我在iPhone 4S和iPad 3(发行版本)上测试了所有其他答案。CACurrentMediaTime的开销最小。timeIntervalSince1970比其他的要慢得多，可能是由于NSDate实例化开销，尽管对于许多用例来说可能无关紧要。

如果您希望开销最少，并且不介意添加Quartz Framework依赖项，我建议您使用CACurrentMediaTime。或者gettimeofday(如果可移植性对您来说是优先考虑的)。

iPhone 4 s

CACurrentMediaTime: 1.33 µs/call
gettimeofday: 1.38 µs/call
[NSDate timeIntervalSinceReferenceDate]: 1.45 µs/call
CFAbsoluteTimeGetCurrent: 1.48 µs/call
[[NSDate date] timeIntervalSince1970]: 4.93 µs/call

iPad 3

CACurrentMediaTime: 1.25 µs/call
gettimeofday: 1.33 µs/call
CFAbsoluteTimeGetCurrent: 1.34 µs/call
[NSDate timeIntervalSinceReferenceDate]: 1.37 µs/call
[[NSDate date] timeIntervalSince1970]: 3.47 µs/call

 func currentmicrotimeTimeMillis() -> Int64{
let nowDoublevaluseis = NSDate().timeIntervalSince1970
return Int64(nowDoublevaluseis*1000)

}

到目前为止，我发现gettimeofday在iOS (iPad)上是一个很好的解决方案，当你想执行一些间隔评估(比如帧速率，渲染帧的计时……):

#include <sys/time.h>
struct timeval time;
gettimeofday(&time, NULL);
long millis = (time.tv_sec * 1000) + (time.tv_usec / 1000);

我需要一个NSNumber对象，包含[[NSDate date] timeIntervalSince1970]的确切结果。因为这个函数被调用了很多次，我并不真的需要创建一个NSDate对象，性能不是很好。

所以要得到原始函数给我的格式，试试这个:

#include <sys/time.h>
struct timeval tv;
gettimeofday(&tv,NULL);
double perciseTimeStamp = tv.tv_sec + tv.tv_usec * 0.000001;

这应该给你完全相同的结果[[NSDate date] timeIntervalSince1970]

It may be useful to know about CodeTimestamps, which provide a wrapper around mach-based timing functions. This gives you nanosecond-resolution timing data - 1000000x more precise than milliseconds. Yes, a million times more precise. (The prefixes are milli, micro, nano, each 1000x more precise than the last.) Even if you don't need CodeTimestamps, check out the code (it's open source) to see how they use mach to get the timing data. This would be useful when you need more precision and want a faster method call than the NSDate approach.

http://eng.pulse.me/line-by-line-speed-analysis-for-ios-apps/

获取当前日期的毫秒数。

斯威夫特4 +:

func currentTimeInMilliSeconds()-> Int
    {
        let currentDate = Date()
        let since1970 = currentDate.timeIntervalSince1970
        return Int(since1970 * 1000)
    }