如何在我的路由中定义路由。jsx文件捕获__firebase_request_key参数值从一个URL生成的Twitter的单点登录过程后，从他们的服务器重定向?
http://localhost:8000/#/signin?_k=v9ifuf&__firebase_request_key=blablabla
我尝试了以下路由配置，但:redirectParam没有捕获提到的参数:
<Router>
<Route path="/" component={Main}>
<Route path="signin" component={SignIn}>
<Route path=":redirectParam" component={TwitterSsoButton} />
</Route>
</Route>
</Router>
当前回答
在typescript中，参见下面的示例片段:
const getQueryParams = (s?: string): Map<string, string> => {
if (!s || typeof s !== 'string' || s.length < 2) {
return new Map();
}
const a: [string, string][] = s
.substr(1) // remove `?`
.split('&') // split by `&`
.map(x => {
const a = x.split('=');
return [a[0], a[1]];
}); // split by `=`
return new Map(a);
};
在react中使用react-router-dom，你可以做
const {useLocation} from 'react-router-dom';
const s = useLocation().search;
const m = getQueryParams(s);
参见下面的例子
//下面是上面转换和缩小的ts函数 如果(const getQueryParams = t = > {! t | |“字符串”!=typeof t||t.length<2)return new Map;const r=t.substr(1).split("&")。地图(t = > {const r = t.split(" = ");返回[r[0],[1]]});返回新地图(r)}; //一个示例查询字符串 Const s = '?__arg1 = value1&arg2 = value2 ' getQueryParams(s) console.log (m.get (__arg1)) console.log (m.get(最长)) Console.log (m.t get('arg3')) //不存在，返回undefined
其他回答
React路由器Dom V6 https://reactrouter.com/docs/en/v6/hooks/use-search-params
import * as React from "react";
import { useSearchParams } from "react-router-dom";
function App() {
let [searchParams, setSearchParams] = useSearchParams();
function handleSubmit(event) {
event.preventDefault();
// The serialize function here would be responsible for
// creating an object of { key: value } pairs from the
// fields in the form that make up the query.
let params = serializeFormQuery(event.target);
setSearchParams(params);
}
return (
<div>
<form onSubmit={handleSubmit}>{/* ... */}</form>
</div>
);
}
直到React路由器Dom V5
function useQueryParams() {
const params = new URLSearchParams(
window ? window.location.search : {}
);
return new Proxy(params, {
get(target, prop) {
return target.get(prop)
},
});
}
React钩子很棒
如果你的url看起来像/users?页面= 2数= 10字段=姓名、电子邮件、电话
// app.domain.com/users?page=2&count=10&fields=name,email,phone
const { page, fields, count, ...unknown } = useQueryParams();
console.log({ page, fields, count })
console.log({ unknown })
如果您的查询参数包含hyphone("-")或空格(" ") 然后你不能像{page, fields, count，…未知的}
你需要做传统的作业，比如
// app.domain.com/users?utm-source=stackOverFlow
const params = useQueryParams();
console.log(params['utm-source']);
在React Router v4中，只有withRoute才是正确的方式
您可以通过withRouter高阶组件访问历史对象的属性和最近的匹配。withRouter将在包装组件呈现时将更新的匹配、位置和历史道具传递给它。
import React from 'react'
import PropTypes from 'prop-types'
import { withRouter } from 'react-router'
// A simple component that shows the pathname of the current location
class ShowTheLocation extends React.Component {
static propTypes = {
match: PropTypes.object.isRequired,
location: PropTypes.object.isRequired,
history: PropTypes.object.isRequired
}
render() {
const { match, location, history } = this.props
return (
<div>You are now at {location.pathname}</div>
)
}
}
// Create a new component that is "connected" (to borrow redux
// terminology) to the router.
const ShowTheLocationWithRouter = withRouter(ShowTheLocation)
https://reacttraining.com/react-router/web/api/withRouter
http://localhost:8000/#/signin?id=12345
import React from "react";
import { useLocation } from "react-router-dom";
const MyComponent = () => {
const search = useLocation().search;
const id=new URLSearchParams(search).get("id");
console.log(id);//12345
}
React路由器v4
const urlParams = new URLSearchParams(this.props.location.search)
const key = urlParams.get('__firebase_request_key')
请注意，它目前还处于试验阶段。
查看浏览器兼容性:https://developer.mozilla.org/en-US/docs/Web/API/URLSearchParams/URLSearchParams#Browser_compatibility
有了这一行代码，你可以在React Hook和React Class Component的任何地方使用它。
https://www.hunterisgod.com/?city=Leipzig
let city = (new URLSearchParams(window.location.search)).get("city")
