodeURIComponent(v)}` ); } } return str.join('&'); }; return serialize(data); };

其他回答

另一种方法(没有递归对象):

   getQueryString = function(obj)
   {
      result = "";

      for(param in obj)
         result += ( encodeURIComponent(param) + '=' + encodeURIComponent(obj[param]) + '&' );

      if(result) //it's not empty string when at least one key/value pair was added. In such case we need to remove the last '&' char
         result = result.substr(0, result.length - 1); //If length is zero or negative, substr returns an empty string [ref. http://msdn.microsoft.com/en-us/library/0esxc5wy(v=VS.85).aspx]

      return result;
   }

alert( getQueryString({foo: "hi there", bar: 123, quux: 2 }) );

下面是Object.entries的简洁递归版本。它处理任意嵌套的数组,但不处理嵌套的对象。它还会删除空元素:

const format = (k,v) => v !== null ? `${k}=${encodeURIComponent(v)}` : ''

const to_qs = (obj) => {
    return [].concat(...Object.entries(obj)
                       .map(([k,v]) => Array.isArray(v) 
                          ? v.map(arr => to_qs({[k]:arr})) 
                          : format(k,v)))
           .filter(x => x)
           .join('&');
}

例如:

let json = { 
    a: [1, 2, 3],
    b: [],              // omit b
    c: 1,
    d: "test&encoding", // uriencode
    e: [[4,5],[6,7]],   // flatten this
    f: null,            // omit nulls
    g: 0
};

let qs = to_qs(json)

=> "a=1&a=2&a=3&c=1&d=test%26encoding&e=4&e=5&e=6&e=7&g=0"

Ramda:

    R.pipe(R.toPairs, R.map(R.join('=')), R.join('&'))({a: 'b', b: 'a'})
const serialize = obj => Object.keys(obj).reduce((a, b) =>
    a.push(encodeURIComponent(b) + "=" + encodeURIComponent(obj[b])) && a,
    []).join("&");

电话:

console.log(serialize({a:1,b:2}));
// output: 'a=1&b=2

'

我建议使用URLSearchParams接口:

const searchParams = new URLSearchParams(); Const params = {foo: "hi there", bar: "100%"}; 种(params)。forEach(key => searchParams。追加(关键,params[主要])); console.log (searchParams.toString ())

或者像这样将搜索对象传递给构造函数:

Const params = {foo: "hi there", bar: "100%"}; const queryString = new URLSearchParams(params).toString(); console.log(参数);