如何在我的路由中定义路由。jsx文件捕获__firebase_request_key参数值从一个URL生成的Twitter的单点登录过程后,从他们的服务器重定向?

http://localhost:8000/#/signin?_k=v9ifuf&__firebase_request_key=blablabla

我尝试了以下路由配置,但:redirectParam没有捕获提到的参数:

<Router>
  <Route path="/" component={Main}>
    <Route path="signin" component={SignIn}>
      <Route path=":redirectParam" component={TwitterSsoButton} />
    </Route>
  </Route>
</Router>

当前回答

在typescript中,参见下面的示例片段:

const getQueryParams = (s?: string): Map<string, string> => {
  if (!s || typeof s !== 'string' || s.length < 2) {
    return new Map();
  }

  const a: [string, string][] = s
    .substr(1) // remove `?`
    .split('&') // split by `&`
    .map(x => {
      const a = x.split('=');
      return [a[0], a[1]];
    }); // split by `=`

  return new Map(a);
};

在react中使用react-router-dom,你可以做

const {useLocation} from 'react-router-dom';
const s = useLocation().search;
const m = getQueryParams(s);

参见下面的例子

//下面是上面转换和缩小的ts函数 如果(const getQueryParams = t = > {! t | |“字符串”!=typeof t||t.length<2)return new Map;const r=t.substr(1).split("&")。地图(t = > {const r = t.split(" = ");返回[r[0],[1]]});返回新地图(r)}; //一个示例查询字符串 Const s = '?__arg1 = value1&arg2 = value2 ' getQueryParams(s) console.log (m.get (__arg1)) console.log (m.get(最长)) Console.log (m.t get('arg3')) //不存在,返回undefined

其他回答

或者像这样?

Let win = { “位置”:{ “路径”:“http://localhost: 8000 / # / signin吗?_k = v9ifuf&__firebase_request_key =之类的 } } If (win.location.path.match('__firebase_request_key').length) { 让key= win.location.path.split('__firebase_request_key=')[1] console.log(关键) }

如果你没有得到这个。道具…根据其他答案,您可能需要使用withthrouter (docs v4):

import React from 'react'
import PropTypes from 'prop-types'
import { withRouter } from 'react-router'

// A simple component that shows the pathname of the current location
class ShowTheLocation extends React.Component {
  static propTypes = {
    match: PropTypes.object.isRequired,
    location: PropTypes.object.isRequired,
    history: PropTypes.object.isRequired
  }

  render() {
    const { match, location, history } = this.props

    return (
      <div>You are now at {location.pathname}</div>
    )
  }
}

// Create a new component that is "connected" (to borrow redux terminology) to the router.  
const TwitterSsoButton = withRouter(ShowTheLocation)  

// This gets around shouldComponentUpdate
withRouter(connect(...)(MyComponent))

// This does not
connect(...)(withRouter(MyComponent))

如果你的路由器是这样的

<Route exact path="/category/:id" component={ProductList}/>

你会得到这样的id

this.props.match.params.id

最简单的解决方案!

在路由方面:

   <Route path="/app/someUrl/:id" exact component={binder} />

在react代码中:

componentDidMount() {
    var id = window.location.href.split('/')[window.location.href.split('/').length - 1];
    var queryString = "http://url/api/controller/" + id
    $.getJSON(queryString)
      .then(res => {
        this.setState({ data: res });
      });
  }

你可以使用下面的react钩子:

如果url改变,钩子状态会更新 SSR: typeof window === "undefined",只是检查窗口导致错误(尝试一下) 代理对象隐藏实现,因此返回undefined而不是null

这是获取搜索参数为对象的函数:

const getSearchParams = <T extends object>(): Partial<T> => {
    // server side rendering
    if (typeof window === "undefined") {
        return {}
    }

    const params = new URLSearchParams(window.location.search) 

    return new Proxy(params, {
        get(target, prop, receiver) {
            return target.get(prop as string) || undefined
        },
    }) as T
}

然后像这样把它用作钩子:

const useSearchParams = <T extends object = any>(): Partial<T> => {
    const [searchParams, setSearchParams] = useState(getSearchParams())

    useEffect(() => {
        setSearchParams(getSearchParams())
    }, [typeof window === "undefined" ? "once" : window.location.search])

    return searchParams
}

如果你的url是这样的:

/app?page=2&count=10

你可以这样读:

const { page, count } = useQueryParams();

console.log(page, count)