我正在尝试从一个“活动”发送客户类的对象，并在另一个“”中显示它。
客户类别的代码：
public class Customer {
private String firstName, lastName, address;
int age;
public Customer(String fname, String lname, int age, String address) {
firstName = fname;
lastName = lname;
age = age;
address = address;
}
public String printValues() {
String data = null;
data = "First Name :" + firstName + " Last Name :" + lastName
+ " Age : " + age + " Address : " + address;
return data;
}
}
我想将其对象从一个“活动”发送到另一个“，然后在另一个活动”上显示数据。
我怎样才能做到这一点？
像这样创建自定义类：
public class Test implements Parcelable {
String message;
protected Test(Parcel in) {
message = in.readString();
}
public static final Creator<Test> CREATOR = new Creator<Test>() {
@Override
public Test createFromParcel(Parcel in) {
return new Test(in);
}
@Override
public Test[] newArray(int size) {
return new Test[size];
}
};
public String getMessage() {
return message;
}
@Override
public int describeContents() {
return 0;
}
@Override
public void writeToParcel(Parcel dest, int flags) {
dest.writeString(message);
}
使用Intent发送数据，如下所示：开始活动之前，必须设置一些数据
Intent intent = new Intent(context, PostDetailsActivity.class);
intent.putExtra("data", (Parcelable) test);
((context)).startActivity(intent);
从以下意图中获取数据：
Test test = (Test) getIntent().getParcelableExtra("data");
你可以尝试使用该类。限制是它不能在一个过程之外使用。
一项活动：
final Object obj1 = new Object();
final Intent in = new Intent();
in.putExtra(EXTRA_TEST, new Sharable(obj1));
其他活动：
final Sharable s = in.getExtras().getParcelable(EXTRA_TEST);
final Object obj2 = s.obj();
public final class Sharable implements Parcelable {
private Object mObject;
public static final Parcelable.Creator < Sharable > CREATOR = new Parcelable.Creator < Sharable > () {
public Sharable createFromParcel(Parcel in ) {
return new Sharable( in );
}
@Override
public Sharable[] newArray(int size) {
return new Sharable[size];
}
};
public Sharable(final Object obj) {
mObject = obj;
}
public Sharable(Parcel in ) {
readFromParcel( in );
}
Object obj() {
return mObject;
}
@Override
public int describeContents() {
return 0;
}
@Override
public void writeToParcel(final Parcel out, int flags) {
final long val = SystemClock.elapsedRealtime();
out.writeLong(val);
put(val, mObject);
}
private void readFromParcel(final Parcel in ) {
final long val = in .readLong();
mObject = get(val);
}
/////
private static final HashMap < Long, Object > sSharableMap = new HashMap < Long, Object > (3);
synchronized private static void put(long key, final Object obj) {
sSharableMap.put(key, obj);
}
synchronized private static Object get(long key) {
return sSharableMap.remove(key);
}
}
不可能序列化任何类型的对象。例如，不能序列化携带代码而不是数据的委托方法或接口。因此，我编写了一个“Box”类，您可以使用它来传递任何类型的数据，而无需序列化。
1-将数据用于预期用途：
Intent I = new Intent(this, YourActivity.class);
CustomClass Date = new CustomClass();
Box.Add(I, "Name", Data);
2-用于从意向检索数据：
CustomClass Data = Box.Get(getIntent(), "Name");
3-要在使用后删除数据，请将此方法添加到活动中：
@Override
protected void onDestroy() {
Box.Remove(getIntent());
super.onDestroy();
}
4-并将此代码添加到项目中：
package ir.namirasoft.Utility;
import android.content.Intent;
import java.util.HashMap;
import java.util.Vector;
public class Box {
// Number
private static int Number = 1;
public static int NextNumber() {
return Number++;
}
//
private static String _Intent_Identifier = "_Intent_Identifier";
private static HashMap<Integer, Vector<Integer>> DeleteList = new HashMap<Integer, Vector<Integer>>();
private static HashMap<Integer, HashMap<String, Object>> ObjectList = new HashMap<Integer, HashMap<String, Object>>();
public static int GetIntent_Identifier(Intent I) {
int Intent_Identifier = I.getIntExtra(_Intent_Identifier, 0);
if (Intent_Identifier == 0)
I.putExtra(_Intent_Identifier, Intent_Identifier = NextNumber());
return Intent_Identifier;
}
public static void Add(Intent I, String Name, Object O) {
int Intent_Identifier = GetIntent_Identifier(I);
synchronized (ObjectList) {
if (!ObjectList.containsKey(Intent_Identifier))
ObjectList.put(Intent_Identifier, new HashMap<String, Object>());
ObjectList.get(Intent_Identifier).put(Name, O);
}
}
public static <T> T Get(Intent I, String Name) {
int Intent_Identifier = GetIntent_Identifier(I);
synchronized (DeleteList) {
DeleteList.remove(Intent_Identifier);
}
return (T) ObjectList.get(Intent_Identifier).get(Name);
}
public static void Remove(final Intent I) {
final int Intent_Identifier = GetIntent_Identifier(I);
final int ThreadID = NextNumber();
synchronized (DeleteList) {
if (!DeleteList.containsKey(Intent_Identifier))
DeleteList.put(Intent_Identifier, new Vector<Integer>());
DeleteList.get(Intent_Identifier).add(ThreadID);
}
new Thread(new Runnable() {
@Override
public void run() {
try {
Thread.sleep(60 * 1000);
} catch (InterruptedException e) {
}
synchronized (DeleteList) {
if (DeleteList.containsKey(Intent_Identifier))
if (DeleteList.get(Intent_Identifier).contains(ThreadID))
synchronized (ObjectList) {
ObjectList.remove(Intent_Identifier);
}
}
}
}).start();
}
}
**Box类是线程安全的。
从此活动启动另一个活动，并通过捆绑对象传递参数
Intent intent = new Intent(getBaseContext(), YourActivity.class);
intent.putExtra("USER_NAME", "xyz@gmail.com");
startActivity(intent);
检索其他活动的数据（YourActivity）
String s = getIntent().getStringExtra("USER_NAME");
这对于一种简单的数据类型是可以的。但是如果你想在活动之间传递复杂的数据。你需要先序列化它。
这里有员工模型
class Employee{
private String empId;
private int age;
print Double salary;
getters...
setters...
}
您可以使用google提供的Gson-lib来序列化复杂的数据这样地
String strEmp = new Gson().toJson(emp);
Intent intent = new Intent(getBaseContext(), YourActivity.class);
intent.putExtra("EMP", strEmp);
startActivity(intent);
Bundle bundle = getIntent().getExtras();
String empStr = bundle.getString("EMP");
Gson gson = new Gson();
Type type = new TypeToken<Employee>() {
}.getType();
Employee selectedEmp = gson.fromJson(empStr, type);
