在typescript中，参见下面的示例片段:

const getQueryParams = (s?: string): Map<string, string> => {
  if (!s || typeof s !== 'string' || s.length < 2) {
    return new Map();
  }

  const a: [string, string][] = s
    .substr(1) // remove `?`
    .split('&') // split by `&`
    .map(x => {
      const a = x.split('=');
      return [a[0], a[1]];
    }); // split by `=`

  return new Map(a);
};

在react中使用react-router-dom，你可以做

const {useLocation} from 'react-router-dom';
const s = useLocation().search;
const m = getQueryParams(s);

参见下面的例子

//下面是上面转换和缩小的ts函数 如果(const getQueryParams = t = > {! t | |“字符串”!=typeof t||t.length<2)return new Map;const r=t.substr(1).split("&")。地图(t = > {const r = t.split(" = ");返回[r[0],[1]]});返回新地图(r)}; //一个示例查询字符串 Const s = '?__arg1 = value1&arg2 = value2 ' getQueryParams(s) console.log (m.get (__arg1)) console.log (m.get(最长)) Console.log (m.t get('arg3')) //不存在，返回undefined

假设有一个url如下所示

http://localhost:3000/callback?code=6c3c9b39-de2f-3bf4-a542-3e77a64d3341

如果我们想从该URL提取代码，下面的方法将工作。

const authResult = new URLSearchParams(window.location.search); 
const code = authResult.get('code')

你可以使用下面的react钩子:

如果url改变，钩子状态会更新 SSR: typeof window === "undefined"，只是检查窗口导致错误(尝试一下) 代理对象隐藏实现，因此返回undefined而不是null

这是获取搜索参数为对象的函数:

const getSearchParams = <T extends object>(): Partial<T> => {
    // server side rendering
    if (typeof window === "undefined") {
        return {}
    }

    const params = new URLSearchParams(window.location.search) 

    return new Proxy(params, {
        get(target, prop, receiver) {
            return target.get(prop as string) || undefined
        },
    }) as T
}

然后像这样把它用作钩子:

const useSearchParams = <T extends object = any>(): Partial<T> => {
    const [searchParams, setSearchParams] = useState(getSearchParams())

    useEffect(() => {
        setSearchParams(getSearchParams())
    }, [typeof window === "undefined" ? "once" : window.location.search])

    return searchParams
}

如果你的url是这样的:

/app？page=2&count=10

你可以这样读:

const { page, count } = useQueryParams();

console.log(page, count)

React路由器v3

使用React Router v3，你可以从this.props.location.search (?qs1=naisarg&qs2=parmar)获取查询字符串。例如，使用let params = queryString.parse(this.props.location.search)，将给出{qs1: 'naisarg'， qs2: 'parmar'}

React路由器v4

在React Router v4中，this.props.location.query不再存在。您需要使用this.props.location.search，并自己或使用现有的包(如query-string)解析查询参数。

例子

下面是一个使用React Router v4和query-string库的最小示例。

import { withRouter } from 'react-router-dom';
import queryString from 'query-string';
    
class ActivateAccount extends Component{
    someFunction(){
        let params = queryString.parse(this.props.location.search)
        ...
    }
    ...
}
export default withRouter(ActivateAccount);

理性的

React Router团队移除query属性的理由是:

There are a number of popular packages that do query string parsing/stringifying slightly differently, and each of these differences might be the "correct" way for some users and "incorrect" for others. If React Router picked the "right" one, it would only be right for some people. Then, it would need to add a way for other users to substitute in their preferred query parsing package. There is no internal use of the search string by React Router that requires it to parse the key-value pairs, so it doesn't have a need to pick which one of these should be "right". [...] The approach being taken for 4.0 is to strip out all the "batteries included" kind of features and get back to just basic routing. If you need query string parsing or async loading or Redux integration or something else very specific, then you can add that in with a library specifically for your use case. Less cruft is packed in that you don't need and you can customize things to your specific preferences and needs.

你可以在GitHub上找到完整的讨论。

如果你没有得到这个。道具…根据其他答案，您可能需要使用withthrouter (docs v4):

import React from 'react'
import PropTypes from 'prop-types'
import { withRouter } from 'react-router'

// A simple component that shows the pathname of the current location
class ShowTheLocation extends React.Component {
  static propTypes = {
    match: PropTypes.object.isRequired,
    location: PropTypes.object.isRequired,
    history: PropTypes.object.isRequired
  }

  render() {
    const { match, location, history } = this.props

    return (
      <div>You are now at {location.pathname}</div>
    )
  }
}

// Create a new component that is "connected" (to borrow redux terminology) to the router.  
const TwitterSsoButton = withRouter(ShowTheLocation)  

// This gets around shouldComponentUpdate
withRouter(connect(...)(MyComponent))

// This does not
connect(...)(withRouter(MyComponent))

在没有第三方库或复杂的解决方案的情况下，在一行中完成这一切。以下是如何

let myVariable = new URLSearchParams(history.location.search).get('business');

你唯一需要改变的是你自己的参数名称的单词“business”。

业务= url.com例子吗?你好

myVariable的结果将是hello