Linux和OSX的另一种干净的解决方案，它也可以与bash变量一起使用

python -c "print(\"abc\".capitalize())"

返回美国广播公司

下面是“原生”文本工具的使用方法:

#!/bin/bash

string="abcd"
first=`echo $string|cut -c1|tr [a-z] [A-Z]`
second=`echo $string|cut -c2-`
echo $first$second

它也可以在纯bash中使用bash-3.2完成:

# First, get the first character.
fl=${foo:0:1}

# Safety check: it must be a letter :).
if [[ ${fl} == [a-z] ]]; then
    # Now, obtain its octal value using printf (builtin).
    ord=$(printf '%o' "'${fl}")

    # Fun fact: [a-z] maps onto 0141..0172. [A-Z] is 0101..0132.
    # We can use decimal '- 40' to get the expected result!
    ord=$(( ord - 40 ))

    # Finally, map the new value back to a character.
    fl=$(printf '%b' '\'${ord})
fi

echo "${fl}${foo:1}"

只大写第一个单词:

foo='one two three'
foo="${foo^}"
echo $foo

一二三

将变量中的每个单词大写:

foo="one two three"
foo=( $foo ) # without quotes
foo="${foo[@]^}"
echo $foo

一二三

(适用于bash 4+)

如果第一个字符不是字母(而是制表符、空格和转义双引号)怎么办?我们最好测试它，直到我们找到一个字母!所以:

S='  \"ó foo bar\"'
N=0
until [[ ${S:$N:1} =~ [[:alpha:]] ]]; do N=$[$N+1]; done
#F=`echo ${S:$N:1} | tr [:lower:] [:upper:]`
#F=`echo ${S:$N:1} | sed -E -e 's/./\u&/'` #other option
F=`echo ${S:$N:1}
F=`echo ${F} #pure Bash solution to "upper"
echo "$F"${S:(($N+1))} #without garbage
echo '='${S:0:(($N))}"$F"${S:(($N+1))}'=' #garbage preserved

Foo bar
= \"Foo bar=

使用bash(版本4+)的一种方法:

foo=bar
echo "${foo^}"

打印:

Bar