我正在Ubuntu系统上工作,目前我正在做的是:
if ! which command > /dev/null; then
echo -e "Command not found! Install? (y/n) \c"
read
if "$REPLY" = "y"; then
sudo apt-get install command
fi
fi
大多数人都会这么做吗?还是有更优雅的解决方案?
我正在Ubuntu系统上工作,目前我正在做的是:
if ! which command > /dev/null; then
echo -e "Command not found! Install? (y/n) \c"
read
if "$REPLY" = "y"; then
sudo apt-get install command
fi
fi
大多数人都会这么做吗?还是有更优雅的解决方案?
当前回答
既然你提到了Ubuntu,而且你想以编程的方式做到这一点(虽然也可以使用dpkg的变体,但实现起来会更复杂),这(这)肯定是可行的:
#!/bin/bash
pkgname=mutt
which $pkgname > /dev/null;isPackage=$?
if [ $isPackage != 0 ];then
echo "$pkgname not installed"
sleep 1
read -r -p "${1:-$pkgname will be installed. Are you sure? [y/N]} " response
case "$response" in
[yY][eE][sS]|[yY])
sudo apt-get install $pkgname
;;
*)
false
;;
esac
else
echo "$pkgname is installed"
sleep 1
fi
尽管为了POSIX兼容性,您可能希望使用命令-v,正如在另一个类似问题中提到的那样。
这样的话, 在上面的代码示例中,$pkgname > /dev/null应该被命令-v $pkgname替换。
其他回答
我使用以下方法:
which mySQL 2>&1|tee 1> /dev/null
if [[ "$?" == 0 ]]; then
echo -e "\e[42m MySQL already installed. Moving on...\e[0m"
else
sudo apt-get install -y mysql-server
if [[ "$?" == 0 ]]; then
echo -e "\e[42mMy SQL installed\e[0m"
else
echo -e "\e[42Installation failed\e[0m"
fi
fi
Ubuntu添加了它的“个人包存档”(PPA),而PPA包有不同的结果。
A native Debian repository package is not installed: ~$ dpkg-query -l apache-perl ~$ echo $? 1 A PPA package registered on the host and installed: ~$ dpkg-query -l libreoffice ~$ echo $? 0 A PPA package registered on the host, but not installed: ~$ dpkg-query -l domy-ce ~$ echo $? 0 ~$ sudo apt-get remove domy-ce [sudo] password for user: Reading package lists... Done Building dependency tree Reading state information... Done Package domy-ce is not installed, so not removed 0 upgraded, 0 newly installed, 0 to remove and 0 not upgraded.
测试APT中是否安装了软件包
which <command>
if [ $? == 1 ]; then
<pkg-manager> -y install <command>
fi
这个特性已经存在于Ubuntu和Debian的command-not-found包中。
这个就行了。Apt-get install是幂等的。
sudo apt-get install --no-upgrade command