我有一个windows窗体应用程序与一个文本框控件,我想只接受整数值。在过去,我通过重载KeyPress事件并删除不符合规范的字符来进行这种验证。我已经看了MaskedTextBox控件,但我想一个更通用的解决方案,可以与也许正则表达式,或依赖于其他控件的值。

理想情况下,按下非数字字符要么不产生结果,要么立即向用户提供关于无效字符的反馈。


当前回答

WPF的工作解决方案&一个简单的TextChangedEventArgs。

private void TextBox_TextChanged(object sender, TextChangedEventArgs e)
{
    var TextBox = (sender as TextBox);

    // if not a numeric value, remove news characters
    if (Regex.IsMatch(TextBox.Text, "[^0-9]"))
    {
        foreach (TextChange Change in e.Changes)
        {
            TextBox.Text = TextBox.Text.Remove(Change.Offset, Change.AddedLength);

            TextBox.CaretIndex = Change.Offset;
        }
    }
}

其他回答

3解决方案

1)

//Add to the textbox's KeyPress event
//using Regex for number only textBox

private void txtBox_KeyPress(object sender, KeyPressEventArgs e)
{
if (!System.Text.RegularExpressions.Regex.IsMatch(e.KeyChar.ToString(), "\\d+"))
e.Handled = true;
}

2) 来自MSDN的另一个解决方案

// Boolean flag used to determine when a character other than a number is entered.
private bool nonNumberEntered = false;
// Handle the KeyDown event to determine the type of character entered into the     control.
private void textBox1_KeyDown(object sender, KeyEventArgs e)
{
// Initialize the flag to false.
nonNumberEntered = false;
// Determine whether the keystroke is a number from the top of the keyboard.
if (e.KeyCode < Keys.D0 || e.KeyCode > Keys.D9)
{
    // Determine whether the keystroke is a number from the keypad.
    if (e.KeyCode < Keys.NumPad0 || e.KeyCode > Keys.NumPad9)
    {
        // Determine whether the keystroke is a backspace.
        if (e.KeyCode != Keys.Back)
        {
            // A non-numerical keystroke was pressed.
            // Set the flag to true and evaluate in KeyPress event.
            nonNumberEntered = true;
        }
    }
}

}

private void textBox1_KeyPress(object sender, KeyPressEventArgs e)
{
    if (nonNumberEntered == true)
    {
       MessageBox.Show("Please enter number only..."); 
       e.Handled = true;
    }
}

源http://msdn.microsoft.com/en-us/library/system.windows.forms.control.keypress (v =应用程序). aspx

3)使用MaskedTextBox: http://msdn.microsoft.com/en-us/library/system.windows.forms.maskedtextbox.aspx

int Number;
bool isNumber;
isNumber = int32.TryPase(textbox1.text, out Number);

if (!isNumber)
{ 
    (code if not an integer);
}
else
{
    (code if an integer);
}
Here is a simple solution that works for me.

public static bool numResult;
    public static bool checkTextisNumber(string numberVal)
    {
        try
        {
            if (numberVal.Equals("."))
            {
                numResult = true;
            }
            else if (numberVal.Equals(""))
            {
                numResult = true;
            }
            else
            {
                decimal number3 = 0;
                bool canConvert = decimal.TryParse(numberVal, out number3);
                if (canConvert == true)
                {
                    numResult = true;
                }
                else
                    numResult = false;
            }

        }
        catch (System.Exception ex)
        {
            numResult = false;
        }
        return numResult;
    }
    string correctNum;
    private void tBox_NumTester_TextChanged(object sender, TextChangedEventArgs e)
    {


        if(checkTextisNumber(tBox_NumTester.Text))
        {
            correctNum = tBox_NumTester.Text;
        }
        else
        {
            tBox_NumTester.Text = correctNum;
        }

    }

最简单粗暴的方法是使用组合框而不是带有只读的文本框。当然,只有当你希望用户使用一个合理的整数集,而不是试图接近无穷大时,它才有用。

private void txt3_KeyPress(object sender, KeyPressEventArgs e)
{
    for (int h = 58; h <= 127; h++)
    {
        if (e.KeyChar == h)             //58 to 127 is alphabets tat will be         blocked
        {
            e.Handled = true;
        }
    }
    for(int k=32;k<=47;k++)
    {
        if (e.KeyChar == k)              //32 to 47 are special characters tat will 
        {                                  be blocked
            e.Handled = true;
        }
    }
}

试试这个很简单