我如何使用杰克逊JSON映射与Java 8 LocalDateTime?

jsonmappingexception:不能实例化类型[简单类型,java.time类]的值。LocalDateTime] from JSON字符串;没有单字符串构造函数/工厂方法(通过引用链:MyDTO["field1"]->SubDTO["date"])


当前回答

如果您正在使用fastxml的ObjectMapper类, 默认情况下,ObjectMapper不理解LocalDateTime类,所以,你需要在你的gradle/maven中添加另一个依赖项:

compile 'com.fasterxml.jackson.datatype:jackson-datatype-jsr310:2.7.3'

现在你需要将这个库提供的数据类型支持注册到你的objectmapper对象中,这可以通过以下方式完成:

ObjectMapper objectMapper = new ObjectMapper();
objectMapper.findAndRegisterModules();

现在,在你的jsonString中,你可以很容易地把你的java。LocalDateTime字段如下所示:

{
    "user_id": 1,
    "score": 9,
    "date_time": "2016-05-28T17:39:44.937"
}

通过这样做,你的Json文件到Java对象的转换将工作良好,你可以通过以下方式读取文件:

objectMapper.readValue(jsonString, new TypeReference<List<User>>() {
            });

其他回答

如果你正在使用Jersey,那么你需要像其他人建议的那样添加Maven依赖项(jackson- dattype -jsr310),并像这样注册你的对象映射器实例:

@Provider
public class JacksonObjectMapper implements ContextResolver<ObjectMapper> {

  final ObjectMapper defaultObjectMapper;

  public JacksonObjectMapper() {
    defaultObjectMapper = createDefaultMapper();
  }

  @Override
  public ObjectMapper getContext(Class<?> type) {
    return defaultObjectMapper;
  }

  private static ObjectMapper createDefaultMapper() {
    final ObjectMapper mapper = new ObjectMapper();    
    mapper.registerModule(new JavaTimeModule());
    return mapper;
  }
}

当在你的资源中注册Jackson时,你需要像这样添加这个映射器:

final ResourceConfig rc = new ResourceConfig().packages("<your package>");
rc
  .register(JacksonObjectMapper.class)
  .register(JacksonJaxbJsonProvider.class);

更新:由于历史原因,留下这个答案,但我不建议这样做。请参阅上面接受的答案。

告诉Jackson使用自定义的[反]序列化类进行映射:

@JsonSerialize(using = LocalDateTimeSerializer.class)
@JsonDeserialize(using = LocalDateTimeDeserializer.class)
private LocalDateTime ignoreUntil;

提供自定义类:

public class LocalDateTimeSerializer extends JsonSerializer<LocalDateTime> {
    @Override
    public void serialize(LocalDateTime arg0, JsonGenerator arg1, SerializerProvider arg2) throws IOException {
        arg1.writeString(arg0.toString());
    }
}

public class LocalDateTimeDeserializer extends JsonDeserializer<LocalDateTime> {
    @Override
    public LocalDateTime deserialize(JsonParser arg0, DeserializationContext arg1) throws IOException {
        return LocalDateTime.parse(arg0.getText());
    }
}

随机事实:如果我在类上面嵌套并且不使它们静态,错误消息是奇怪的: httpmediatypenotsupportedexception:内容类型'application/json;charset=UTF-8'不支持

我使用这个时间格式:"{birthDate": "2018-05-24T13:56:13Z}"从json反序列化为java.time.Instant(见截图)

如果您因为GraphQL Java工具而遇到此问题,并试图从日期字符串编组Java Instant,则需要设置SchemaParser以使用具有特定配置的ObjectMapper:

在GraphQLSchemaBuilder类中,注入ObjectMapper并添加以下模块:

        ObjectMapper objectMapper = 
    new ObjectMapper().registerModule(new JavaTimeModule())
            .configure(SerializationFeature.WRITE_DATES_AS_TIMESTAMPS, false);

并将其添加到选项中:

final SchemaParserOptions options = SchemaParserOptions.newOptions()
            .objectMapperProvider(fieldDefinition -> objectMapper)
            .typeDefinitionFactory(new YourTypeDefinitionFactory())
            .build();

参见https://github.com/graphql-java-kickstart/graphql-spring-boot/issues/32

ObjectMapper objectMapper = new ObjectMapper().configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false);
objectMapper.registerModule(new JavaTimeModule());

这对我很有效