如何在我的路由中定义路由。jsx文件捕获__firebase_request_key参数值从一个URL生成的Twitter的单点登录过程后，从他们的服务器重定向?
http://localhost:8000/#/signin?_k=v9ifuf&__firebase_request_key=blablabla
我尝试了以下路由配置，但:redirectParam没有捕获提到的参数:
<Router>
<Route path="/" component={Main}>
<Route path="signin" component={SignIn}>
<Route path=":redirectParam" component={TwitterSsoButton} />
</Route>
</Route>
</Router>
当前回答
你可以使用下面的react钩子:
如果url改变，钩子状态会更新 SSR: typeof window === "undefined"，只是检查窗口导致错误(尝试一下) 代理对象隐藏实现，因此返回undefined而不是null
这是获取搜索参数为对象的函数:
const getSearchParams = <T extends object>(): Partial<T> => {
// server side rendering
if (typeof window === "undefined") {
return {}
}
const params = new URLSearchParams(window.location.search)
return new Proxy(params, {
get(target, prop, receiver) {
return target.get(prop as string) || undefined
},
}) as T
}
然后像这样把它用作钩子:
const useSearchParams = <T extends object = any>(): Partial<T> => {
const [searchParams, setSearchParams] = useState(getSearchParams())
useEffect(() => {
setSearchParams(getSearchParams())
}, [typeof window === "undefined" ? "once" : window.location.search])
return searchParams
}
如果你的url是这样的:
/app？page=2&count=10
你可以这样读:
const { page, count } = useQueryParams();
console.log(page, count)
其他回答
试试这个
http://localhost:4000/#/amoos?id=101
// ReactJS
import React from "react";
import { useLocation } from "react-router-dom";
const MyComponent = () => {
const search = useLocation().search;
const id = new URLSearchParams(search).get("id");
console.log(id); //101
}
// VanillaJS
const id = window.location.search.split("=")[1];
console.log(id); //101
React Router v4不再有props.location.query对象(见github讨论)。因此，已接受的答案将不适用于较新的项目。
v4的解决方案是使用外部库查询字符串来解析props.location.search
const qs = require('query-string');
//or
import * as qs from 'query-string';
console.log(location.search);
//=> '?foo=bar'
const parsed = qs.parse(location.search);
console.log(parsed);
//=> {foo: 'bar'}
最简单的解决方案!
在路由方面:
<Route path="/app/someUrl/:id" exact component={binder} />
在react代码中:
componentDidMount() {
var id = window.location.href.split('/')[window.location.href.split('/').length - 1];
var queryString = "http://url/api/controller/" + id
$.getJSON(queryString)
.then(res => {
this.setState({ data: res });
});
}
export class ClassName extends Component{
constructor(props){
super(props);
this.state = {
id:parseInt(props.match.params.id,10)
}
}
render(){
return(
//Code
{this.state.id}
);
}
React路由器Dom V6 https://reactrouter.com/docs/en/v6/hooks/use-search-params
import * as React from "react";
import { useSearchParams } from "react-router-dom";
function App() {
let [searchParams, setSearchParams] = useSearchParams();
function handleSubmit(event) {
event.preventDefault();
// The serialize function here would be responsible for
// creating an object of { key: value } pairs from the
// fields in the form that make up the query.
let params = serializeFormQuery(event.target);
setSearchParams(params);
}
return (
<div>
<form onSubmit={handleSubmit}>{/* ... */}</form>
</div>
);
}
直到React路由器Dom V5
function useQueryParams() {
const params = new URLSearchParams(
window ? window.location.search : {}
);
return new Proxy(params, {
get(target, prop) {
return target.get(prop)
},
});
}
React钩子很棒
如果你的url看起来像/users?页面= 2数= 10字段=姓名、电子邮件、电话
// app.domain.com/users?page=2&count=10&fields=name,email,phone
const { page, fields, count, ...unknown } = useQueryParams();
console.log({ page, fields, count })
console.log({ unknown })
如果您的查询参数包含hyphone("-")或空格(" ") 然后你不能像{page, fields, count，…未知的}
你需要做传统的作业，比如
// app.domain.com/users?utm-source=stackOverFlow
const params = useQueryParams();
console.log(params['utm-source']);
