我是这样做的:

type ParentProps = {}
type ParentState = { someValue: number }
class Parent extends React.Component<ParentProps, ParentState> {
    constructor(props: ParentProps) {
        super(props)
        this.state = { someValue: 0 }

        this.handleChange = this.handleChange.bind(this)
    }

    handleChange(value: number) {
        this.setState({...this.state, someValue: value})
    }

    render() {
        return <div>
            <Child changeFunction={this.handleChange} defaultValue={this.state.someValue} />
            <p>Value: {this.state.someValue}</p>
        </div>
    }
}

type ChildProps = { defaultValue: number, changeFunction: (value: number) => void}
type ChildState = { anotherValue: number }
class Child extends React.Component<ChildProps, ChildState> {
    constructor(props: ChildProps) {
        super(props)
        this.state = { anotherValue: this.props.defaultValue }

        this.handleChange = this.handleChange.bind(this)
    }

    handleChange(value: number) {
        this.setState({...this.state, anotherValue: value})
        this.props.changeFunction(value)
    }

    render() {
        return <div>
            <input onChange={event => this.handleChange(Number(event.target.value))} type='number' value={this.state.anotherValue}/>
        </div>
    }
}

我们可以通过将一个函数作为props传递给子组件来设置子组件的父状态，如下所示:

class Parent extends React.Component{
    state = { term : ''}

     onInputChange = (event) => {
         this.setState({term: event.target.value});
     }

     onFormSubmit = (event) => {
         event.preventDefault();
         this.props.onFormSubmit(this.state.term);
     }

     render(){
         return (
             <Child onInputChange={this.onInputChange} onFormSubmit=
                {this.onFormSubmit} />
         )
     }
}


class Child extends React.Component{

     render(){
         return (
             <div className="search-bar ui segment">
                 <form className="ui form" onSubmit={this.props.onFormSubmit}>
                     <div class="field">
                         <label>Search Video</label>
                         <input type="text" value={this.state.term} onChange=
                             {this.props.onInputChange} />
                     </div>
                 </form>
             </div>
         )
     }
}

这样，子进程将更新父进程的状态onInputChange和onFormSubmit是父进程传递的道具。这可以从子进程中的事件侦听器调用，因此状态将在那里更新。

我喜欢关于传递函数的答案。这是一个非常方便的技巧。

On the flip side you can also achieve this using pub/sub or using a variant, a dispatcher, as Flux does. The theory is super simple. Have component 5 dispatch a message which component 3 is listening for. Component 3 then updates its state which triggers the re-render. This requires stateful components, which, depending on your viewpoint, may or may not be an anti-pattern. I'm against them personally and would rather that something else is listening for dispatches and changes state from the very top-down (Redux does this, but it adds additional terminology).

import { Dispatcher } from 'flux'
import { Component } from 'React'

const dispatcher = new Dispatcher()

// Component 3
// Some methods, such as constructor, omitted for brevity
class StatefulParent extends Component {
  state = {
    text: 'foo'
  } 

  componentDidMount() {
    dispatcher.register( dispatch => {
      if ( dispatch.type === 'change' ) {
        this.setState({ text: 'bar' })
      }
    }
  }

  render() {
    return <h1>{ this.state.text }</h1>
  }
}

// Click handler
const onClick = event => {
  dispatcher.dispatch({
    type: 'change'
  })
}

// Component 5 in your example
const StatelessChild = props => {
  return <button onClick={ onClick }>Click me</button> 
}

使用Flux的调度程序捆绑非常简单。它只是简单地注册回调，并在任何分派发生时调用它们，传递分派上的内容(在上面的简洁示例中，分派没有有效负载，只有一个消息id)。如果对您更有意义的话，您可以很容易地将其调整为传统的pub/sub(例如，从事件中使用EventEmitter或其他版本)。

只需通过props将父组件的setState函数传递给子组件。

function ParentComp() {
  const [searchValue, setSearchValue] = useState("");
  return <SearchBox setSearchValue={setSearchValue} searchValue={searchValue} />;
}

然后在子组件中:

function SearchBox({ searchValue, setSearchValue }) {
  return (
        <input
          id="search-post"
          type="text"
          value={searchValue}
          onChange={(e) => setSearchValue(e.target.value)}
          placeholder="Search Blogs ..."
        />
    )
}

处理子组件点击的第二个例子:

// We've below function and component in parent component
const clickHandler = (val) => {
  alert(`httpRequest sent. \nValue Received: ${val}`);
};

// JSX
<HttpRequest clickHandler={clickHandler} />

这就是你如何从父组件中获取函数，然后传递一个值并通过它触发clickHandler。

function HttpRequest({ clickHandler }) {
  const [content, setContent] = useState("initialState");

  return (
    <button onClick={() => clickHandler(content)}>
      Send Request
    </button>
  );
}

export default HttpRequest;

对于子-父通信，您应该传递一个函数来设置从父到子的状态，如下所示

class Parent extends React.Component {
  constructor(props) {
    super(props)

    this.handler = this.handler.bind(this)
  }

  handler() {
    this.setState({
      someVar: 'some value'
    })
  }

  render() {
    return <Child handler = {this.handler} />
  }
}

class Child extends React.Component {
  render() {
    return <Button onClick = {this.props.handler}/ >
  }
}

这样，子进程就可以通过调用带有props的函数来更新父进程的状态。

但是你必须重新考虑组件的结构，因为根据我的理解，组件5和组件3是不相关的。

一种可能的解决方案是将它们包装在一个更高级别的组件中，该组件将同时包含组件1和组件3的状态。该组件将通过props设置较低级别的状态。

当您需要在子节点和父节点之间进行任何级别的通信时，最好利用上下文。在父组件中定义可以被子组件调用的上下文，例如:

在父组件中，在你的案例中，组件3，

static childContextTypes = {
    parentMethod: React.PropTypes.func.isRequired
};

getChildContext() {
    return {
        parentMethod: (parameter_from_child) => this.parentMethod(parameter_from_child)
    };
}

parentMethod(parameter_from_child){
    // Update the state with parameter_from_child
}

现在在子组件中(在你的例子中是组件5)，只需告诉这个组件它想要使用它的父组件的上下文。

static contextTypes = {
    parentMethod: React.PropTypes.func.isRequired
};

render() {
    return(
        <TouchableHighlight
            onPress = {() => this.context.parentMethod(new_state_value)}
            underlayColor='gray' >

            <Text> update state in parent component </Text>

        </TouchableHighlight>
)}

您可以在这个GitHub存储库中找到Demo项目。