我如何使用杰克逊JSON映射与Java 8 LocalDateTime?
jsonmappingexception:不能实例化类型[简单类型,java.time类]的值。LocalDateTime] from JSON字符串;没有单字符串构造函数/工厂方法(通过引用链:MyDTO["field1"]->SubDTO["date"])
我如何使用杰克逊JSON映射与Java 8 LocalDateTime?
jsonmappingexception:不能实例化类型[简单类型,java.time类]的值。LocalDateTime] from JSON字符串;没有单字符串构造函数/工厂方法(通过引用链:MyDTO["field1"]->SubDTO["date"])
当前回答
如果你正在使用Jersey,那么你需要像其他人建议的那样添加Maven依赖项(jackson- dattype -jsr310),并像这样注册你的对象映射器实例:
@Provider
public class JacksonObjectMapper implements ContextResolver<ObjectMapper> {
final ObjectMapper defaultObjectMapper;
public JacksonObjectMapper() {
defaultObjectMapper = createDefaultMapper();
}
@Override
public ObjectMapper getContext(Class<?> type) {
return defaultObjectMapper;
}
private static ObjectMapper createDefaultMapper() {
final ObjectMapper mapper = new ObjectMapper();
mapper.registerModule(new JavaTimeModule());
return mapper;
}
}
当在你的资源中注册Jackson时,你需要像这样添加这个映射器:
final ResourceConfig rc = new ResourceConfig().packages("<your package>");
rc
.register(JacksonObjectMapper.class)
.register(JacksonJaxbJsonProvider.class);
其他回答
更新:由于历史原因,留下这个答案,但我不建议这样做。请参阅上面接受的答案。
告诉Jackson使用自定义的[反]序列化类进行映射:
@JsonSerialize(using = LocalDateTimeSerializer.class)
@JsonDeserialize(using = LocalDateTimeDeserializer.class)
private LocalDateTime ignoreUntil;
提供自定义类:
public class LocalDateTimeSerializer extends JsonSerializer<LocalDateTime> {
@Override
public void serialize(LocalDateTime arg0, JsonGenerator arg1, SerializerProvider arg2) throws IOException {
arg1.writeString(arg0.toString());
}
}
public class LocalDateTimeDeserializer extends JsonDeserializer<LocalDateTime> {
@Override
public LocalDateTime deserialize(JsonParser arg0, DeserializationContext arg1) throws IOException {
return LocalDateTime.parse(arg0.getText());
}
}
随机事实:如果我在类上面嵌套并且不使它们静态,错误消息是奇怪的: httpmediatypenotsupportedexception:内容类型'application/json;charset=UTF-8'不支持
如果你因为任何原因不能使用jackson-modules-java8,你可以(反)序列化即时字段,只要使用@JsonIgnore和@JsonGetter和@JsonSetter:
public class MyBean {
private Instant time = Instant.now();
@JsonIgnore
public Instant getTime() {
return this.time;
}
public void setTime(Instant time) {
this.time = time;
}
@JsonGetter
private long getEpochTime() {
return this.time.toEpochMilli();
}
@JsonSetter
private void setEpochTime(long time) {
this.time = Instant.ofEpochMilli(time);
}
}
例子:
@Test
public void testJsonTime() throws Exception {
String json = new ObjectMapper().writeValueAsString(new MyBean());
System.out.println(json);
MyBean myBean = new ObjectMapper().readValue(json, MyBean.class);
System.out.println(myBean.getTime());
}
收益率
{"epochTime":1506432517242}
2017-09-26T13:28:37.242Z
我在使用Spring boot时遇到了类似的问题。 使用Spring启动1.5.1。我所要做的就是添加依赖项:
<dependency>
<groupId>com.fasterxml.jackson.datatype</groupId>
<artifactId>jackson-datatype-jsr310</artifactId>
</dependency>
如果您正在使用fastxml的ObjectMapper类, 默认情况下,ObjectMapper不理解LocalDateTime类,所以,你需要在你的gradle/maven中添加另一个依赖项:
compile 'com.fasterxml.jackson.datatype:jackson-datatype-jsr310:2.7.3'
现在你需要将这个库提供的数据类型支持注册到你的objectmapper对象中,这可以通过以下方式完成:
ObjectMapper objectMapper = new ObjectMapper();
objectMapper.findAndRegisterModules();
现在,在你的jsonString中,你可以很容易地把你的java。LocalDateTime字段如下所示:
{
"user_id": 1,
"score": 9,
"date_time": "2016-05-28T17:39:44.937"
}
通过这样做,你的Json文件到Java对象的转换将工作良好,你可以通过以下方式读取文件:
objectMapper.readValue(jsonString, new TypeReference<List<User>>() {
});
如果你正在使用Jersey,那么你需要像其他人建议的那样添加Maven依赖项(jackson- dattype -jsr310),并像这样注册你的对象映射器实例:
@Provider
public class JacksonObjectMapper implements ContextResolver<ObjectMapper> {
final ObjectMapper defaultObjectMapper;
public JacksonObjectMapper() {
defaultObjectMapper = createDefaultMapper();
}
@Override
public ObjectMapper getContext(Class<?> type) {
return defaultObjectMapper;
}
private static ObjectMapper createDefaultMapper() {
final ObjectMapper mapper = new ObjectMapper();
mapper.registerModule(new JavaTimeModule());
return mapper;
}
}
当在你的资源中注册Jackson时,你需要像这样添加这个映射器:
final ResourceConfig rc = new ResourceConfig().packages("<your package>");
rc
.register(JacksonObjectMapper.class)
.register(JacksonJaxbJsonProvider.class);