如何在Python中创建目录结构的zip存档?
当前回答
现代Python(3.6+)使用pathlib模块对路径进行类似OOP的简洁处理,使用pathlib.Path.rglob()进行递归globing。据我所知,这相当于乔治·V·莱利的回答:压缩压缩,最顶层的元素是目录,保持空目录,使用相对路径。
from pathlib import Path
from zipfile import ZIP_DEFLATED, ZipFile
from os import PathLike
from typing import Union
def zip_dir(zip_name: str, source_dir: Union[str, PathLike]):
src_path = Path(source_dir).expanduser().resolve(strict=True)
with ZipFile(zip_name, 'w', ZIP_DEFLATED) as zf:
for file in src_path.rglob('*'):
zf.write(file, file.relative_to(src_path.parent))
注意:如可选类型提示所示,zip_name不能是Path对象(将在3.6.2+中修复)。
其他回答
下面是Nux给出的答案的一个变体,对我有用:
def WriteDirectoryToZipFile( zipHandle, srcPath, zipLocalPath = "", zipOperation = zipfile.ZIP_DEFLATED ):
basePath = os.path.split( srcPath )[ 0 ]
for root, dirs, files in os.walk( srcPath ):
p = os.path.join( zipLocalPath, root [ ( len( basePath ) + 1 ) : ] )
# add dir
zipHandle.write( root, p, zipOperation )
# add files
for f in files:
filePath = os.path.join( root, f )
fileInZipPath = os.path.join( p, f )
zipHandle.write( filePath, fileInZipPath, zipOperation )
我对Mark Byers给出的代码做了一些修改。如果您有空目录,下面的函数也会添加它们。示例应该更清楚添加到zip的路径是什么。
#!/usr/bin/env python
import os
import zipfile
def addDirToZip(zipHandle, path, basePath=""):
"""
Adding directory given by \a path to opened zip file \a zipHandle
@param basePath path that will be removed from \a path when adding to archive
Examples:
# add whole "dir" to "test.zip" (when you open "test.zip" you will see only "dir")
zipHandle = zipfile.ZipFile('test.zip', 'w')
addDirToZip(zipHandle, 'dir')
zipHandle.close()
# add contents of "dir" to "test.zip" (when you open "test.zip" you will see only it's contents)
zipHandle = zipfile.ZipFile('test.zip', 'w')
addDirToZip(zipHandle, 'dir', 'dir')
zipHandle.close()
# add contents of "dir/subdir" to "test.zip" (when you open "test.zip" you will see only contents of "subdir")
zipHandle = zipfile.ZipFile('test.zip', 'w')
addDirToZip(zipHandle, 'dir/subdir', 'dir/subdir')
zipHandle.close()
# add whole "dir/subdir" to "test.zip" (when you open "test.zip" you will see only "subdir")
zipHandle = zipfile.ZipFile('test.zip', 'w')
addDirToZip(zipHandle, 'dir/subdir', 'dir')
zipHandle.close()
# add whole "dir/subdir" with full path to "test.zip" (when you open "test.zip" you will see only "dir" and inside it only "subdir")
zipHandle = zipfile.ZipFile('test.zip', 'w')
addDirToZip(zipHandle, 'dir/subdir')
zipHandle.close()
# add whole "dir" and "otherDir" (with full path) to "test.zip" (when you open "test.zip" you will see only "dir" and "otherDir")
zipHandle = zipfile.ZipFile('test.zip', 'w')
addDirToZip(zipHandle, 'dir')
addDirToZip(zipHandle, 'otherDir')
zipHandle.close()
"""
basePath = basePath.rstrip("\\/") + ""
basePath = basePath.rstrip("\\/")
for root, dirs, files in os.walk(path):
# add dir itself (needed for empty dirs
zipHandle.write(os.path.join(root, "."))
# add files
for file in files:
filePath = os.path.join(root, file)
inZipPath = filePath.replace(basePath, "", 1).lstrip("\\/")
#print filePath + " , " + inZipPath
zipHandle.write(filePath, inZipPath)
以上是一个简单的函数,适用于简单的情况。你可以在我的Gist中找到更优雅的课程:https://gist.github.com/Eccenux/17526123107ca0ac28e6
函数创建zip文件。
def CREATEZIPFILE(zipname, path):
#function to create a zip file
#Parameters: zipname - name of the zip file; path - name of folder/file to be put in zip file
zipf = zipfile.ZipFile(zipname, 'w', zipfile.ZIP_DEFLATED)
zipf.setpassword(b"password") #if you want to set password to zipfile
#checks if the path is file or directory
if os.path.isdir(path):
for files in os.listdir(path):
zipf.write(os.path.join(path, files), files)
elif os.path.isfile(path):
zipf.write(os.path.join(path), path)
zipf.close()
最简单的方法是使用shutil.make_archive。它支持zip和tar格式。
import shutil
shutil.make_archive(output_filename, 'zip', dir_name)
如果您需要做一些比压缩整个目录更复杂的事情(例如跳过某些文件),那么您需要像其他人建议的那样深入到zipfile模块。
要将mydirectory的内容添加到新的zip文件中,包括所有文件和子目录:
import os
import zipfile
zf = zipfile.ZipFile("myzipfile.zip", "w")
for dirname, subdirs, files in os.walk("mydirectory"):
zf.write(dirname)
for filename in files:
zf.write(os.path.join(dirname, filename))
zf.close()
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