获得当前系统时间毫秒的最佳方法是什么?
当前回答
这基本上和@TristanLorach发布的答案是一样的,只是为Swift 3重新编码:
/// Method to get Unix-style time (Java variant), i.e., time since 1970 in milliseconds. This
/// copied from here: http://stackoverflow.com/a/24655601/253938 and here:
/// http://stackoverflow.com/a/7885923/253938
/// (This should give good performance according to this:
/// http://stackoverflow.com/a/12020300/253938 )
///
/// Note that it is possible that multiple calls to this method and computing the difference may
/// occasionally give problematic results, like an apparently negative interval or a major jump
/// forward in time. This is because system time occasionally gets updated due to synchronization
/// with a time source on the network (maybe "leap second"), or user setting the clock.
public static func currentTimeMillis() -> Int64 {
var darwinTime : timeval = timeval(tv_sec: 0, tv_usec: 0)
gettimeofday(&darwinTime, nil)
return (Int64(darwinTime.tv_sec) * 1000) + Int64(darwinTime.tv_usec / 1000)
}
其他回答
到目前为止,我发现gettimeofday在iOS (iPad)上是一个很好的解决方案,当你想执行一些间隔评估(比如帧速率,渲染帧的计时……):
#include <sys/time.h>
struct timeval time;
gettimeofday(&time, NULL);
long millis = (time.tv_sec * 1000) + (time.tv_usec / 1000);
NSTimeInterval time = ([[NSDate date] timeIntervalSince1970]); //double
long digits = (long)time; //first 10 digits
int decimalDigits = (int)(fmod(time, 1) * 1000); //3 missing digits
/*** long ***/
long timestamp = (digits * 1000) + decimalDigits;
/*** string ***/
NSString *timestampString = [NSString stringWithFormat:@"%ld%03d",digits ,decimalDigits];
[[NSDate date] timeIntervalSince1970];
它以双精度返回自epoch以来的秒数。我几乎可以肯定你可以从小数部分访问毫秒。
这基本上和@TristanLorach发布的答案是一样的,只是为Swift 3重新编码:
/// Method to get Unix-style time (Java variant), i.e., time since 1970 in milliseconds. This
/// copied from here: http://stackoverflow.com/a/24655601/253938 and here:
/// http://stackoverflow.com/a/7885923/253938
/// (This should give good performance according to this:
/// http://stackoverflow.com/a/12020300/253938 )
///
/// Note that it is possible that multiple calls to this method and computing the difference may
/// occasionally give problematic results, like an apparently negative interval or a major jump
/// forward in time. This is because system time occasionally gets updated due to synchronization
/// with a time source on the network (maybe "leap second"), or user setting the clock.
public static func currentTimeMillis() -> Int64 {
var darwinTime : timeval = timeval(tv_sec: 0, tv_usec: 0)
gettimeofday(&darwinTime, nil)
return (Int64(darwinTime.tv_sec) * 1000) + Int64(darwinTime.tv_usec / 1000)
}
试试这个:
NSDate * timestamp = [NSDate dateWithTimeIntervalSince1970:[[NSDate date] timeIntervalSince1970]];
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:@"YYYY-MM-dd HH:mm:ss.SSS"];
NSString *newDateString = [dateFormatter stringFromDate:timestamp];
timestamp = (NSDate*)newDateString;
在本例中,dateWithTimeIntervalSince1970与格式化程序@"YYYY-MM-dd HH:mm:ss结合使用。它将返回带有年、月、日的日期和带有小时、分钟、秒和毫秒的时间。参见示例:"2015-12-02 04:43:15.008"。我使用NSString来确保格式之前已经写过。
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