似乎应该有一种比以下更简单的方法:

import string
s = "string. With. Punctuation?" # Sample string 
out = s.translate(string.maketrans("",""), string.punctuation)

有?


当前回答

在不太严格的情况下,单行线可能会有所帮助:

''.join([c for c in s if c.isalnum() or c.isspace()])

其他回答

这是我写的一个函数。它不是很有效,但很简单,您可以添加或删除任何您想要的标点符号:

def stripPunc(wordList):
    """Strips punctuation from list of words"""
    puncList = [".",";",":","!","?","/","\\",",","#","@","$","&",")","(","\""]
    for punc in puncList:
        for word in wordList:
            wordList=[word.replace(punc,'') for word in wordList]
    return wordList

我喜欢使用这样的函数:

def scrub(abc):
    while abc[-1] is in list(string.punctuation):
        abc=abc[:-1]
    while abc[0] is in list(string.punctuation):
        abc=abc[1:]
    return abc

这可能不是最好的解决方案,但我就是这样做的。

import string
f = lambda x: ''.join([i for i in x if i not in string.punctuation])

对于严肃的自然语言处理(NLP),您应该让像SpaCy这样的库通过标记化处理标点符号,然后您可以根据需要手动调整。

例如,您希望如何处理单词中的连字符?例外情况,如缩写?开始和结束引号?URL?在NLP中,将“let’s”这样的收缩分隔为“let”和“s”以进行进一步处理通常很有用。

使用Python从文本文件中删除停止词

print('====THIS IS HOW TO REMOVE STOP WORS====')

with open('one.txt','r')as myFile:

    str1=myFile.read()

    stop_words ="not", "is", "it", "By","between","This","By","A","when","And","up","Then","was","by","It","If","can","an","he","This","or","And","a","i","it","am","at","on","in","of","to","is","so","too","my","the","and","but","are","very","here","even","from","them","then","than","this","that","though","be","But","these"

    myList=[]

    myList.extend(str1.split(" "))

    for i in myList:

        if i not in stop_words:

            print ("____________")

            print(i,end='\n')