我应该如何选择一个标签在TabLayout编程?
TabLayout tabLayout = (TabLayout) findViewById(R.id.tabs);
tabLayout.setupWithViewPager(viewPager);
我应该如何选择一个标签在TabLayout编程?
TabLayout tabLayout = (TabLayout) findViewById(R.id.tabs);
tabLayout.setupWithViewPager(viewPager);
当前回答
我使用TabLayout切换片段。它在大多数情况下都是有效的,除了当我试图以编程方式使用tab.select(),我的TabLayout选择一个选项卡时。OnTabSelectedListener将触发onTabSelected(TabLayout。Tab Tab),这会让我很伤心。我正在寻找一种不触发侦听器的方法来做程序化选择。
So I adapted @kenodoggy 's answer to my use. I was further facing a problem where some of the internal objects would return null (because they weren't created yet, because I was answering onActivityResult() from my fragment, which occurs before onCreate() in the case the activity is singleTask or singleInstance) so I wrote up a detailed if/else sequence which would report the error and fall through without the NullPointerException that would otherwise trigger. I use Timber for logging, if you're not using that substitute with Log.e().
void updateSelectedTabTo(int position) {
if (tabLayout != null){
int selected = tabLayout.getSelectedTabPosition();
if (selected != -1){
TabLayout.Tab oldTab = tabLayout.getTabAt(0);
if (oldTab != null){
View view = oldTab.getCustomView();
if (view != null){
view.setSelected(false);
}
else {
Timber.e("oldTab customView is null");
}
}
else {
Timber.e("oldTab is null");
}
}
else {
Timber.e("selected is -1");
}
TabLayout.Tab newTab = tabLayout.getTabAt(position);
if (newTab != null){
View view = newTab.getCustomView();
if (view != null){
view.setSelected(false);
}
else {
Timber.e("newTab customView is null");
}
}
else {
Timber.e("newTab is null");
}
}
else {
Timber.e("tablayout is null");
}
}
这里,tabLayout是绑定到XML中的tabLayout对象的内存变量。我不使用滚动标签功能,所以我把它也删除了。
其他回答
对于Viewpager2, Kotlin,其他答案都没有帮助,只有下面这个有用。位置是从片段结果监听器在我的情况下:
TabLayoutMediator(binding.tabLayout, binding.viewPager2) { _, _ ->
binding.viewPager2 = position
}.attach()
如果你不能使用tab.select(),也不想使用ViewPager,你仍然可以通过编程方式选择一个选项卡。如果你通过TabLayout使用自定义视图。选项卡setCustomView (android.view。View View)它更简单。以下是如何做到这两种方式。
// if you've set a custom view
void updateTabSelection(int position) {
// get the position of the currently selected tab and set selected to false
mTabLayout.getTabAt(mTabLayout.getSelectedTabPosition()).getCustomView().setSelected(false);
// set selected to true on the desired tab
mTabLayout.getTabAt(position).getCustomView().setSelected(true);
// move the selection indicator
mTabLayout.setScrollPosition(position, 0, true);
// ... your logic to swap out your fragments
}
如果你不使用自定义视图,那么你可以这样做
// if you are not using a custom view
void updateTabSelection(int position) {
// get a reference to the tabs container view
LinearLayout ll = (LinearLayout) mTabLayout.getChildAt(0);
// get the child view at the position of the currently selected tab and set selected to false
ll.getChildAt(mTabLayout.getSelectedTabPosition()).setSelected(false);
// get the child view at the new selected position and set selected to true
ll.getChildAt(position).setSelected(true);
// move the selection indicator
mTabLayout.setScrollPosition(position, 0, true);
// ... your logic to swap out your fragments
}
使用StateListDrawable在选中和未选中的可绘制对象之间切换,或者类似地处理颜色和/或可绘制对象。
科特林修复
viewPager.currentItem = 0
tabs.setupWithViewPager(viewPager)
这可能不是最终的解决方案,它需要你使用TabLayout和一个ViewPager,但这是我解决它的方法:
void selectPage(int pageIndex)
{
viewPager.setCurrentItem(pageIndex);
tabLayout.setupWithViewPager(viewPager);
}
我测试了使用这段代码对性能的影响有多大,首先在Android Studio中运行该方法时查看CPU和内存监视器,然后将其与我自己在页面之间导航时(使用滑动手势)对CPU和内存的负载进行比较,结果发现差异并不大,所以至少这不是一个可怕的解决方案……
希望这能帮助到一些人!
结合不同的答案可以得出:
new Handler().postDelayed(() -> {
myViewPager.setCurrentItem(position, true);
myTabLayout.setScrollPosition(position, 0f, true);
},
100);