我希望我没有重复上面的内容但是如果传递一个回调道具来设置父类中的函数呢?这很有效，也很简单。(添加的代码在////之间)

class Parent extends Component {
  ///// 
  getAlert = () => {} // initial value for getAlert

  setGetAlertMethod = (newMethod) => {
    this.getAlert = newMethod;
  }
  /////

  render() {
    return (
      <Child setGetAlertMethod={this.setGetAlertMethod}>
        <button onClick={this.getAlert}>Click</button>
      </Child>
      );
    }
  }



class Child extends Component {
  /////
  componentDidMount() {
    this.props.setGetAlertMethod(this.getAlert);
  }
  /////

  getAlert() => {
    alert('clicked');
  }

  render() {
    return (
      <h1 ref="hello">Hello</h1>
    );
  }
}

从父函数触发子函数的另一种方法是在子组件中使用componentDidUpdate函数。我将一个道具triggerChildFunc从父对象传递给子对象，初始值为null。当单击按钮时，该值更改为一个函数，Child注意到componentDidUpdate中的更改并调用自己的内部函数。

因为道具triggerChildFunc变成了一个函数，我们也得到了一个回调到父类的函数。如果Parent不需要知道函数何时被调用，则triggerChildFunc值可以从null改为true。

const { Component } = React; const { render } = ReactDOM; class Parent extends Component { state = { triggerFunc: null } render() { return ( <div> <Child triggerChildFunc={this.state.triggerFunc} /> <button onClick={() => { this.setState({ triggerFunc: () => alert('Callback in parent')}) }}>Click </button> </div> ); } } class Child extends Component { componentDidUpdate(prevProps) { if (this.props.triggerChildFunc !== prevProps.triggerChildFunc) { this.onParentTrigger(); } } onParentTrigger() { alert('parent triggered me'); // Let's call the passed variable from parent if it's a function if (this.props.triggerChildFunc && {}.toString.call(this.props.triggerChildFunc) === '[object Function]') { this.props.triggerChildFunc(); } } render() { return ( <h1>Hello</h1> ); } } render( <Parent />, document.getElementById('app') ); <script src="https://cdnjs.cloudflare.com/ajax/libs/react/16.6.3/umd/react.production.min.js"></script> <script src="https://cdnjs.cloudflare.com/ajax/libs/react-dom/16.6.3/umd/react-dom.production.min.js"></script> <div id='app'></div>

CodePen: https://codepen.io/calsal/pen/NWPxbJv?editors=1010

我希望我没有重复上面的内容但是如果传递一个回调道具来设置父类中的函数呢?这很有效，也很简单。(添加的代码在////之间)

class Parent extends Component {
  ///// 
  getAlert = () => {} // initial value for getAlert

  setGetAlertMethod = (newMethod) => {
    this.getAlert = newMethod;
  }
  /////

  render() {
    return (
      <Child setGetAlertMethod={this.setGetAlertMethod}>
        <button onClick={this.getAlert}>Click</button>
      </Child>
      );
    }
  }



class Child extends Component {
  /////
  componentDidMount() {
    this.props.setGetAlertMethod(this.getAlert);
  }
  /////

  getAlert() => {
    alert('clicked');
  }

  render() {
    return (
      <h1 ref="hello">Hello</h1>
    );
  }
}

首先，让我声明一下，在React领域，这通常不是做事的方式。通常，您要做的是将功能传递给道具中的子元素，并在事件中传递子元素的通知(或者更好的方法是:分派)。

但如果必须在子组件上公开命令式方法，则可以使用refs。记住，这是一个逃生口，通常表明有更好的设计可用。

以前，引用只支持基于类的组件。 随着React Hooks的出现，这种情况不再存在

Modern React with Hooks (v16.8+)

const { forwardRef, useRef, useImperativeHandle } = React; // We need to wrap component in `forwardRef` in order to gain // access to the ref object that is assigned using the `ref` prop. // This ref is passed as the second parameter to the function component. const Child = forwardRef((props, ref) => { // The component instance will be extended // with whatever you return from the callback passed // as the second argument useImperativeHandle(ref, () => ({ getAlert() { alert("getAlert from Child"); } })); return <h1>Hi</h1>; }); const Parent = () => { // In order to gain access to the child component instance, // you need to assign it to a `ref`, so we call `useRef()` to get one const childRef = useRef(); return ( <div> <Child ref={childRef} /> <button onClick={() => childRef.current.getAlert()}>Click</button> </div> ); }; ReactDOM.render( <Parent />, document.getElementById('root') ); <script src="https://unpkg.com/react@16/umd/react.development.js" crossorigin></script> <script src="https://unpkg.com/react-dom@16/umd/react-dom.development.js" crossorigin></script> <div id="root"></div>

useImperativeHandle()的文档在这里:

useImperativeHandle自定义使用ref时暴露给父组件的实例值。

使用类组件的遗留API (>= react@16.4)

const { Component } = React; class Parent extends Component { constructor(props) { super(props); this.child = React.createRef(); } onClick = () => { this.child.current.getAlert(); }; render() { return ( <div> <Child ref={this.child} /> <button onClick={this.onClick}>Click</button> </div> ); } } class Child extends Component { getAlert() { alert('getAlert from Child'); } render() { return <h1>Hello</h1>; } } ReactDOM.render(<Parent />, document.getElementById('root')); <script src="https://unpkg.com/react@16/umd/react.development.js" crossorigin></script> <script src="https://unpkg.com/react-dom@16/umd/react-dom.development.js" crossorigin></script> <div id="root"></div>

回调参考API

回调风格的引用是实现这一点的另一种方法，尽管在现代React中不太常见:

const { Component } = React; const { render } = ReactDOM; class Parent extends Component { render() { return ( <div> <Child ref={instance => { this.child = instance; }} /> <button onClick={() => { this.child.getAlert(); }}>Click</button> </div> ); } } class Child extends Component { getAlert() { alert('clicked'); } render() { return ( <h1>Hello</h1> ); } } render( <Parent />, document.getElementById('app') ); <script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react.min.js"></script> <script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react-dom.min.js"></script> <div id="app"></div>

这里有个虫子?注意: 我同意rossipedia的解决方案使用forwardRef, useRef, useImperativeHandle

网上有一些错误的信息说refs只能从React类组件创建，但如果你使用上面提到的钩子，你确实可以使用函数组件。注意，只有在我将文件更改为在导出组件时不使用withRouter()后，钩子才对我有效。例如，从

export default withRouter(TableConfig);

取而代之的是

export default TableConfig;

In hindsight the withRouter() is not needed for such a component anyway, but usually it doesn't hurt anything having it in. My use case is that I created a component to create a Table to handle the viewing and editing of config values, and I wanted to be able to tell this Child component to reset it's state values whenever the Parent form's Reset button was hit. UseRef() wouldn't properly get the ref or ref.current (kept on getting null) until I removed withRouter() from the file containing my child component TableConfig

使用useEffect的替代方法:

家长:

const [refresh, doRefresh] = useState(0);
<Button onClick={() => doRefresh(prev => prev + 1)} />
<Children refresh={refresh} />

孩子们:

useEffect(() => {
    performRefresh(); //children function of interest
  }, [props.refresh]);