到目前为止，我发现gettimeofday在iOS (iPad)上是一个很好的解决方案，当你想执行一些间隔评估(比如帧速率，渲染帧的计时……):

#include <sys/time.h>
struct timeval time;
gettimeofday(&time, NULL);
long millis = (time.tv_sec * 1000) + (time.tv_usec / 1000);

如果你不想包含Quartz框架，[NSDate timeintervalsincerely eferencedate]是另一个选项。它返回一个double，表示秒数。

这基本上和@TristanLorach发布的答案是一样的，只是为Swift 3重新编码:

   /// Method to get Unix-style time (Java variant), i.e., time since 1970 in milliseconds. This 
   /// copied from here: http://stackoverflow.com/a/24655601/253938 and here:
   /// http://stackoverflow.com/a/7885923/253938
   /// (This should give good performance according to this: 
   ///  http://stackoverflow.com/a/12020300/253938 )
   ///
   /// Note that it is possible that multiple calls to this method and computing the difference may 
   /// occasionally give problematic results, like an apparently negative interval or a major jump 
   /// forward in time. This is because system time occasionally gets updated due to synchronization 
   /// with a time source on the network (maybe "leap second"), or user setting the clock.
   public static func currentTimeMillis() -> Int64 {
      var darwinTime : timeval = timeval(tv_sec: 0, tv_usec: 0)
      gettimeofday(&darwinTime, nil)
      return (Int64(darwinTime.tv_sec) * 1000) + Int64(darwinTime.tv_usec / 1000)
   }

斯威夫特2

let seconds = NSDate().timeIntervalSince1970
let milliseconds = seconds * 1000.0

斯威夫特3

let currentTimeInMiliseconds = Date().timeIntervalSince1970.milliseconds

到目前为止，我发现gettimeofday在iOS (iPad)上是一个很好的解决方案，当你想执行一些间隔评估(比如帧速率，渲染帧的计时……):

#include <sys/time.h>
struct timeval time;
gettimeofday(&time, NULL);
long millis = (time.tv_sec * 1000) + (time.tv_usec / 1000);

// Timestamp after converting to milliseconds.

NSString * timeInMS = [NSString stringWithFormat:@"%lld", [@(floor([date timeIntervalSince1970] * 1000)) longLongValue]];