这似乎很有效。

$ sudo dpkg-query -l | grep <some_package_name> | wc -l

如果没有安装，则返回0;如果安装，则返回某个数字> 0。

which <command>
if [ $? == 1 ]; then
    <pkg-manager> -y install <command>
fi

有点以你的为基础，只是更“优雅”一点。只是因为我很无聊。

#!/bin/bash
FOUND=("\033[38;5;10m")
NOTFOUND=("\033[38;5;9m")
PKG="${@:1}"
command ${PKG} &>/dev/null
if [[ $? != 0 ]]; then
    echo -e "${NOTFOUND}[!] ${PKG} not found [!]"
    echo -e "${NOTFOUND}[!] Would you like to install ${PKG} now ? [!]"
    read -p "[Y/N] >$ " ANSWER
    if [[ ${ANSWER} == [yY] || ${ANSWER} == [yY][eE][sS] ]]; then
        if grep -q "bian" /etc/os-release; then
            sudo apt-get install ${PKG}
        elif grep -q "arch" /etc/os-release; then
            if [[ -f /bin/yay ]] || [[ -f /bin/yaourt ]]; then
                yaourt -S ${PKG} 2>./err || yay -S ${PKG} 2>./err
            else
                sudo pacman -S ${PKG}
            fi
        elif grep -q "fedora" /etc/os-release; then
             sudo dnf install ${PKG}
        else
            echo -e "${NOTFOUND}[!] This script couldn't detect your package manager [!]"
            echo -e "${NOTFOUND}[!] Manually install it [!]"
        fi
    elif [[ ${ANSWER} == [nN] || ${ANSWER} == [nN][oO] ]]; then
        echo -e "${NOTFOUND}[!] Exiting [!]"
    fi
else
    echo -e "${FOUND}[+] ${PKG} found [+]"
fi

apt list [packagename]

这似乎是在DPKG和旧apt-*工具之外最简单的方法。

这一行代码为“nano”包返回1(已安装)或0(未安装)…

$(dpkg-query -W -f='${Status}' nano 2>/dev/null | grep -c "ok installed")

即使包不存在或不可用。

下面的例子将安装'nano'包，如果它没有安装…

if [ $(dpkg-query -W -f='${Status}' nano 2>/dev/null | grep -c "ok installed") -eq 0 ];
then
  apt-get install nano;
fi

要检查是否安装了packagename，输入:

dpkg -s <packagename>

您还可以使用dpkg-query，它的输出更简洁，而且还接受通配符。

dpkg-query -l <packagename>

要找到哪个包拥有该命令，请尝试:

dpkg -S `which <command>`

有关更多详细信息，请参见文章“了解Linux中是否安装了软件包”和dpkg备忘单。