private void showImage(ImageView img, String absolutePath) {
  
    BitmapFactory.Options options = new BitmapFactory.Options();
    options.inSampleSize = 8;
    Bitmap bitmapPicture = BitmapFactory.decodeFile(absolutePath);
    img.setImageBitmap(bitmapPicture);

}

大多数答案都是有效的，但没有人提到高分辨率的图像会降低应用程序的速度，在我的情况下，我使用了imagesrecyclerview，它在30张图像中占用了0.9 GB的设备内存。

我/编舞:跳过73帧!应用程序可能也在这样做 它的主线有很多工作要做。

解决方法很简单，你可以像这样降低质量:降低位图的分辨率

但我用简单的方式，Glide处理剩下的工作

fanContext?.let {
            Glide.with(it)
                .load(Uri.fromFile(File(item.filePath)))
                .into(viewHolder.imagePreview)
        }

       public static Bitmap decodeFile(String path) {
    Bitmap b = null;
    File f = new File(path);
    // Decode image size
    BitmapFactory.Options o = new BitmapFactory.Options();
    o.inJustDecodeBounds = true;

    FileInputStream fis = null;
    try {
        fis = new FileInputStream(f);
        BitmapFactory.decodeStream(fis, null, o);
        fis.close();

        int IMAGE_MAX_SIZE = 1024; // maximum dimension limit
        int scale = 1;
        if (o.outHeight > IMAGE_MAX_SIZE || o.outWidth > IMAGE_MAX_SIZE) {
            scale = (int) Math.pow(2, (int) Math.round(Math.log(IMAGE_MAX_SIZE / (double) Math.max(o.outHeight, o.outWidth)) / Math.log(0.5)));
        }

        // Decode with inSampleSize
        BitmapFactory.Options o2 = new BitmapFactory.Options();
        o2.inSampleSize = scale;

        fis = new FileInputStream(f);
        b = BitmapFactory.decodeStream(fis, null, o2);
        fis.close();

    } catch (Exception e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

    return b;
}

public static Bitmap showBitmapFromFile(String file_path)
{
    try {
        File imgFile = new  File(file_path);
        if(imgFile.exists()){

            Bitmap pic_Bitmap = decodeFile(file_path);
            return pic_Bitmap;

        }
    } catch (Exception e) {
        MyLog.e("Exception showBitmapFromFile");
        return null;
    }
    return null;
}   

如果你在列表视图中使用图像加载，那么使用Aquery概念。

https://github.com/AshishPsaini/AqueryExample

     AQuery  aq= new AQuery((Activity) activity, convertView);
            //load image from file, down sample to target width of 250 pixels .gi 
    File file=new File("//pic/path/here/aaaa.jpg");
    if(aq!=null)
    aq.id(holder.pic_imageview).image(file, 250);

您可以使用它来访问特定的文件夹并获得特定的图像

 public void Retrieve(String path, String Name)
   {
    File imageFile = new File(path+Name);

    if(imageFile.exists()){

        Bitmap myBitmap = BitmapFactory.decodeFile(path+Name);
        myImage = (ImageView) findViewById(R.id.savedImage);
        myImage.setImageBitmap(myBitmap);
        Toast.makeText(SaveImage.this, myBitmap.toString(), Toast.LENGTH_LONG).show();

    }
}

然后你就可以过来了

Retrieve(Environment.getExternalStorageDirectory().toString()+"/Aqeel/Images/","Image2.PNG");
Toast.makeText(SaveImage.this, "Saved", Toast.LENGTH_LONG).show();

String path = Environment.getExternalStorageDirectory()+ "/Images/test.jpg";

File imgFile = new File(path);
if(imgFile.exists())
{
   Bitmap myBitmap = BitmapFactory.decodeFile(imgFile.getAbsolutePath());
   ImageView imageView=(ImageView)findViewById(R.id.imageView);
  imageView.setImageBitmap(myBitmap);
}

你还可以使用:

    File imgFile = new  File(“filepath”);
    if(imgFile.exists())
    {
        ImageView myImage = new ImageView(this);
        myImage.setImageURI(Uri.fromFile(imgFile));

    }

这为您隐式地完成位图解码。