我认为调用方法的最基本方法是在子组件上设置请求。然后，一旦子进程处理了请求，它就调用一个回调方法来重置请求。

为了能够多次发送相同的请求，重置机制是必要的。

在父组件中

在父类的渲染方法中:

const { request } = this.state;
return (<Child request={request} onRequestHandled={()->resetRequest()}/>);

父节点需要两个方法，在两个方向上与子节点进行通信。

sendRequest() {
  const request = { param: "value" };
  this.setState({ request });
}

resetRequest() {
  const request = null;
  this.setState({ request });
}

在子组件中

子进程更新其内部状态，复制来自道具的请求。

constructor(props) {
  super(props);
  const { request } = props;
  this.state = { request };
}

static getDerivedStateFromProps(props, state) {
  const { request } = props;
  if (request !== state.request ) return { request };
  return null;
}

最后，它处理请求，并将重置发送给父进程:

componentDidMount() {
  const { request } = this.state;
  // todo handle request.

  const { onRequestHandled } = this.props;
  if (onRequestHandled != null) onRequestHandled();
}

用这种方法可以很容易地实现这一点

步骤,

Create a boolean variable in the state in the parent class. Update this when you want to call a function. Create a prop variable and assign the boolean variable. From the child component access that variable using props and execute the method you want by having an if condition. class Child extends Component { Method=()=>{ --Your method body-- } render() { return ( //check whether the variable has been updated or not if(this.props.updateMethod){ this.Method(); } ) } } class Parent extends Component { constructor(){ this.state={ callMethod:false } } render() { return ( //update state according to your requirement this.setState({ callMethod:true }} <Child updateMethod={this.state.callMethod}></Child> ); } }

对于功能组件，最简单的方法是

父组件

parent.tsx

import React, { useEffect, useState, useRef } from "react";
import child from "../../child"

const parent: React.FunctionComponent = () => {
  const childRef: any = useRef();
}

const onDropDownChange: any = (event): void => {
    const target = event.target;
    childRef.current.onFilterChange(target.value);
};

return <child ref={childRef} />

export default parent;

子组件

child.tsx

import React, {   useState,   useEffect,   forwardRef,   useRef,   useImperativeHandle, } from "react";

const Child = forwardRef((props, ref) => {
 useImperativeHandle(ref, () => ({
    onFilterChange(id) {
      console.log("Value from parent", id)
    },
  }));
})

Child.displayName = "Child";

export default Child;

父组件

import Child from './Child'

export default function Parent(props) {
    const [childRefreshFunction, setChildRefreshFunction] = useState(null);

    return (
        <div>
            <button type="button" onClick={() => {
                childRefreshFunction();
            }}>Refresh child</button>
            <Child setRefreshFunction={(f) => {
                setChildRefreshFunction(f);
            }} />
        </div>
    )
}

子组件

export default function Child(props) {

    useEffect(() => {
        props.setRefreshFunction(() => refreshMe);
    }, []);

    function refreshMe() {
        fetch('http://example.com/data.json')....
    };

    return (
        <div>
            child
        </div>
    )
}

这里有个虫子?注意: 我同意rossipedia的解决方案使用forwardRef, useRef, useImperativeHandle

网上有一些错误的信息说refs只能从React类组件创建，但如果你使用上面提到的钩子，你确实可以使用函数组件。注意，只有在我将文件更改为在导出组件时不使用withRouter()后，钩子才对我有效。例如，从

export default withRouter(TableConfig);

取而代之的是

export default TableConfig;

In hindsight the withRouter() is not needed for such a component anyway, but usually it doesn't hurt anything having it in. My use case is that I created a component to create a Table to handle the viewing and editing of config values, and I wanted to be able to tell this Child component to reset it's state values whenever the Parent form's Reset button was hit. UseRef() wouldn't properly get the ref or ref.current (kept on getting null) until I removed withRouter() from the file containing my child component TableConfig

https://facebook.github.io/react/tips/expose-component-functions.html 更多答案请参考这里调用React子组件上的方法

通过查看“reason”组件的引用，您正在破坏封装，如果不仔细检查使用该组件的所有位置，就不可能重构该组件。正因为如此，我们强烈建议将引用视为组件的私有，就像状态一样。

一般来说，数据应该通过道具沿着树向下传递。有一些例外情况(比如调用.focus()或触发一个不会真正“改变”状态的一次性动画)，但任何时候你要公开一个名为“set”的方法，道具通常是更好的选择。试着让内部输入组件担心它的大小和外观，这样它的祖先就不会担心。