componentDidMount(){
    //http://localhost:3000/service/anas
    //<Route path="/service/:serviceName" component={Service} />
    const {params} =this.props.match;
    this.setState({ 
        title: params.serviceName ,
        content: data.Content
    })
}

你可以使用下面的react钩子:

如果url改变，钩子状态会更新 SSR: typeof window === "undefined"，只是检查窗口导致错误(尝试一下) 代理对象隐藏实现，因此返回undefined而不是null

这是获取搜索参数为对象的函数:

const getSearchParams = <T extends object>(): Partial<T> => {
    // server side rendering
    if (typeof window === "undefined") {
        return {}
    }

    const params = new URLSearchParams(window.location.search) 

    return new Proxy(params, {
        get(target, prop, receiver) {
            return target.get(prop as string) || undefined
        },
    }) as T
}

然后像这样把它用作钩子:

const useSearchParams = <T extends object = any>(): Partial<T> => {
    const [searchParams, setSearchParams] = useState(getSearchParams())

    useEffect(() => {
        setSearchParams(getSearchParams())
    }, [typeof window === "undefined" ? "once" : window.location.search])

    return searchParams
}

如果你的url是这样的:

/app？page=2&count=10

你可以这样读:

const { page, count } = useQueryParams();

console.log(page, count)

在需要访问可以使用的参数的组件中

this.props.location.state.from.search

这将显示整个查询字符串(在?标志)

在typescript中，参见下面的示例片段:

const getQueryParams = (s?: string): Map<string, string> => {
  if (!s || typeof s !== 'string' || s.length < 2) {
    return new Map();
  }

  const a: [string, string][] = s
    .substr(1) // remove `?`
    .split('&') // split by `&`
    .map(x => {
      const a = x.split('=');
      return [a[0], a[1]];
    }); // split by `=`

  return new Map(a);
};

在react中使用react-router-dom，你可以做

const {useLocation} from 'react-router-dom';
const s = useLocation().search;
const m = getQueryParams(s);

参见下面的例子

//下面是上面转换和缩小的ts函数 如果(const getQueryParams = t = > {! t | |“字符串”!=typeof t||t.length<2)return new Map;const r=t.substr(1).split("&")。地图(t = > {const r = t.split(" = ");返回[r[0],[1]]});返回新地图(r)}; //一个示例查询字符串 Const s = '?__arg1 = value1&arg2 = value2 ' getQueryParams(s) console.log (m.get (__arg1)) console.log (m.get(最长)) Console.log (m.t get('arg3')) //不存在，返回undefined

不是反应的方式，但我相信这个单行函数可以帮助你:)

const getQueryParams = (query = null) => [...(new URLSearchParams(query||window.location.search||"")).entries()].reduce((a,[k,v])=>(a[k]=v,a),{});

或:

const getQueryParams = (query = null) => (query||window.location.search.replace('?','')).split('&').map(e=>e.split('=').map(decodeURIComponent)).reduce((r,[k,v])=>(r[k]=v,r),{});

或完整版:

const getQueryParams = (query = null) => {
  return (
    (query || window.location.search.replace("?", ""))

      // get array of KeyValue pairs
      .split("&") 

      // Decode values
      .map((pair) => {
        let [key, val] = pair.split("=");

        return [key, decodeURIComponent(val || "")];
      })

      // array to object
      .reduce((result, [key, val]) => {
        result[key] = val;
        return result;
      }, {})
  );
};

例子: URL:…?= = 1 b =建发集团有限公司的测试 代码:

getQueryParams()
//=> {a: "1", b: "c", d: "test"}

getQueryParams('type=user&name=Jack&age=22')
//=> {type: "user", name: "Jack", age: "22" }

最受欢迎的答案中的链接是死的，因为SO不让我评论，对于ReactRouter v6.3.0，你可以使用params钩子

import * as React from 'react';
import { Routes, Route, useParams } from 'react-router-dom';

function ProfilePage() {
  // Get the userId param from the URL.
  let { userId } = useParams();
  // ...
}

function App() {
  return (
    <Routes>
      <Route path="users">
        <Route path=":userId" element={<ProfilePage />} />
        <Route path="me" element={...} />
      </Route>
    </Routes>
  );
}