似乎应该有一种比以下更简单的方法:

import string
s = "string. With. Punctuation?" # Sample string 
out = s.translate(string.maketrans("",""), string.punctuation)

有?


当前回答

这可能不是最好的解决方案,但我就是这样做的。

import string
f = lambda x: ''.join([i for i in x if i not in string.punctuation])

其他回答

这个问题没有太多细节,所以我采取的方法是用最简单的解释来解决这个问题:去掉标点符号。

请注意,所提供的解决方案不考虑收缩词(例如,you are)或连字符词(例如肛门保留)。。。这是关于它们是否应该被视为标点符号的争论。。。也不能解释非英语字符集或类似的东西。。。因为问题中没有提到这些细节。有人认为空格是标点符号,这在技术上是正确的。。。但对我来说,这在当前问题的背景下毫无意义。

# using lambda
''.join(filter(lambda c: c not in string.punctuation, s))

# using list comprehension
''.join('' if c in string.punctuation else c for c in s)

不一定更简单,但如果你更熟悉re家族的话,就另辟蹊径。

import re, string
s = "string. With. Punctuation?" # Sample string 
out = re.sub('[%s]' % re.escape(string.punctuation), '', s)

我通常用这样的词:

>>> s = "string. With. Punctuation?" # Sample string
>>> import string
>>> for c in string.punctuation:
...     s= s.replace(c,"")
...
>>> s
'string With Punctuation'

这可能不是最好的解决方案,但我就是这样做的。

import string
f = lambda x: ''.join([i for i in x if i not in string.punctuation])

使用Python从文本文件中删除停止词

print('====THIS IS HOW TO REMOVE STOP WORS====')

with open('one.txt','r')as myFile:

    str1=myFile.read()

    stop_words ="not", "is", "it", "By","between","This","By","A","when","And","up","Then","was","by","It","If","can","an","he","This","or","And","a","i","it","am","at","on","in","of","to","is","so","too","my","the","and","but","are","very","here","even","from","them","then","than","this","that","though","be","But","these"

    myList=[]

    myList.extend(str1.split(" "))

    for i in myList:

        if i not in stop_words:

            print ("____________")

            print(i,end='\n')