获得当前系统时间毫秒的最佳方法是什么?


当前回答

这基本上和@TristanLorach发布的答案是一样的,只是为Swift 3重新编码:

   /// Method to get Unix-style time (Java variant), i.e., time since 1970 in milliseconds. This 
   /// copied from here: http://stackoverflow.com/a/24655601/253938 and here:
   /// http://stackoverflow.com/a/7885923/253938
   /// (This should give good performance according to this: 
   ///  http://stackoverflow.com/a/12020300/253938 )
   ///
   /// Note that it is possible that multiple calls to this method and computing the difference may 
   /// occasionally give problematic results, like an apparently negative interval or a major jump 
   /// forward in time. This is because system time occasionally gets updated due to synchronization 
   /// with a time source on the network (maybe "leap second"), or user setting the clock.
   public static func currentTimeMillis() -> Int64 {
      var darwinTime : timeval = timeval(tv_sec: 0, tv_usec: 0)
      gettimeofday(&darwinTime, nil)
      return (Int64(darwinTime.tv_sec) * 1000) + Int64(darwinTime.tv_usec / 1000)
   }

其他回答

如果你不想包含Quartz框架,[NSDate timeintervalsincerely eferencedate]是另一个选项。它返回一个double,表示秒数。

NSTimeInterval time = ([[NSDate date] timeIntervalSince1970]); //double
long digits = (long)time; //first 10 digits        
int decimalDigits = (int)(fmod(time, 1) * 1000); //3 missing digits
/*** long ***/
long timestamp = (digits * 1000) + decimalDigits;
/*** string ***/
NSString *timestampString = [NSString stringWithFormat:@"%ld%03d",digits ,decimalDigits];
let timeInMiliSecDate = Date()
let timeInMiliSec = Int (timeInMiliSecDate.timeIntervalSince1970 * 1000)
print(timeInMiliSec)

如果你正在考虑使用这个相对定时(例如游戏或动画),我宁愿使用CACurrentMediaTime()

double CurrentTime = CACurrentMediaTime();

哪一种是推荐的方式;NSDate从网络的同步时钟中提取,并且在与网络重新同步时偶尔会打嗝。

它返回当前的绝对时间,以秒为单位。


如果你只想要小数部分(通常在同步动画时使用),

let ct = CACurrentMediaTime().truncatingRemainder(dividingBy: 1)
[[NSDate date] timeIntervalSince1970];

它以双精度返回自epoch以来的秒数。我几乎可以肯定你可以从小数部分访问毫秒。